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6<b>09</b>

  • TLC2543 中文资料

    TLC2543是TI公司的12位串行模数转换器,使用开关电容逐次逼近技术完成A/D转换过程。由于是串行输入结构,能够节省51系列单片机I/O资源;且价格适中,分辨率较高,因此在仪器仪表中有较为广泛的应用。 TLC2543的特点 (1)12位分辩率A/D转换器; (2)在工作温度范围内10μs转换时间; (3)11个模拟输入通道; (4)3路内置自测试方式; (5)采样率为66kbps; (6)线性误差±1LSBmax; (7)有转换结束输出EOC; (8)具有单、双极性输出; (9)可编程的MSB或LSB前导; (10)可编程输出数据长度。 TLC2543的引脚排列及说明    TLC2543有两种封装形式:DB、DW或N封装以及FN封装,这两种封装的引脚排列如图1,引脚说明见表1 TLC2543电路图和程序欣赏 #include<reg52.h> #include<intrins.h> #define uchar unsigned char #define uint unsigned int sbit clock=P1^0; sbit d_in=P1^1; sbit d_out=P1^2; sbit _cs=P1^3; uchar a1,b1,c1,d1; float sum,sum1; double  sum_final1; double  sum_final; uchar duan[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f}; uchar wei[]={0xf7,0xfb,0xfd,0xfe};  void delay(unsigned char b)   //50us {           unsigned char a;           for(;b>0;b--)                     for(a=22;a>0;a--); }  void display(uchar a,uchar b,uchar c,uchar d) {    P0=duan[a]|0x80;    P2=wei[0];    delay(5);    P2=0xff;    P0=duan[b];    P2=wei[1];    delay(5);   P2=0xff;   P0=duan[c];   P2=wei[2];   delay(5);   P2=0xff;   P0=duan[d];   P2=wei[3];   delay(5);   P2=0xff;   } uint read(uchar port) {   uchar  i,al=0,ah=0;   unsigned long ad;   clock=0;   _cs=0;   port<<=4;   for(i=0;i<4;i++)  {    d_in=port&0x80;    clock=1;    clock=0;    port<<=1;  }   d_in=0;   for(i=0;i<8;i++)  {    clock=1;    clock=0;  }   _cs=1;   delay(5);   _cs=0;   for(i=0;i<4;i++)  {    clock=1;    ah<<=1;    if(d_out)ah|=0x01;    clock=0; }   for(i=0;i<8;i++)  {    clock=1;    al<<=1;    if(d_out) al|=0x01;    clock=0;  }   _cs=1;   ad=(uint)ah;   ad<<=8;   ad|=al;   return(ad); }  void main()  {   uchar j;   sum=0;sum1=0;   sum_final=0;   sum_final1=0;    while(1)  {              for(j=0;j<128;j++)          {             sum1+=read(1);             display(a1,b1,c1,d1);           }            sum=sum1/128;            sum1=0;            sum_final1=(sum/4095)*5;            sum_final=sum_final1*1000;            a1=(int)sum_final/1000;            b1=(int)sum_final%1000/100;            c1=(int)sum_final%1000%100/10;            d1=(int)sum_final%10;            display(a1,b1,c1,d1);           }         } 

    标签: 2543 TLC

    上传时间: 2013-11-19

    上传用户:shen1230

  • PIC单片机程序设计基础

    1、程序的基本格式先介绍二条伪指令:EQU ——标号赋值伪指令ORG ——地址定义伪指令PIC16C5X在RESET后指令计算器PC被置为全“1”,所以PIC16C5X几种型号芯片的复位地址为:PIC16C54/55:1FFHPIC16C56:3FFHPIC16C57/58:7FFH一般来说,PIC的源程序并没有要求统一的格式,大家可以根据自己的风格来编写。但这里我们推荐一种清晰明了的格式TITLE This is ⋯⋯ ;程序标题;--------------------------------------;名称定义和变量定义;--------------------------------------F0 EQU 0RTCC EQU 1PC EQU 2STATUS EQU 3FSR EQU 4RA EQU 5RB EQU 6RC EQU 7┋PIC16C54 EQU 1FFH ;芯片复位地址PIC16C56 EQU 3FFHPIC16C57 EQU 7FFH;-----------------------------------------ORG PIC16C54 GOTO MAIN ;在复位地址处转入主程序ORG 0 ;在0000H开始存放程序;-----------------------------------------;子程序区;-----------------------------------------DELAY MOVLW 255┋RETLW 0;------------------------------------------;主程序区;------------------------------------------MAINMOVLW B‘00000000’TRIS RB ;RB已由伪指令定义为6,即B口┋LOOPBSF RB,7 CALL DELAYBCF RB,7 CALL DELAY┋GOTO LOOP;-------------------------------------------END ;程序结束注:MAIN标号一定要处在0页面内。2、程序设计基础

