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Voltage-Output

  • KNN算法实现

    KNN算法实现,初始化模糊成员等级 initialize fuzzy membership grades of sample output for fuzzy KNN

    标签: KNN 算法

    上传时间: 2013-12-25

    上传用户:waizhang

  • AM26C31CLow Power, I CC = 100 ƒ ⊂ A Typ Operate From a Single 5-V Supply High Spee

    AM26C31CLow Power, I CC = 100 ƒ ⊂ A Typ Operate From a Single 5-V Supply High Speed, t PLH = t PHL = 7 ns Typ Low Pulse Distortion, t sk(p) = 0.5 ns Typ High Output Impedance in Power-Off Conditions Improved Replacement for AM26LS31

    标签: Operate Single Supply Power

    上传时间: 2014-01-20

    上传用户:gtzj

  • These codes require an ASCII input file called input.dat of the following form: Lower Limit on x

    These codes require an ASCII input file called input.dat of the following form: Lower Limit on x Upper Limit on x Final Time Pressure for x<0 when t=0 Density for x<0 when t=0 Speed for x<0 when t=0 Pressure for x>0 when t=0 Density for x>0 when t=0 Speed for x>0 when t=0 These codes produce 8 ASCII output files: density.out. Density vs. x entropy.out. Entropy vs. x mach.out. Mach number vs. x massflux.out. Mass flux vs. x pressure.out. Pressure vs. x sound.out. Speed-of-sound vs. x velocity.out. Velocity vs. x waves.out. A description of the solution in terms of the three waves defined in the book (+,-,0).

    标签: input following require called

    上传时间: 2017-09-21

    上传用户:希酱大魔王

  • svd 算法代码 This directory contains instrumented SVDPACKC Version 1.0 (ANSI-C) programs for compiling

    svd 算法代码 This directory contains instrumented SVDPACKC Version 1.0 (ANSI-C) programs for compiling within the "svdrun" script. The "svdsum" script can be run after all output files of the form <dataset>.outN, where N=1,2,... have been produced by svdrun. more details please read the file readme!

    标签: instrumented directory compiling SVDPACKC

    上传时间: 2017-09-24

    上传用户:manking0408

  • fpga差分信号

    LVDS:Low Voltage Differential Signaling,低电压差分信号。 LVDS传输支持速率一般在155Mbps(大约为77MHZ)以上。

    标签: 差分信号

    上传时间: 2015-03-04

    上传用户:初夏浅浅时光

  • ISIS Timer Design

    A design about 8051 (running at 12MHz) based system with 3 7-Seg displays and two buttons to implement the following functions.  1. When press the + button, the display C = A+B.  2. When press the button, the display C = A - B.  “A” and “B” are 8-bit inputs when “C” is 9-bit output. 

    标签: ISIS AT89C52

    上传时间: 2015-05-05

    上传用户:guoxiy

  • Boost C++ Libraries 1.35.0

    Boost C++ Libraries Free peer-reviewed portable C++ source libraries Boost C++ Libraries 基本上是一個免費的 C++ 的跨平台函式庫集合,基本上應該可以把它視為 C++ STL 的功能再延伸;他最大的特色在於他是一個經過「同行評審」(peer review,可參考維基百科)、開放原始碼的函式庫,而且有許多 Boost 的函式庫是由 C++ 標準委員會的人開發的,同時部分函式庫的功能也已經成為 C++ TR1 (Technical Report 1,參考維基百科)、TR2、或是 C++ 0x 的標準了。 它的官方網站是:http://www.boost.org/,包含了 104 個不同的 library;由於他提供的函式庫非常地多,的內容也非常地多元,根據官方的分類,大致上可以分為下面這二十類: 字串和文字處理(String and text processing) 容器(Containers) Iterators 演算法(Algorithms) Function objects and higher-order programming 泛型(Generic Programming) Template Metaprogramming Preprocessor Metaprogramming Concurrent Programming 數學與數字(Math and numerics) 正確性與測試(Correctness and testing) 資料結構(Data structures) 影像處理(Image processing) 輸入、輸出(Input/Output) Inter-language support 記憶體(Memory) 語法分析(Parsing) 程式介面(Programming Interfaces) 其他雜項 Broken compiler workarounds 其中每一個分類,又都包含了一個或多個函式庫,可以說是功能相當豐富。

