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UCOS-II绘图圆和圆角<b>矩形</b>

  • VIP专区-单片机源代码精选合集系列(3)

    eeworm.com VIP专区 单片机源码系列 3资源包含以下内容:1. N97.rar2. TMS320C2000.rar3. wince.rar4. C8051F.rar5. ARM.rar6. nichelite.for.lpc.zip7. 12864.rar8. 神龙卡SDK (DirectShow版).zip9. READ_STC12C5A60S2.rar10. DS18B20.rar11. PowerLogic5.0.1.rar12. 51.rar13. 2410.rar14. UCOS2.52.rar15. arm9.rar16. yitaiwang.rar17. JLDLED.rar18. 51单片机方波发生器.rar19. efsl-0.3.6.zip20. MyGui.rar21. Zigbee2007.rar22. ZIGBEE.rar23. LCD12864.rar24. uCOS-II.rar25. uc-gui.rar26. wifi-of-88w8686.rar27. S3C2410_TEST.rar28. H-JTAG-V0.6.1.zip29. ZigBee_xbee.rar30. S7200Sysm.rar31. Led_font_extraction.zip32. IAR_example_EasyARM8962.zip33. siemensPLCjiaocheng.rar34. MFRC500antenna.rar35. LCD1602.rar36. ucos.rar37. s3c2410.rar38. 20086238534741.rar39. ISE7.1lesson.rar40. zlg_fs.rar41. DM9000.rar42. shuzicunchu.rar43. lgui_0.3.0.rar44. 单片机的40个实验.pdf45. STM32_fatfs_shell_SDHC.rar46. CC2430_chinese_pdf.rar47. cypressusb2.0.zip48. PIC.rar49. UCOS-2.rar50. pmc.rar51. boot.rar52. mp3.rar53. STdemo.rar54. ARM9.rar55. ARM7Proteus.rar56. 240128.rar57. AVRkaifashili.rar58. motor_control.zip59. yaoyaobang.rar60. wince_serialport.rar61. Document.rar62. zlggui.rar63. freescale.rar64. NIOS_UART_TEST.rar65. LPC2290.rar66. 硬件cpu&rom课程设计.rar67. ucfs.rar68. TL431.rar69. 单片机读写usb、sd卡技术参考资料.rar70. TCP_IPprotocol.rar71. TS8001K.rar72. nucleus_arm.rar73. 12864串行通信驱动.rar74. stc12c5608ad.zip75. ATmega16读写SD卡程序.rar76. Keil Cx51 V7.0单片机高级语言编程与uVision2应用实践.rar77. freescale单片机应用实例.rar78. 周立功 开发包 ARM9.rar79. 智能小车.rar80. 串行下载线的原理图.pdf81. C51入门.rar82. C51入门2.rar83. C51入门3.rar84. C51入门4.rar85. C51入门5.rar86. C51入门6.rar87. C51入门7.rar88.  单片机 漏电检测原理.doc89. nrf24z1 代码.rar90. 舞蹈机器人设计与制作.pdf91. C8051系列单片机开发与C语言编程!.rar92. PIC单片机C语言应用例程.rar93. 基于89c52的12864液晶程序.txt.rar94. 温度控制系统——毕业设计.rar95. 力天电子LPC210X例程代码.zip96. 新型楼道声控灯(毕业设计).rar97. stm32数码相框.rar98. 宏晶单片机的AD演示程序.rar99. 在VB下PC机与MCS.doc.doc100. 单片机技术应用教程.pdf

    标签: Matlab 编程

    上传时间: 2013-05-15

    上传用户:eeworm

  • 微电脑型数学演算式隔离传送器

    特点: 精确度0.1%满刻度 可作各式數學演算式功能如:A+B/A-B/AxB/A/B/A&B(Hi or Lo)/|A|/ 16 BIT类比输出功能 输入与输出绝缘耐压2仟伏特/1分钟(input/output/power) 宽范围交直流兩用電源設計 尺寸小,穩定性高

