* 高斯列主元素消去法求解矩阵方程AX=B,其中A是N*N的矩阵,B是N*M矩阵 * 输入: n----方阵A的行数 * a----矩阵A * m----矩阵B的列数 * b----矩阵B * 输出: det----矩阵A的行列式值 * a----A消元后的上三角矩阵 * b----矩阵方程的解X
上传时间： 2015-07-26
上传用户：xauthu
本程序是ARM7系列下LPC2148的例程，通过K7I开发板实现的数码管显示 1-2-3-4-5-6-7-8-9-0-A-b-C-d-E-F
上传时间： 2017-03-30
上传用户：1966640071
常用芯片DIP SOT SOIC QFP电阻电容二极管等3D模型库 3D视图封装库 STEP后缀三维视图（154个）:050-9.STEP0805R.STEP1001-1.STEP1001-2.STEP1001-3.STEP1001-4.STEP1001-5.STEP1001-6.STEP1001-7.STEP1001-8.STEP103_1KV.STEP10X5JT.STEP1206R.STEP13PX2.STEP15PX2.STEP20P插针.STEP25V1000UF.STEP3296W.STEP35V2200UF.STEP3mmLED.STEP3mmLEDH.STEP3X3可调电阻.STEP400V0.1UF.STEP455.STEP630V0.1UF.STEP7805.STEP8P4R.STEPAXIAL-0.2-0.125W.STEPAXIAL-0.4-0.25W.STEPaxial-0.6-2W.STEPB-3528.STEPC-0805.STEPC06x18.STEPCAP-6032.STEPCH3.96 X2.STEPCH3.96-3P.STEPD-PAK.STEPDB25.STEPDC-30.STEPDIP14.STEPDIP16.STEPDIP6.STEPDIP8.STEPDO-214AA.STEPDO-214AB.STEPDO-214AC.STEPDO-41.STEPDO-41Z.STEPFMQ.STEPGNR14D.STEPH9700.STEPILI4981.STEPIN4007.STEPIN5408.STEPJP051-6P6C_02.STEPJQC-3F.STEPJS-1132-10.STEPJS-1132-11.STEPJS-1132-12.STEPJS-1132-13.STEPJS-1132-14.STEPJS-1132-15.STEPJS-1132-2.STEPJS-1132-3.STEPJS-1132-4.STEPJS-1132-5.STEPJS-1132-6.STEPJS-1132-7.STEPJS-1132-8.STEPJS-1132-9.STEPJS-1132R-2.STEPJS-1132R-3.STEPJS-1132R-4.STEPJS-1132R-5.STEPJS-1132R-6.STEPJS-1132R-7.STEPJS-1132R-8.STEPJZC-33F.STEPKBP210.STEPKE2108.STEPKF2510 X8.STEPKF301.STEPKF301x3.STEPKSD-9700.STEPLED5_BLUE.STEPLED5_GRE.STEPLED5_RED.STEPLED5_YEL.STEPLFCSP_WQ.STEPLQFP100.STEPLQFP48.STEPMC-146.STEPmolex-22-27-2021.STEPmolex-22-27-2031.STEPmolex-22-27-2041.STEPmolex-22-27-2051.STEPmolex-22-27-2061.STEPmolex-22-27-2071.STEPmolex-22-27-2081.STEPMSOP10.STEPMSOP8.STEPPA0630NOXOX-HA1.STEPPIN10.STEPPIN24.STEPPIN24A.STEPR 0805.STEPR0402.STEPR0603.STEPR0805.STEPR1206.STEPRA-15.STEPRA-20.STEPRS808.STEPSIP-3-3.96 22-27-2031.STEPSL-B.STEPSL-D.STEPSL-E.STEPSL-G.STEPSL-H.STEPSOD-123.STEPSOD-323.STEPSOD-523.STEPSOD-723.STEPSOD-80.STEPSOIC-8.STEPSOP-4.STEPSOP14.STEPSOP16.STEPSOP18.STEPSOT-89.STEPSOT223.STEPSOT23-3.STEPSOT23-5.STEPSSOP28.STEPTAJ-A.STEPTAJ-B.STEPTAJ-C.STEPTAJ-D.STEPTAJ-E.STEPTAJ-R.STEPTHB6064H.STEPTO-126.STEPTO-126X.STEPTO-220.STEPTO-247.STEPTO-252-3L.STEPTOSHIBA_11-4C1.STEPTSSOP-8.STEPTSSOP14-BOTTON.STEPTSSOP14.STEPTSSOP28.STEPUSB-A.STEPUSB-B.STEPWT.STEP
