Floyd-Warshall算法描述 1)适用范围： a)APSP(All Pairs Shortest Paths) b)稠密图效果最佳 c)边权可正可负 2)算法描述： a)初始化：dis[u,v]=w[u,v] b)For k:=1 to n For i:=1 to n For j:=1 to n If dis[i,j]>dis[i,k]+dis[k,j] Then Dis[I,j]:=dis[I,k]+dis[k,j] c)算法结束：dis即为所有点对的最短路径矩阵 3)算法小结：此算法简单有效，由于三重循环结构紧凑，对于稠密图，效率要高于执行|V|次Dijkstra算法。时间复杂度O(n^3)。 考虑下列变形：如(I,j)∈E则dis[I,j]初始为1,else初始为0，这样的Floyd算法最后的最短路径矩阵即成为一个判断I,j是否有通路的矩阵。更简单的，我们可以把dis设成boolean类型，则每次可以用“dis[I,j]:=dis[I,j]or(dis[I,k]and dis[k,j])”来代替算法描述中的蓝色部分，可以更直观地得到I,j的连通情况。
标签： Floyd-Warshall Shortest Pairs Paths
上传时间： 2013-12-01
上传用户：dyctj
Program main BIOS image | | /B - Program Boot Block | | /N - Program NVRAM | | /C - Destroy CMOS checksum | | /E - Program Embedded Controller Block | | /K - Program all non-critical blocks | | /Kn - Program n th non-critical block only(n=0-7) | | /Q - Silent execution | | /REBOOT - Reboot after programming | | /X - Don t Check ROM ID | | /S - Display current system s ROMID | | /Ln - Load CMOS defaults
标签： Program Destroy Block NVRAM
上传时间： 2016-07-26
上传用户：wfl_yy
这是一个三次样条插值的.m程序 输入的是一个二维数组A(Nx2) 插值方法为: S(x) = A(J) + B(J)*( x - x(J) ) + C(J)*( x - x(J) )**2 +D(J) * ( x - x(J) )**3 for x(J) <= x < x(J + 1)
上传时间： 2013-12-14
上传用户：gengxiaochao
采用3D Bresenham算法在两点间划一直线 ％ This program is ported to MATLAB from: ％ B.Pendleton. line3d - 3D Bresenham s (a 3D line drawing algorithm) ％ ftp://ftp.isc.org/pub/usenet/comp.sources.unix/volume26/line3d, 1992 ％ ％ Which is referenced by: ％ Fischer, J., A. del Rio (2004). A Fast Method for Applying Rigid ％ Transformations to Volume Data, WSCG2004 Conference. ％ http://wscg.zcu.cz/wscg2004/Papers_2004_Short/M19.pdf
标签： Bresenham Pendleton program MATLAB
上传时间： 2013-12-10
上传用户：sz_hjbf
Atheros Communications AR6001 WLAN Driver for SDIO installation Read Me March 26,2007 (based on k14 fw1.1) Windows CE Embedded CE 6.0 driver installation. 1. Unzip the installation file onto your system (called installation directory below) 2. Create an OS design or open an existing OS design in Platform Builder 6.0. a. The OS must support the SD bus driver and have an SD Host Controller driver (add these from Catalog Items). b. Run image size should be set to allow greater than 32MB. 3. a. From the Project menu select Add Existing Subproject... b. select AR6K_DRV.pbxml c. select open This should create a subproject within your OS Design project for the AR6K_DRV driver. 4. Build the solution.
标签： Communications installation Atheros Driver
上传时间： 2016-10-27
上传用户：hebmuljb
溫度華氏轉變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void) { int a=73,b=85,c=66 { if (a>=90) printf("a=A等級!!\n") else if (a>=80) printf("73分=B等級!!\n") else if (a>=70) printf("73分=C等級!!\n") else if (a>=60) printf("73分=D等級!!\n") else if (a<60) printf("73分=E等級!!\n") } { if (b>=90) printf("b=A等級!!\n") else if (b>=80) printf("85分=B等級!!\n") else if (b>=70) printf("85分=C等級!!\n") else if (b>=60) printf("85分=D等級!!\n") else if (b<60) printf("85分=E等級!!\n") } { if (c>=90) printf("c=A等級!!\n") else if (c>=80) printf("66分=B等級!!\n") else if (c>=70) printf("66分=C等級!!\n") else if (c>=60) printf("66分=D等級!!\n") else if (c<60) printf("66分=E等級!!\n") } system("pause") return 0 }
上传时间： 2014-11-10
上传用户：wpwpwlxwlx
溫度華氏轉變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void) { int a=73,b=85,c=66 { if (a>=90) printf("a=A等級!!\n") else if (a>=80) printf("73分=B等級!!\n") else if (a>=70) printf("73分=C等級!!\n") else if (a>=60) printf("73分=D等級!!\n") else if (a<60) printf("73分=E等級!!\n") } { if (b>=90) printf("b=A等級!!\n") else if (b>=80) printf("85分=B等級!!\n") else if (b>=70) printf("85分=C等級!!\n") else if (b>=60) printf("85分=D等級!!\n") else if (b<60) printf("85分=E等級!!\n") } { if (c>=90) printf("c=A等級!!\n") else if (c>=80) printf("66分=B等級!!\n") else if (c>=70) printf("66分=C等級!!\n") else if (c>=60) printf("66分=D等級!!\n") else if (c<60) printf("66分=E等級!!\n") } system("pause") return 0 }
上传时间： 2013-12-12
上传用户：亚亚娟娟123
Problem B:Longest Ordered Subsequence A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence (a1, a2, ..., aN) be any sequence (ai1, ai2, ..., aiK), where 1 <= i1 < i2 < ... < iK <= N. For example, sequence (1, 7, 3, 5, 9, 4, 8) has ordered subsequences, e. g., (1, 7), (3, 4, 8) and many others. All longest ordered subsequences are of length 4, e. g., (1, 3, 5, 8).
标签： Subsequence sequence Problem Longest
上传时间： 2016-12-08
上传用户：busterman
AR6001 WLAN Driver for SDIO installation Read Me March 26,2007 (based on k14 fw1.1) Windows CE Embedded CE 6.0 driver installation. 1. Unzip the installation file onto your system (called installation directory below) 2. Create an OS design or open an existing OS design in Platform Builder 6.0. a. The OS must support the SD bus driver and have an SD Host Controller driver (add these from Catalog Items). b. Run image size should be set to allow greater than 32MB. 3. a. From the Project menu select Add Existing Subproject... b. select AR6K_DRV.pbxml c. select open This should create a subproject within your OS Design project for the AR6K_DRV driver. 4. Build the solution.
标签： installation Windows Driver March
上传时间： 2014-09-06
上传用户：yuzsu
basic.c */ /**//* Project:NeuroBasic, basic package*//**/ /* Survey:This is a simple Basic b-code compiler which*/ /*can be used as a comfortable command shell for */ /* any program. The actual compiler is found in */ /*compiler.c.*/ /*The functions m_fctptr() and user_server()*/ /*build an interface to an
标签： basic NeuroBasic Project package
上传时间： 2017-02-15
上传用户：xymbian
