代入法的启发示搜索 我的代码实现是：按照自然语言各字母出现频率的大小从高到低（已经有人作国统计分析了）先生成一张字母出现频率统计表（A）--------(e),(t,a,o,i,n,s,h,r),(d,l),(c,u,m,w,f,g,y,p,b),(v,k,j,x,q,z) ，再对密文字母计算频率，并按频率从高到低生成一张输入密文字母的统计表（B），通过两张表的对应关系，不断用A中的字母去替换B中的字母，搜索不成功时就回退，在这里回朔是一个关键。
上传时间： 2015-10-24
上传用户：wanqunsheng
黑白点的匹配贪心算法 设平面上分布着n个白点和n个黑点，每个点用一对坐标（x, y）表示。一个黑点b=（xb,yb）支配一个白点w=(xw, yw)当且仅当xb>=xw和yb>=yw。若黑点b支配白点w，则黑点b和白点w可匹配（可形成一个匹配对）。在一个黑点最多只能与一个白点匹配，一个白点最多只能与一个黑点匹配的前提下，求n个白点和n个黑点的最大匹配对数。
上传时间： 2015-10-25
上传用户：zhliu007
TLV1544与TMS320VC5402通过串行口连接，此时，A／D转换芯片作为从设备，DSP提供帧同步和输入／输出时钟信号。TLV1544与DSP之间数据交换的时序图如图3所示。 开始时， 为高电平（芯片处于非激活状态），DATA IN和I/OCLK无效，DATAOUT处于高阻状态。当串行接口使CS变低（激活），芯片开始工作，I／OCLK和DATAIN能使DATA OUT不再处于高阻状态。DSP通过I／OCLK引脚提供输入／输出时钟8序列，当由DSP提供的帧同步脉冲到来后，芯片从DATA IN接收4 b通道选择地址，同时从DATAOUT送出的前一次转换的结果，由DSP串行接收。I／OCLK接收DSP送出的输入序列长度为10～16个时钟周期。前4个有效时钟周期，将从DATAIN输入的4 b输入数据装载到输入数据寄存器，选择所需的模拟通道。接下来的6个时钟周期提供模拟输入采样的控制时间。模拟输入的采样在前10个I／O时钟序列后停止。第10个时钟沿（确切的I／O时钟边缘，即上升沿或下降沿，取决于操作的模式选择）将EOC变低，转换开始。
上传时间： 2014-12-05
上传用户：yepeng139
This book is an in-depth exploration into eVB s inherent features, and how to use them to solve likely mobile application programming tasks. After reading the book the reader will be able to write applications tackling a wide array of business problems for Windows CE-powered devices, both customized and for PocketPC and Handheld PC products. This book will help ease the transition into the language, and provide a reference for even more experienced developers.
标签： exploration in-depth features inherent
上传时间： 2013-12-12
上传用户：aa54
Returns weighted percentiles of a sample given the weight vector w ％ The idea is to give more emphasis in some examples of data as compared to ％ others by giving more weight. For example, we could give lower weights to ％ the outliers. ％ The motivation to write this function is to compute percentiles for Monte ％ Carlos simulations where some simulations are very bad (in terms of goodness ％ of fit between simulated and actual value) than the others and to give ％ the lower weights based on some goodness of fit criteria.
标签： percentiles weighted Returns sample
上传时间： 2016-01-28
上传用户：小儒尼尼奥
DirectX not only provides fast access to the hardware and therefore incredibly speedy performance, but it also makes it much easier for hardware developers to produce new devices that work well in the Windows environment. The DirectX APIs take away the necessity of writing your own low-level, device-specific code to access hardware such as the display adapter and network card, making it much easier for you to write programs that take full advantage of the computer s multimedia capabilities.
标签： performance incredibly therefore hardware
上传时间： 2016-02-16
上传用户：秦莞尔w
Generate 100 samples of a zero-mean white noise sequence with variance , by using a uniform random number generator. a Compute the autocorrelation of for . b Compute the periodogram estimate and plot it. c Generate 10 different realizations of , and compute the corresponding sample autocorrelation sequences , and . Compute the average autocorrelation sequence as and the corresponding periodogram for . d Compute and plot the average periodogram using the Bartlett method. e Comment on the results in parts (a) through (d).
标签： zero-mean Generate sequence variance
上传时间： 2016-03-04
上传用户：朗朗乾坤
数据结构 1、算法思路： 哈夫曼树算法：a）根据给定的n个权值{W1，W2… ，Wn }构成 n棵二叉树的集合F={T1，T2…，T n }，其中每棵二叉树T中只有一个带权为W i的根结点，其左右子树均空；b）在F中选取两棵根结点的权值最小的树作为左右子树构造一棵新的二叉树，且置新的二叉树的根结点的权值为其左、右子树上结点的权值之和；c）F中删除这两棵树，同时将新得到的二叉树加入F中； d）重复b)和c),直到F只含一棵树为止。
上传时间： 2016-03-05
上传用户：lacsx
(1).问题描述：集装箱的装箱问题 给定一个集装箱，其长为L，宽为W和高为H，现有一批圆柱形木材，每根木材的长均为L，但是半径不同，设第i根木材半径为ri。问如何装箱，使得集装箱的空间利用率最高？ (2).程序设计要求： a. 设计一个贪心算法 b. 任给一个输入实例，能输出集装箱的空间利用率 c. 能用图形演示装箱的过程 演示： 输入要测试的文件名，如c17.txt，程序将给出结果，并用图形演示。
标签： 集装箱
上传时间： 2014-01-07
上传用户：miaochun888
1) Write a function reverse(A) which takes a matrix A of arbitrary dimensions as input and returns a matrix B consisting of the columns of A in reverse order. Thus for example, if A = 1 2 3 then B = 3 2 1 4 5 6 6 5 4 7 8 9 9 8 7 Write a main program to call reverse(A) for the matrix A = magic(5). Print to the screen both A and reverse(A). 2) Write a program which accepts an input k from the keyboard, and which prints out the smallest fibonacci number that is at least as large as k. The program should also print out its position in the fibonacci sequence. Here is a sample of input and output: Enter k>0: 100 144 is the smallest fibonacci number greater than or equal to 100. It is the 12th fibonacci number.
标签： dimensions arbitrary function reverse
上传时间： 2016-04-16
上传用户：waitingfy
