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  • private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoin

    private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI * 0.5f else return Math.PI * 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {

    标签: AOrigin APoint Point PointToAngle

    上传时间: 2016-10-31

    上传用户:sunjet

  • private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoin

    private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI * 0.5f else return Math.PI * 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {

    标签: AOrigin APoint Point PointToAngle

    上传时间: 2013-12-18

    上传用户:rocketrevenge

  • 这是一个拼图游戏。玩家应该将打散的小图拼成一张大图。 玩家可以通过鼠标和键盘来移动小图

    这是一个拼图游戏。玩家应该将打散的小图拼成一张大图。 玩家可以通过鼠标和键盘来移动小图,移动的次数和拼成 一张大图所化费的时间作为游戏得分的依据。 成绩=1000-时间(秒)-移动步数*10 按F1键重新开始该游戏,按Y健可以预览整个的图片

    标签: 鼠标 键盘 移动

    上传时间: 2016-11-01

    上传用户:Yukiseop

  • a Java program that reads in the following values from the standard input device (i.e. Keyboard) an

    a Java program that reads in the following values from the standard input device (i.e. Keyboard) and writes its result on the standard output device (i.e. Console/Monitor): Inputs: A: the loan amount in dollars and cents (e.g. 150000.00). r: the net annual interest rate, expressed as an integer (e.g. 10 which means 10%) Y: the number of whole remaining years (for repayment) M: the number of remaining months Output: The program should calculate and output the amount of monthly repayments in dollars and cents as single value (e.g. $840.55)

    标签: i.e. following the Keyboard

    上传时间: 2013-12-15

    上传用户:米卡

  • 本文采用蒙特卡洛方法

    本文采用蒙特卡洛方法,将方程y=sin(x)+x与方程y=cos(x)+x之间的曲线包络面积求解出来。

    标签: 蒙特卡洛

    上传时间: 2016-11-04

    上传用户:gtzj

  • 用蒙特卡洛方法

    用蒙特卡洛方法,求解出y=cos(x)/x在给定区间上的定积分值。

    标签: 蒙特卡洛

    上传时间: 2014-01-22

    上传用户:1966640071

  • 输入某年某月某日

    输入某年某月某日,判断是不是闰年? 输入三个整数x,y,z,请把这三个数由小到大输出。

    标签: 输入

    上传时间: 2013-12-17

    上传用户:aix008

  • 显示螺旋队列

    显示螺旋队列,//螺旋队列.cpp // 21 22 ... ... // 20 7 8 9 10 // 19 6 1 2 11 // 18 5 4 3 12 // 17 16 15 14 13 //看清以上数字排列的规律,设1点的坐标是(0,0),X方向向右为正,y方向向下为正。例如,7的坐标为 //(-1,-1),2的坐标为(0,1),3的坐标为(1,1)。编程实现输入任意一点坐标(x,y),输出所对应得

    标签: 螺旋 队列

    上传时间: 2013-12-18

    上传用户:许小华

  • 用RBF神经网络

    用RBF神经网络,完成对y=f(x)的曲线拟合。

    标签: RBF 神经网络

    上传时间: 2013-12-06

    上传用户:mikesering

  • PRINCIPLE: The UVE algorithm detects and eliminates from a PLS model (including from 1 to A componen

    PRINCIPLE: The UVE algorithm detects and eliminates from a PLS model (including from 1 to A components) those variables that do not carry any relevant information to model Y. The criterion used to trace the un-informative variables is the reliability of the regression coefficients: c_j=mean(b_j)/std(b_j), obtained by jackknifing. The cutoff level, below which c_j is considered to be too small, indicating that the variable j should be removed, is estimated using a matrix of random variables.The predictive power of PLS models built on the retained variables only is evaluated over all 1-a dimensions =(yielding RMSECVnew).

    标签: from eliminates PRINCIPLE algorithm

    上传时间: 2016-11-27

    上传用户:凌云御清风