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编解<b>码器</b>

  • 此文件为电子书籍

    此文件为电子书籍,无解压码

    标签: 电子 书籍

    上传时间: 2014-07-26

    上传用户:AbuGe

  • 数字运算

    数字运算,判断一个数是否接近素数 A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no

    标签: 数字 运算

    上传时间: 2015-05-21

    上传用户:daguda

  • 源代码用动态规划算法计算序列关系个数 用关系"<"和"="将3个数a

    源代码\用动态规划算法计算序列关系个数 用关系"<"和"="将3个数a,b,c依次序排列时,有13种不同的序列关系: a=b=c,a=b<c,a<b=v,a<b<c,a<c<b a=c<b,b<a=c,b<a<c,b<c<a,b=c<a c<a=b,c<a<b,c<b<a 若要将n个数依序列,设计一个动态规划算法,计算出有多少种不同的序列关系, 要求算法只占用O(n),只耗时O(n*n).

    标签: lt 源代码 动态规划 序列

    上传时间: 2013-12-26

    上传用户:siguazgb

  • c语言版的多项式曲线拟合。 用最小二乘法进行曲线拟合. 用p-1 次多项式进行拟合

    c语言版的多项式曲线拟合。 用最小二乘法进行曲线拟合. 用p-1 次多项式进行拟合,p<= 10 x,y 的第0个域x[0],y[0],没有用,有效数据从x[1],y[1] 开始 nNodeNum,有效数据节点的个数。 b,为输出的多项式系数,b[i] 为b[i-1]次项。b[0],没有用。 b,有10个元素ok。

    标签: 多项式 曲线拟合 c语言 最小二乘法

    上传时间: 2014-01-12

    上传用户:变形金刚

  • XviD源代码

    XviD源代码,mpeg-4的编解码源码

    标签: XviD 源代码

    上传时间: 2015-08-08

    上传用户:gdgzhym

  • 数据库制图者

    数据库制图者,用VB编的源码,很好用,是制图的好代码

    标签: 数据库 制图

    上传时间: 2014-01-03

    上传用户:924484786

  • 一个完整的数据库管理程序

    一个完整的数据库管理程序,用VB编的源码

    标签: 数据库管理 程序

    上传时间: 2013-12-22

    上传用户:蠢蠢66

  • 公司遥控器IC

    公司遥控器IC,类似于51单片机,但功能更强大,然后把其制作成一个解nec码的接受设备,省钱啊!

    标签: 遥控器

    上传时间: 2014-11-08

    上传用户:zyt

  • We have a group of N items (represented by integers from 1 to N), and we know that there is some tot

    We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.

    标签: represented integers group items

    上传时间: 2016-01-17

    上传用户:jeffery

  • 含声调的GBK拼音编码表

    含声调的GBK拼音编码表,XLS格式,用于编制拼音输入法或用于程序设计中,没有解压码。

    标签: GBK 声调 编码

    上传时间: 2014-01-04

    上传用户:zukfu