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Multiple-Input-<b>multiple-Output</b>

  • 1.有三根杆子A,B,C。A杆上有若干碟子 2.每次移动一块碟子,小的只能叠在大的上面 3.把所有碟子从A杆全部移到C杆上 经过研究发现

    1.有三根杆子A,B,C。A杆上有若干碟子 2.每次移动一块碟子,小的只能叠在大的上面 3.把所有碟子从A杆全部移到C杆上 经过研究发现,汉诺塔的破解很简单,就是按照移动规则向一个方向移动金片: 如3阶汉诺塔的移动:A→C,A→B,C→B,A→C,B→A,B→C,A→C 此外,汉诺塔问题也是程序设计中的经典递归问题

    标签: 移动 发现

    上传时间: 2016-07-25

    上传用户:gxrui1991

  • Produce Java classes to calculate and display the root of a quadratic equation when input the coeffi

    Produce Java classes to calculate and display the root of a quadratic equation when input the coefficients a, b and c within the range of -100 to 100 by user.

    标签: calculate the quadratic equation

    上传时间: 2014-01-17

    上传用户:aappkkee

  • 溫度華氏轉變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void)

    溫度華氏轉變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void) { int a=73,b=85,c=66 { if (a>=90) printf("a=A等級!!\n") else if (a>=80) printf("73分=B等級!!\n") else if (a>=70) printf("73分=C等級!!\n") else if (a>=60) printf("73分=D等級!!\n") else if (a<60) printf("73分=E等級!!\n") } { if (b>=90) printf("b=A等級!!\n") else if (b>=80) printf("85分=B等級!!\n") else if (b>=70) printf("85分=C等級!!\n") else if (b>=60) printf("85分=D等級!!\n") else if (b<60) printf("85分=E等級!!\n") } { if (c>=90) printf("c=A等級!!\n") else if (c>=80) printf("66分=B等級!!\n") else if (c>=70) printf("66分=C等級!!\n") else if (c>=60) printf("66分=D等級!!\n") else if (c<60) printf("66分=E等級!!\n") } system("pause") return 0 }

    标签: include stdlib stdio gt

    上传时间: 2014-11-10

    上传用户:wpwpwlxwlx

  • 溫度華氏轉變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void)

    溫度華氏轉變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void) { int a=73,b=85,c=66 { if (a>=90) printf("a=A等級!!\n") else if (a>=80) printf("73分=B等級!!\n") else if (a>=70) printf("73分=C等級!!\n") else if (a>=60) printf("73分=D等級!!\n") else if (a<60) printf("73分=E等級!!\n") } { if (b>=90) printf("b=A等級!!\n") else if (b>=80) printf("85分=B等級!!\n") else if (b>=70) printf("85分=C等級!!\n") else if (b>=60) printf("85分=D等級!!\n") else if (b<60) printf("85分=E等級!!\n") } { if (c>=90) printf("c=A等級!!\n") else if (c>=80) printf("66分=B等級!!\n") else if (c>=70) printf("66分=C等級!!\n") else if (c>=60) printf("66分=D等級!!\n") else if (c<60) printf("66分=E等級!!\n") } system("pause") return 0 }

    标签: include stdlib stdio gt

    上传时间: 2013-12-12

    上传用户:亚亚娟娟123

  • 输入、输出功能

    输入、输出功能,检验输入的数是否为数字功能,ASCII码与二进制数的的相互转化功能,两数相乘功能,因此整个程序定义了两个宏INPUT和MULTIPLE,宏INPUT实现了输入、检验和ASCII码与二进制的相互转换功能,MULTIPLE实现了两数相乘功能,实现输出功能的是子程序OUTPUT,由于在输入的过程中多次用到了回车换行,因此定义了一个回车换行子程序CRLF。

    标签: 输入 输出功能

    上传时间: 2017-02-08

    上传用户:Ants

  • All of Java s Input/Output (I/O) facilities are based on streams, which provide simple ways to read

    All of Java s Input/Output (I/O) facilities are based on streams, which provide simple ways to read and write data of different types. Java provides many different kinds of streams, each with its own application. The universe of streams is divided into four large categories: input streams and output streams, for reading and writing binary data and readers and writers, for reading and writing textual (character) data. You re almost certainly familiar with the basic kinds of streams--but did you know that there s a CipherInputStream for reading encrypted data? And a ZipOutputStream for automatically compressing data? Do you know how to use buffered streams effectively to make your I/O operations more efficient? Java I/O, 2nd Edition has been updated for Java 5.0 APIs and tells you all you ever need to know about streams--and probably more.

    标签: facilities streams provide Output

    上传时间: 2013-12-17

    上传用户:6546544

  • 给定两个集合A、B

    给定两个集合A、B,集合内的任一元素x满足1 ≤ x ≤ 109,并且每个集合的元素个数不大于105。我们希望求出A、B之间的关系。 任 务 :给定两个集合的描述,判断它们满足下列关系的哪一种: A是B的一个真子集,输出“A is a proper subset of B” B是A的一个真子集,输出“B is a proper subset of A” A和B是同一个集合,输出“A equals B” A和B的交集为空,输出“A and B are disjoint” 上述情况都不是,输出“I m confused!”

    标签:

    上传时间: 2017-03-15

    上传用户:yulg

  • 3rd Generation Partnership Project Technical Specification Group Radio Access Network Spatial ch

    3rd Generation Partnership Project Technical Specification Group Radio Access Network Spatial channel model for Multiple Input Multiple Output [MIMO] simulations

    标签: Specification Partnership Generation Technical

    上传时间: 2014-01-11

    上传用户:nanfeicui

  • Complex Orthogonal Space-Time Processing

    Multiple-Input Multiple-Output (MIMO) systems have recently been the subject of intensive consideration in modem wireless communications as they offer the potential of providing high capacity, thus unleashing a wide range of applications in the wireless domain. The main feature of MIMO systems is the use of space-time processing and Space-Time Codes (STCs). Among a variety of STCs, orthogonal Space-Time Block Codes (STBCs) have a much simpler decoding method, compared to other STCs

    标签: Orthogonal Space-Time Processing Complex

    上传时间: 2020-05-26

    上传用户:shancjb

  • Dynamic+Channel+Acquisition

    Multiuser multiple-input-multiple-output (MU- MIMO) systems are known to be hindered by dimensionality loss due to channel state information (CSI) acquisition overhead. In this paper, we investigate user-scheduling in MU-MIMO systems on account of CSI acquisition overhead, where a base station dynamically acquires user channels to avoid choking the system with CSI overhead. 

    标签: Acquisition Dynamic Channel

    上传时间: 2020-05-27

    上传用户:shancjb