    标签: Boost C++ Libraries

    上传时间: 2015-05-15

    上传用户:fangfeng

  • 蛇形矩阵(规律)

    题目描述 蛇行矩阵 Problem 蛇形矩阵是由1开始的自然数依次排列成的一个矩阵上三角形。 输入 Input 本题有多组数据,每组数据由一个正整数N组成。(N不大于100)  输出 Output 对于每一组数据,输出一个N行的蛇形矩阵。两组输出之间不要额外的空行。  矩阵三角中同一行的数字用一个空格分开。行尾不要多余的空格。  样例输入 5 样例输出 1 3 6 10 15 2 5 9 14 4 8 13 7 12 11

    标签: 数字规律 数组 三角形

    上传时间: 2016-02-29

    上传用户:lwol2007

  • 计算本征值程序

    Computes all eigenvalues and eigenvectors of a real symmetric matrix a, ! which is of size n by n, stored in a physical np by np array. ! On output, elements of a above the diagonal are destroyed. ! d returns the eigenvalues of a in its first n elements. ! v is a matrix with the same logical and physical dimensions as a, ! whose columns contain, on output, the normalized eigenvectors of a. ! nrot returns the number of Jacobi rotations that were required. ! Please notice that the eigenvalues are not ordered on output. ! If the sorting is desired, the addintioal routine "eigsrt" ! can be invoked to reorder the output of jacobi.