标签： 芯片 dip sot soic qfp 电阻 电容 二极管 封装
上传时间： 2021-11-21
上传用户：XuVshu
|- 9.配套数据手册 - 0 B|- 8.面包板接线软件 - 0 B|- 7.物联网实验 - 0 B|- 6.图形化编程 - 0 B|- 5.实验接线图 - 0 B|- 4.视频教程 - 0 B|- 3.案例程序 - 0 B|- 2.开发环境 - 0 B|- 10.辅助软件 - 0 B|- 1.学前先看 - 0 B|- CLB.ico - 17.00 kB|- Autorun.inf - 23 B
上传时间： 2022-06-06
上传用户：
/*--------- 8051内核特殊功能寄存器 -------------*/ sfr ACC = 0xE0; //累加器 sfr B = 0xF0; //B 寄存器 sfr PSW = 0xD0; //程序状态字寄存器 sbit CY = PSW^7; //进位标志位 sbit AC = PSW^6; //辅助进位标志位 sbit F0 = PSW^5; //用户标志位0 sbit RS1 = PSW^4; //工作寄存器组选择控制位 sbit RS0 = PSW^3; //工作寄存器组选择控制位 sbit OV = PSW^2; //溢出标志位 sbit F1 = PSW^1; //用户标志位1 sbit P = PSW^0; //奇偶标志位 sfr SP = 0x81; //堆栈指针寄存器 sfr DPL = 0x82; //数据指针0低字节 sfr DPH = 0x83; //数据指针0高字节 /*------------ 系统管理特殊功能寄存器 -------------*/ sfr PCON = 0x87; //电源控制寄存器 sfr AUXR = 0x8E; //辅助寄存器 sfr AUXR1 = 0xA2; //辅助寄存器1 sfr WAKE_CLKO = 0x8F; //时钟输出和唤醒控制寄存器 sfr CLK_DIV = 0x97; //时钟分频控制寄存器 sfr BUS_SPEED = 0xA1; //总线速度控制寄存器 /*----------- 中断控制特殊功能寄存器 --------------*/ sfr IE = 0xA8; //中断允许寄存器 sbit EA = IE^7; //总中断允许位 sbit ELVD = IE^6; //低电压检测中断控制位 8051
上传时间： 2013-10-30
上传用户：yxgi5
数字运算，判断一个数是否接近素数 A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no
上传时间： 2015-05-21
上传用户：daguda
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
标签： represented integers group items
上传时间： 2016-01-17
上传用户：jeffery
* BASE64编码规则:将一组连续的字节数据按6个bit位进行分组,然后对每组数据用 * 一个ASICC字符来表示,6个bit位最多能表示2的6次方即64个数值,这64个ASICC字符 * 就是:"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/", * 其中每个字符表示的数值就是该字符在上面的排列中对应的索引号, * BASE64编码要求在对字节数据按每6个bit位进行分组时,如果不够6位则补"0", * 另一条规定就是编码后的结果长度必须是4的整数倍,否则补"=".
上传时间： 2016-02-12
上传用户：xzt
(1) 、用下述两条具体规则和规则形式实现.设大写字母表示魔王语言的词汇 小写字母表示人的语言词汇 希腊字母表示可以用大写字母或小写字母代换的变量.魔王语言可含人的词汇. (2) 、B→tAdA A→sae (3) 、将魔王语言B(ehnxgz)B解释成人的语言.每个字母对应下列的语言.
上传时间： 2013-12-30
上传用户：ayfeixiao
1、安装MS SQL Server2000 2、安装PowerBuilder8.0 3、根据《恢复数据库》文档恢复数据库yygl 数据库备份文件\code\database\yygl 数据库表结构文件\code\database\yygl.sql 4、拷贝code下的所有文件到你的硬盘，并将其所有文件取消只读属性 5、打开user.ini，修改文件Database>>ServerName的值 为安装MS SQL Server2000的计算机名称或IP地址； LogPassword的值为sa用户的登录口令 6、使用PowerBuilder8.0打开yygl.pbw文件
标签： codedatabaseyygl PowerBuilder Server 数据库
上传时间： 2016-04-03
上传用户：xinzhch