    标签: PIC 单片机程序设计

    上传时间: 2013-11-14

    上传用户:cjf0304

  • 数字运算

    数字运算,判断一个数是否接近素数 A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no

    标签: 数字 运算

    上传时间: 2015-05-21

    上传用户:daguda

  • The government of a small but important country has decided that the alphabet needs to be streamline

    The government of a small but important country has decided that the alphabet needs to be streamlined and reordered. Uppercase letters will be eliminated. They will issue a royal decree in the form of a String of B and A characters. The first character in the decree specifies whether a must come ( B )Before b in the new alphabet or ( A )After b . The second character determines the relative placement of b and c , etc. So, for example, "BAA" means that a must come Before b , b must come After c , and c must come After d . Any letters beyond these requirements are to be excluded, so if the decree specifies k comparisons then the new alphabet will contain the first k+1 lowercase letters of the current alphabet. Create a class Alphabet that contains the method choices that takes the decree as input and returns the number of possible new alphabets that conform to the decree. If more than 1,000,000,000 are possible, return -1. Definition

    标签: government streamline important alphabet

    上传时间: 2015-06-09

    上传用户:weixiao99

  • 【问题描述】 在一个N*N的点阵中

    【问题描述】 在一个N*N的点阵中,如N=4,你现在站在(1,1),出口在(4,4)。你可以通过上、下、左、右四种移动方法,在迷宫内行走,但是同一个位置不可以访问两次,亦不可以越界。表格最上面的一行加黑数字A[1..4]分别表示迷宫第I列中需要访问并仅可以访问的格子数。右边一行加下划线数字B[1..4]则表示迷宫第I行需要访问并仅可以访问的格子数。如图中带括号红色数字就是一条符合条件的路线。 给定N,A[1..N] B[1..N]。输出一条符合条件的路线,若无解,输出NO ANSWER。(使用U,D,L,R分别表示上、下、左、右。) 2 2 1 2 (4,4) 1 (2,3) (3,3) (4,3) 3 (1,2) (2,2) 2 (1,1) 1 【输入格式】 第一行是数m (n < 6 )。第二行有n个数,表示a[1]..a[n]。第三行有n个数,表示b[1]..b[n]。 【输出格式】 仅有一行。若有解则输出一条可行路线,否则输出“NO ANSWER”。

    标签: 点阵

    上传时间: 2014-06-21

    上传用户:llandlu

  • 常用芯片DIP SOT SOIC QFP电阻电容二极管等3D模型库 3D视图封装库 STEP后缀三维

    常用芯片DIP SOT SOIC QFP电阻电容二极管等3D模型库 3D视图封装库 STEP后缀三维视图(154个):050-9.STEP0805R.STEP1001-1.STEP1001-2.STEP1001-3.STEP1001-4.STEP1001-5.STEP1001-6.STEP1001-7.STEP1001-8.STEP103_1KV.STEP10X5JT.STEP1206R.STEP13PX2.STEP15PX2.STEP20P插针.STEP25V1000UF.STEP3296W.STEP35V2200UF.STEP3mmLED.STEP3mmLEDH.STEP3X3可调电阻.STEP400V0.1UF.STEP455.STEP630V0.1UF.STEP7805.STEP8P4R.STEPAXIAL-0.2-0.125W.STEPAXIAL-0.4-0.25W.STEPaxial-0.6-2W.STEPB-3528.STEPC-0805.STEPC06x18.STEPCAP-6032.STEPCH3.96 X2.STEPCH3.96-3P.STEPD-PAK.STEPDB25.STEPDC-30.STEPDIP14.STEPDIP16.STEPDIP6.STEPDIP8.STEPDO-214AA.STEPDO-214AB.STEPDO-214AC.STEPDO-41.STEPDO-41Z.STEPFMQ.STEPGNR14D.STEPH9700.STEPILI4981.STEPIN4007.STEPIN5408.STEPJP051-6P6C_02.STEPJQC-3F.STEPJS-1132-10.STEPJS-1132-11.STEPJS-1132-12.STEPJS-1132-13.STEPJS-1132-14.STEPJS-1132-15.STEPJS-1132-2.STEPJS-1132-3.STEPJS-1132-4.STEPJS-1132-5.STEPJS-1132-6.STEPJS-1132-7.STEPJS-1132-8.STEPJS-1132-9.STEPJS-1132R-2.STEPJS-1132R-3.STEPJS-1132R-4.STEPJS-1132R-5.STEPJS-1132R-6.STEPJS-1132R-7.STEPJS-1132R-8.STEPJZC-33F.STEPKBP210.STEPKE2108.STEPKF2510 X8.STEPKF301.STEPKF301x3.STEPKSD-9700.STEPLED5_BLUE.STEPLED5_GRE.STEPLED5_RED.STEPLED5_YEL.STEPLFCSP_WQ.STEPLQFP100.STEPLQFP48.STEPMC-146.STEPmolex-22-27-2021.STEPmolex-22-27-2031.STEPmolex-22-27-2041.STEPmolex-22-27-2051.STEPmolex-22-27-2061.STEPmolex-22-27-2071.STEPmolex-22-27-2081.STEPMSOP10.STEPMSOP8.STEPPA0630NOXOX-HA1.STEPPIN10.STEPPIN24.STEPPIN24A.STEPR 0805.STEPR0402.STEPR0603.STEPR0805.STEPR1206.STEPRA-15.STEPRA-20.STEPRS808.STEPSIP-3-3.96 22-27-2031.STEPSL-B.STEPSL-D.STEPSL-E.STEPSL-G.STEPSL-H.STEPSOD-123.STEPSOD-323.STEPSOD-523.STEPSOD-723.STEPSOD-80.STEPSOIC-8.STEPSOP-4.STEPSOP14.STEPSOP16.STEPSOP18.STEPSOT-89.STEPSOT223.STEPSOT23-3.STEPSOT23-5.STEPSSOP28.STEPTAJ-A.STEPTAJ-B.STEPTAJ-C.STEPTAJ-D.STEPTAJ-E.STEPTAJ-R.STEPTHB6064H.STEPTO-126.STEPTO-126X.STEPTO-220.STEPTO-247.STEPTO-252-3L.STEPTOSHIBA_11-4C1.STEPTSSOP-8.STEPTSSOP14-BOTTON.STEPTSSOP14.STEPTSSOP28.STEPUSB-A.STEPUSB-B.STEPWT.STEP