    标签: 计算 程序

    上传时间: 2016-06-04

    上传用户:1512313

  • 运动会源代码

    #include <malloc.h>       #include <stdio.h>       #include <stdlib.h>       #include <string.h>       #define NULL 0      #define MaxSize 30          typedef struct athletestruct /*运动员*/     {         char name[20];          int score; /*分数*/         int range; /**/         int item; /*项目*/     }ATH;     typedef struct schoolstruct /*学校*/     {         int count; /*编号*/         int serial; /**/          int menscore; /*男选手分数*/         int womenscore; /*女选手分数*/         int totalscore; /*总分*/         ATH athlete[MaxSize]; /**/         struct schoolstruct *next;      }SCH;         int nsc,msp,wsp;      int ntsp;      int i,j;      int overgame;      int serial,range;      int n;      SCH *head,*pfirst,*psecond;      int *phead=NULL,*pafirst=NULL,*pasecond=NULL;     void create();         void input ()     {         char answer;          head = (SCH *)malloc(sizeof(SCH)); /**/         head->next = NULL;         pfirst = head;          answer = 'y';         while ( answer == 'y' )         {         Is_Game_DoMain:         printf("\nGET Top 5 when odd\nGET Top 3 when even");         printf("\n输入运动项目序号 (x<=%d):",ntsp);         scanf("%d",pafirst);         overgame = *pafirst;         if ( pafirst != phead )         {             for ( pasecond = phead ; pasecond < pafirst ; pasecond ++ )             {                 if ( overgame == *pasecond )                 {                     printf("\n这个项目已经存在请选择其他的数字\n");                     goto Is_Game_DoMain;                 }             }         }         pafirst = pafirst + 1;         if ( overgame > ntsp )         {             printf("\n项目不存在");             printf("\n请重新输入");             goto Is_Game_DoMain;         }         switch ( overgame%2 )         {         case 0: n = 3;break;         case 1: n = 5;break;         }         for ( i = 1 ; i <= n ; i++ )         {         Is_Serial_DoMain:         printf("\n输入序号 of the NO.%d (0<x<=%d): ",i,nsc);                 scanf("%d",&serial);         if ( serial > nsc )          {             printf("\n超过学校数目,请重新输入");             goto Is_Serial_DoMain;         }         if ( head->next == NULL )          {             create();         }         psecond = head->next ;          while ( psecond != NULL )          {             if ( psecond->serial == serial )             {                 pfirst = psecond;                 pfirst->count = pfirst->count + 1;                 goto Store_Data;             }             else             {                 psecond = psecond->next;             }         }         create();         Store_Data:                 pfirst->athlete[pfirst->count].item = overgame;         pfirst->athlete[pfirst->count].range = i;         pfirst->serial = serial;         printf("Input name:) : ");                 scanf("%s",pfirst->athlete[pfirst->count].name);         }         printf("\n继续输入运动项目(y&n)?");         answer = getchar();         printf("\n");         }     }         void calculate() /**/     {         pfirst = head->next;         while ( pfirst->next != NULL )         {             for (i=1;i<=pfirst->count;i++)             {                 if ( pfirst->athlete[i].item % 2 == 0 )                  {                     switch (pfirst->athlete[i].range)                     {                     case 1:pfirst->athlete[i].score = 5;break;                     case 2:pfirst->athlete[i].score = 3;break;                     case 3:pfirst->athlete[i].score = 2;break;                     }                 }                 else                  {                     switch (pfirst->athlete[i].range)                     {                     case 1:pfirst->athlete[i].score = 7;break;                     case 2:pfirst->athlete[i].score = 5;break;                     case 3:pfirst->athlete[i].score = 3;break;                     case 4:pfirst->athlete[i].score = 2;break;                     case 5:pfirst->athlete[i].score = 1;break;                     }                 }                 if ( pfirst->athlete[i].item <=msp )                  {                     pfirst->menscore = pfirst->menscore + pfirst->athlete[i].score;                 }                 else                  {                     pfirst->womenscore = pfirst->womenscore + pfirst->athlete[i].score;                 }             }             pfirst->totalscore = pfirst->menscore + pfirst->womenscore;             pfirst = pfirst->next;         }     }         void output()     {         pfirst = head->next;         psecond = head->next;         while ( pfirst->next != NULL )          {             // clrscr();              printf("\n第%d号学校的结果成绩:",pfirst->serial);             printf("\n\n项目的数目\t学校的名字\t分数");             for (i=1;i<=ntsp;i++)              {                 for (j=1;j<=pfirst->count;j++)                  {                     if ( pfirst->athlete[j].item == i )                     {                                                                         printf("\n %d\t\t\t\t\t\t%s\n %d",i,pfirst->athlete[j].name,pfirst->athlete[j].score);break;                                             }                 }             }             printf("\n\n\n\t\t\t\t\t\t按任意建 进入下一页");             getchar();             pfirst = pfirst->next;         }     //  clrscr();          printf("\n运动会结果:\n\n学校编号\t男运动员成绩\t女运动员成绩\t总分");         pfirst = head->next;         while ( pfirst->next != NULL )         {             printf("\n %d\t\t %d\t\t %d\t\t %d",pfirst->serial,pfirst->menscore,pfirst->womenscore,pfirst->totalscore);             pfirst = pfirst->next;         }         printf("\n\n\n\t\t\t\t\t\t\t按任意建结束");         getchar();     }         void create()     {                 pfirst = (struct schoolstruct *)malloc(sizeof(struct schoolstruct));         pfirst->next = head->next ;         head->next = pfirst ;                 pfirst->count = 1;         pfirst->menscore = 0;         pfirst->womenscore = 0;         pfirst->totalscore = 0;     }     void Save()     {FILE *fp;     if((fp = fopen("school.dat","wb"))==NULL)     {printf("can't open school.dat\n");     fclose(fp);     return;     }     fwrite(pfirst,sizeof(SCH),10,fp);     fclose(fp);     printf("文件已经成功保存\n");     }         void main()     {         system("cls");         printf("\n\t\t\t 运动会分数统计\n");         printf("输入学校数目 (x>= 5):");         scanf("%d",&nsc);          printf("输入男选手的项目(x<=20):");         scanf("%d",&msp);          printf("输入女选手项目(<=20):");         scanf("%d",&wsp);          ntsp = msp + wsp;                  phead = (int *)calloc(ntsp,sizeof(int));         pafirst = phead;         pasecond = phead;         input();         calculate();          output();         Save();     }             

    标签: 源代码

    上传时间: 2016-12-28

    上传用户:150501