Tug of War(A tug of war is to be arranged at the local office picnic. For the tug of war, the picnickers must be divided into two teams. Each person must be on one team or the other the number of people on the two teams must not differ by more than 1 the total weight of the people on each team should be as nearly equal as possible. The first line of input contains n the number of people at the picnic. n lines follow. The first line gives the weight of person 1 the second the weight of person 2 and so on. Each weight is an integer between 1 and 450. There are at most 100 people at the picnic. Your output will be a single line containing 2 numbers: the total weight of the people on one team, and the total weight of the people on the other team. If these numbers differ, give the lesser first. )
上传时间： 2014-01-07
上传用户：离殇
硬件设计vhdl_cpu1,1. You may copy and distribute verbatim copies of this core, as long -- as this file, and the other associated files, remain intact and -- unmodified. Modifications are outlined below.
标签： this distribute vhdl_cpu verbatim
上传时间： 2015-03-20
上传用户：aa17807091
RSA算法 :首先, 找出三个数, p, q, r, 其中 p, q 是两个相异的质数, r 是与 (p-1)(q-1) 互质的数...... p, q, r 这三个数便是 person_key，接著, 找出 m, 使得 r^m == 1 mod (p-1)(q-1)..... 这个 m 一定存在, 因为 r 与 (p-1)(q-1) 互质, 用辗转相除法就可以得到了..... 再来, 计算 n = pq....... m, n 这两个数便是 public_key ，编码过程是, 若资料为 a, 将其看成是一个大整数, 假设 a < n.... 如果 a >= n 的话, 就将 a 表成 s 进位 (s
标签： person_key RSA 算法
上传时间： 2013-12-14
上传用户：zhuyibin
按递归下降方式设计其编译程序，生成PL/0栈式指令代码，然后解释执行。用(a=1)+2*(b=3+4*5)/2+2*a*b-(a=a+5)/ (c=2) 测试
上传时间： 2014-01-02
上传用户：firstbyte
In each step the LZSS algorithm sends either a character or a <position, length> pair. Among these, perhaps character "e" appears more frequently than "x", and a <position, length> pair of length 3 might be commoner than one of length 18, say. Thus, if we encode the more frequent in fewer bits and the less frequent in more bits, the total length of the encoded text will be diminished. This consideration suggests that we use Huffman or arithmetic coding, preferably of adaptive kind, along with LZSS.
标签： algorithm character position either
上传时间： 2014-01-27
上传用户：wang0123456789
This model simulates a CDMA2000 1xRTT Forward link (between Base Station and Mobile Station). In particular, it simulates the Radio Configuration 3 of a Forward Fundamental channel. The block CDMA2k: Initial settings allows you to set different parameters such as data rate, Power Control SubChannel insertion rate, spreading code index, QOSF index and the channel model.
标签： Station simulates Forward between
上传时间： 2015-03-28
上传用户：13215175592
This an adaptive receiver for a direct-sequence spread spectrum (DS-SS) system over an AWGN channel. The adaptive receiver block is modified from the LMS adaptive filter block in DSP Blockset. For DS-SS signal reception, the adaptive filter needs to have multi-rate operation. The input sample rate is equal to chip rate and the output is at symbol rate. Two rates are related by PG, processing gain
标签： direct-sequence adaptive receiver spectrum
上传时间： 2014-01-16
上传用户：D&L37
This a Bayesian ICA algorithm for the linear instantaneous mixing model with additive Gaussian noise [1]. The inference problem is solved by ML-II, i.e. the sources are found by integration over the source posterior and the noise covariance and mixing matrix are found by maximization of the marginal likelihood [1]. The sufficient statistics are estimated by either variational mean field theory with the linear response correction or by adaptive TAP mean field theory [2,3]. The mean field equations are solved by a belief propagation method [4] or sequential iteration. The computational complexity is N M^3, where N is the number of time samples and M the number of sources.
标签： instantaneous algorithm Bayesian Gaussian
上传时间： 2013-12-19
上传用户：jjj0202
The flpydisk sample is a floppy driver that resides in the directory \\Ntddk\Src\Storage\Fdc\Flpydsk. It is similar to a class driver in that it sits a level above the floppy disk controller in the driver stack, and brokers communication between the application level and the low-level driver. The floppy driver takes commands from the application and then calls routines in the controller which will in turn perform the actual interaction with the device. The sample compiles in 64-bit, but has not been tested in this environment. It is compatible with x86 and Alpha platforms.
标签： NtddkSrcStorageFdcFlpydsk directory flpydisk resides
上传时间： 2015-03-30
上传用户：龙飞艇
REMOVE removes a TSR. It takes two command line arguments. The first is the name of TSR to be removed (or an * to remove the last one), and the second is a file name which MUST contain the interrupt vectors to be loaded when the TSR is removed.
标签： TSR arguments removes command
上传时间： 2013-12-09
上传用户：wys0120
