This project attempts to implement a Database using B+Tree. The project has developed a DATABASE SYSTEM with lesser memory consumption. Its API includes simple SQL Statements and the output is displayed on the screen. Certain applications for which several features of existing databases like concurrency control, transaction management, security features are not enabled. B+Trees can be used as an index for factor access to the data. Help facility is provided to know the syntax of SQL Statements.
标签： project implement developed Database
上传时间： 2013-12-25
上传用户：semi1981
考察例1 4 - 8中的1 4个点。A中的最近点对为(b,h)，其距离约为0 . 3 1 6。B中最近点对为 (f, j)，其距离为0 . 3，因此= 0 . 3。当考察 是否存在第三类点时，除d, g, i, l, m 以外 的点均被淘汰，因为它们距分割线x= 1的 距离≥ 。RA ={d, i, m}，RB= {g, l}，由 于d 和m 的比较区中没有点，只需考察i 即可。i 的比较区中仅含点l。计算i 和l 的距离，发现它小于，因此(i, l) 是最近
标签：
上传时间： 2013-12-03
上传用户：66666
Verilog HDL: Magnitude For a vector (a,b), the magnitude representation is the following: A common approach to implementing these arithmetic functions is to use the Coordinate Rotation Digital Computer (CORDIC) algorithm. The CORDIC algorithm calculates the trigonometric functions of sine, cosine, magnitude, and phase using an iterative process. It is made up of a series of micro-rotations of the vector by a set of predetermined constants, which are powers of two. Using binary arithmetic, this algorithm essentially replaces multipliers with shift and add operations. In a Stratix™ device, it is possible to calculate some of these arithmetic functions directly, without having to implement the CORDIC algorithm.
标签： representation Magnitude the magnitude
上传时间： 2013-12-24
上传用户：金宜
About: hamsterdb is a database engine written in ANSI C. It supports a B+Tree index structure, uses memory mapped I/O (if available), supports cursors, and can create in-memory databases. Release focus: Major feature enhancements Changes: This release comes with many changes and new features. It can manage multiple databases in one file. A new flag (HAM_LOCK_EXCLUSIVE) places an exclusive lock on the file. hamsterdb was ported to Windows CE, and the Solution file for Visual Studio 2005 now supports builds for x64. Several minor bugs were fixed, performance was improved, and small API changes occurred. Pre-built libraries for Windows (32-bit and 64-bit) are available for download. Author: cruppstahl
标签： C. hamsterdb structure database
上传时间： 2013-12-11
上传用户：LouieWu
n皇后问题求解(8<=n<=1000) a) 皇后个数的设定 在指定文本框内输入皇后个数即可,注意: 皇后个数在8和1000 之间(包括8和1000) b) 求解 点击<Solve>按钮即可进行求解. c) 求解过程显示 在标有Total Collision的静态文本框中将输出当前棋盘上的皇后总冲突数. 当冲突数降到0时,求解完毕. d) 求解结果显示 程序可以图形化显示8<=n<=50的皇后求解结果. e) 退出程序,点击<Exit>即可退出程序.
上传时间： 2016-01-28
上传用户：ztj182002
Floyd-Warshall算法描述 1)适用范围： a)APSP(All Pairs Shortest Paths) b)稠密图效果最佳 c)边权可正可负 2)算法描述： a)初始化：dis[u,v]=w[u,v] b)For k:=1 to n For i:=1 to n For j:=1 to n If dis[i,j]>dis[i,k]+dis[k,j] Then Dis[I,j]:=dis[I,k]+dis[k,j] c)算法结束：dis即为所有点对的最短路径矩阵 3)算法小结：此算法简单有效，由于三重循环结构紧凑，对于稠密图，效率要高于执行|V|次Dijkstra算法。时间复杂度O(n^3)。 考虑下列变形：如(I,j)∈E则dis[I,j]初始为1,else初始为0，这样的Floyd算法最后的最短路径矩阵即成为一个判断I,j是否有通路的矩阵。更简单的，我们可以把dis设成boolean类型，则每次可以用“dis[I,j]:=dis[I,j]or(dis[I,k]and dis[k,j])”来代替算法描述中的蓝色部分，可以更直观地得到I,j的连通情况。
标签： Floyd-Warshall Shortest Pairs Paths
上传时间： 2013-12-01
上传用户：dyctj
1． Matrix-chain product. The following are some instances a) <3, 5, 2, 1,10> b) <2, 7, 3, 6, 10> c) <10, 3, 15, 12, 7, 2> d) <7, 2, 4, 15, 20, 5>
标签： Matrix-chain following instances product
上传时间： 2014-11-28
上传用户：731140412
费诺编码的步骤: A 将概率按从大到小的顺序排列 B 按编码进制数将概率分组，使每组概率和尽可能接近或相等。 C 给每组分配一位码元 D 将每一分组再按同样原则划分，重复b和c，直到概率不再可分为止
上传时间： 2016-06-24
上传用户：xinyuzhiqiwuwu
这是一个三次样条插值的.m程序 输入的是一个二维数组A(Nx2) 插值方法为: S(x) = A(J) + B(J)*( x - x(J) ) + C(J)*( x - x(J) )**2 +D(J) * ( x - x(J) )**3 for x(J) <= x < x(J + 1)
上传时间： 2013-12-14
上传用户：gengxiaochao
Problem B:Longest Ordered Subsequence A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence (a1, a2, ..., aN) be any sequence (ai1, ai2, ..., aiK), where 1 <= i1 < i2 < ... < iK <= N. For example, sequence (1, 7, 3, 5, 9, 4, 8) has ordered subsequences, e. g., (1, 7), (3, 4, 8) and many others. All longest ordered subsequences are of length 4, e. g., (1, 3, 5, 8).
标签： Subsequence sequence Problem Longest
上传时间： 2016-12-08
上传用户：busterman