    标签: 芯片 dip sot soic qfp 电阻 电容 二极管 封装

    上传时间: 2021-11-21

    上传用户:XuVshu

  • 安森美车规级1080P图像传感器AR0231手册

    AR0231AT7C00XUEA0-DRBR(RGB滤光)安森美半导体推出采用突破性减少LED闪烁 (LFM)技术的新的230万像素CMOS图像传感器样品AR0231AT,为汽车先进驾驶辅助系统(ADAS)应用确立了一个新基准。新器件能捕获1080p高动态范围(HDR)视频,还具备支持汽车安全完整性等级B(ASIL B)的特性。LFM技术(专利申请中)消除交通信号灯和汽车LED照明的高频LED闪烁,令交通信号阅读算法能于所有光照条件下工作。AR0231AT具有1/2.7英寸(6.82 mm)光学格式和1928(水平) x 1208(垂直)有源像素阵列。它采用最新的3.0微米背照式(BSI)像素及安森美半导体的DR-Pix™技术,提供双转换增益以在所有光照条件下提升性能。它以线性、HDR或LFM模式捕获图像,并提供模式间的帧到帧情境切换。 AR0231AT提供达4重曝光的HDR,以出色的噪声性能捕获超过120dB的动态范围。AR0231AT能同步支持多个摄相机,以易于在汽车应用中实现多个传感器节点,和通过一个简单的双线串行接口实现用户可编程性。它还有多个数据接口,包括MIPI(移动产业处理器接口)、并行和HiSPi(高速串行像素接口)。其它关键特性还包括可选自动化或用户控制的黑电平控制,支持扩频时钟输入和提供多色滤波阵列选择。封装和现状:AR0231AT采用11 mm x 10 mm iBGA-121封装,现提供工程样品。工作温度范围为-40℃至105℃(环境温度),将完全通过AEC-Q100认证。

    标签: 图像传感器

    上传时间: 2022-06-27

    上传用户:XuVshu

  • 微电脑型数学演算式隔离传送器

    特点: 精确度0.1%满刻度 可作各式數學演算式功能如:A+B/A-B/AxB/A/B/A&B(Hi or Lo)/|A|/ 16 BIT类比输出功能 输入与输出绝缘耐压2仟伏特/1分钟(input/output/power) 宽范围交直流兩用電源設計 尺寸小,穩定性高

    标签: 微电脑 数学演算 隔离传送器

    上传时间: 2014-12-23

    上传用户:ydd3625

  • 微电脑型数学演算式双输出隔离传送器

    特点(FEATURES) 精确度0.1%满刻度 (Accuracy 0.1%F.S.) 可作各式数学演算式功能如:A+B/A-B/AxB/A/B/A&B(Hi or Lo)/|A| (Math functioA+B/A-B/AxB/A/B/A&B(Hi&Lo)/|A|/etc.....) 16 BIT 类比输出功能(16 bit DAC isolating analog output function) 输入/输出1/输出2绝缘耐压2仟伏特/1分钟(Dielectric strength 2KVac/1min. (input/output1/output2/power)) 宽范围交直流两用电源设计(Wide input range for auxiliary power) 尺寸小,稳定性高(Dimension small and High stability)

    标签: 微电脑 数学演算 输出 隔离传送器

    上传时间: 2013-11-24

    上传用户:541657925

  • AVR单片机数码管秒表显示

    #include<iom16v.h> #include<macros.h> #define uint unsigned int #define uchar unsigned char uint a,b,c,d=0; void delay(c) { for for(a=0;a<c;a++) for(b=0;b<12;b++); }; uchar tab[]={ 0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,

    标签: AVR 单片机 数码管

    上传时间: 2013-10-21

    上传用户:13788529953