    标签: 微电脑 数学演算 隔离传送器

    上传时间: 2014-12-23

    上传用户:ydd3625

  • 微电脑型数学演算式双输出隔离传送器

    特点(FEATURES) 精确度0.1%满刻度 (Accuracy 0.1%F.S.) 可作各式数学演算式功能如:A+B/A-B/AxB/A/B/A&B(Hi or Lo)/|A| (Math functioA+B/A-B/AxB/A/B/A&B(Hi&Lo)/|A|/etc.....) 16 BIT 类比输出功能(16 bit DAC isolating analog output function) 输入/输出1/输出2绝缘耐压2仟伏特/1分钟(Dielectric strength 2KVac/1min. (input/output1/output2/power)) 宽范围交直流两用电源设计(Wide input range for auxiliary power) 尺寸小,稳定性高(Dimension small and High stability)

    标签: 微电脑 数学演算 输出 隔离传送器

    上传时间: 2013-11-24

    上传用户:541657925

  • AVR单片机数码管秒表显示

    #include<iom16v.h> #include<macros.h> #define uint unsigned int #define uchar unsigned char uint a,b,c,d=0; void delay(c) { for for(a=0;a<c;a++) for(b=0;b<12;b++); }; uchar tab[]={ 0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,

    标签: AVR 单片机 数码管

    上传时间: 2013-10-21

    上传用户:13788529953

  • 题目:利用条件运算符的嵌套来完成此题:学习成绩>=90分的同学用A表示

    题目:利用条件运算符的嵌套来完成此题:学习成绩>=90分的同学用A表示,60-89分之间的用B表示,60分以下的用C表示。 1.程序分析:(a>b)?a:b这是条件运算符的基本例子。

    标签: gt 90 运算符 嵌套

    上传时间: 2015-01-08

    上传用户:lifangyuan12

  • RSA算法 :首先, 找出三个数, p, q, r, 其中 p, q 是两个相异的质数, r 是与 (p-1)(q-1) 互质的数...... p, q, r 这三个数便是 person_key

    RSA算法 :首先, 找出三个数, p, q, r, 其中 p, q 是两个相异的质数, r 是与 (p-1)(q-1) 互质的数...... p, q, r 这三个数便是 person_key,接著, 找出 m, 使得 r^m == 1 mod (p-1)(q-1)..... 这个 m 一定存在, 因为 r 与 (p-1)(q-1) 互质, 用辗转相除法就可以得到了..... 再来, 计算 n = pq....... m, n 这两个数便是 public_key ,编码过程是, 若资料为 a, 将其看成是一个大整数, 假设 a < n.... 如果 a >= n 的话, 就将 a 表成 s 进位 (s

    标签: person_key RSA 算法

    上传时间: 2013-12-14

    上传用户:zhuyibin

  • 数字运算

    数字运算,判断一个数是否接近素数 A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no

    标签: 数字 运算

    上传时间: 2015-05-21

    上传用户:daguda

  • The government of a small but important country has decided that the alphabet needs to be streamline

    The government of a small but important country has decided that the alphabet needs to be streamlined and reordered. Uppercase letters will be eliminated. They will issue a royal decree in the form of a String of B and A characters. The first character in the decree specifies whether a must come ( B )Before b in the new alphabet or ( A )After b . The second character determines the relative placement of b and c , etc. So, for example, "BAA" means that a must come Before b , b must come After c , and c must come After d . Any letters beyond these requirements are to be excluded, so if the decree specifies k comparisons then the new alphabet will contain the first k+1 lowercase letters of the current alphabet. Create a class Alphabet that contains the method choices that takes the decree as input and returns the number of possible new alphabets that conform to the decree. If more than 1,000,000,000 are possible, return -1. Definition

    标签: government streamline important alphabet

    上传时间: 2015-06-09

    上传用户:weixiao99

  • We have a group of N items (represented by integers from 1 to N), and we know that there is some tot

    We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.

    标签: represented integers group items

    上传时间: 2016-01-17

    上传用户:jeffery

  • The XML Toolbox converts MATLAB data types (such as double, char, struct, complex, sparse, logical)

    The XML Toolbox converts MATLAB data types (such as double, char, struct, complex, sparse, logical) of any level of nesting to XML format and vice versa. For example, >> project.name = MyProject >> project.id = 1234 >> project.param.a = 3.1415 >> project.param.b = 42 becomes with str=xml_format(project, off ) "<project> <name>MyProject</name> <id>1234</id> <param> <a>3.1415</a> <b>42</b> </param> </project>" On the other hand, if an XML string XStr is given, this can be converted easily to a MATLAB data type or structure V with the command V=xml_parse(XStr).

    标签: converts Toolbox complex logical

    上传时间: 2016-02-12

    上传用户:a673761058