WHAT MIME64 IS: MIME64 is an encoding described in RFC1341 as MIME base64.Its purpose is to encode binary files into ASCII so that they may be passedthrough e-mail gates. In this regard, MIME64 is similar to UUENCODE.Although most binaries these days are transmitted using UUENCODE, Ihave seen a few using MIME64, and I have had requests from friends thatI decode MIME64 files that have fallen into their hands. As long assome MIME64 continues to exist, a package such as this one is usefulto have.
标签： MIME described 64 encoding
上传时间： 2013-12-17
上传用户：maizezhen
UnZip is a small zipfile extract utility. It is written to be assmall portable as possible and is intended to be starting point for im-plementation of .ZIP files in non-IBM environments.Source code is provided in C and Turbo Pascal. If you port this programto a non-IBM system, I would appreciate a copy of the ported source andexe files.
标签： is portable possible extract
上传时间： 2014-01-20
上传用户：维子哥哥
The code assumes a two-dimensional computational domain with TMz polarization (i.e., non-zero field Ez, Hx, and Hy). The program is currently written so that the incident field always strikes the lower-left corner of the total-field region first. (If you want a different corner, that should be a fairly simple tweak to the code, but for now you ll have to make that tweak yourself.) I have attempted to provide copious comments in the code and hope that a knowledgeable C programmer can quickly map the approach as described in the paper to what is in the program.
标签： two-dimensional computational polarization non-zero
上传时间： 2013-12-13
上传用户：cylnpy
In case you haven t realized it, building computer systems is hard. As the complexity of the system gets greater, the task of building the software gets exponentially harder. As in any profession, we can progress only by learning, both from our mistakes and from our successes. This book represents some of this learning written in a form that I hope will help you to learn these lessons quicker than I did, or to communicate to others more effectively than I did before I boiled these patterns down.
标签： complexity the building computer
上传时间： 2015-04-25
上传用户：tyler
This is a program that I did several days ago.It is about Airport Ticket Sale System.You can use it as an example.
标签： Airport program several System
上传时间： 2015-06-14
上传用户：skhlm
This application note describes a method for developing block-oriented I/O device drivers for applications that use the DSP/BIOS real-time kernel and includes examples that run with Code Composer Studio v2.1 on the Texas Instruments TMS320C5402 and TMS320C6711 DSP Starter Kits (DSKs). The device driver model presented here has now been superceded with an updated version that supports not only block oriented devices, but also devices such as UARTs, PCI and USB buses and Multimedia cards. Documentation on the updated driver model as well as example drivers and source code can be found in the Device Driver Developer s Kit product now available for download from the TI Developer s Village.
标签： block-oriented application developing describes
上传时间： 2015-07-07
上传用户：kelimu
驱动开发向导 I came across an article QuickSYS which implements an NT driver framework. That article demonstrates a MFC application that gets a project name as a parameter and creates Visual C++ workspace with NT driver framework. I decided to copy the NT driver framework source and to put it in the Visual Studio project wizard as seen above. This is simpler rather than running an external executable application that generates the code for you.
标签： article implements framework QuickSYS
上传时间： 2014-01-07
上传用户：2467478207
ACM试题An Easy Problem Description As we known, data stored in the computers is in binary form. The problem we discuss now is about the positive integers and its binary form. Given a positive integer I, you task is to find out an integer J, which is the minimum integer greater than I, and the number of 1 s in whose binary form is the same as that in the binary form of I. For example, if "78" is given, we can write out its binary form, "1001110". This binary form has 4 1 s. The minimum integer, which is greater than "1001110" and also contains 4 1 s, is "1010011", i.e. "83", so you should output "83".
标签： Description computers Problem binary
上传时间： 2013-12-11
上传用户：libenshu01
This section contains a brief introduction to the C language. It is intended as a tutorial on the language, and aims at getting a reader new to C started as quickly as possible. It is certainly not intended as a substitute for any of the numerous textbooks on C. 2. write a recursive function FIB (n) to find out the nth element in theFibanocci sequence number which is 1,1,2,3,5,8,13,21,34,55,…3. write the prefix and postfix form of the following infix expressiona + b – c / d + e * f – g * h / i ^ j4. write a function to count the number of nodes in a binary tr
标签： introduction the contains intended
上传时间： 2013-12-23
上传用户：liansi
Following is a repost of the public domain make that I posted to net.sources a couple of months ago. I have fixed a few bugs, and added some more features, and the resulting changes amounted to about as much text as the whole program (hence the repost).一个编译器C代码，详见REDME。
标签： Following sources domain couple
上传时间： 2015-09-01
上传用户：manlian
