代码搜索:zero

找到约 10,000 项符合「zero」的源代码

代码结果 10,000
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h bldczc.h

/******************************************************************************* * Freescale Inc. * (c) Copyright 2005 Freescale, Inc. * ALL RIGHTS RESERVED. **************************************
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f90 secant.f90

module NUMERICAL implicit none real, parameter :: zero=0.00001 ! 小于zero的值会被当成0 contains ! 割线法的函数 real function secant(a,b,f) implicit none real :: a,b ! 起始的两个猜值 real :: c ! 新的解
www.eeworm.com/read/155415/11876389

cpp listboxst.cpp

#include "stdafx.h" #include "ListBoxST.h" #ifdef _DEBUG #define new DEBUG_NEW #undef THIS_FILE static char THIS_FILE[] = __FILE__; #endif #define MASK_DWDATA 0x01 // dwItemData is valid
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m fsolvtion2.m

function B=fsolvtion2(A) % A为系数矩阵 [m n]=size(A); if m==n&det(A)~=0 disp('only zero solvtion') end format rat %指定有理式格式输出 B=null(A,'r'); %求解空间的有理基
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m fsolvtion.m

function B=fsolvtion(A) % A为系数矩阵 [m n]=size(A); if m==n&det(A)~=0 disp('only zero solvtion') end rref(A)
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cpp bfs.cpp

#include "stdafx.h" #include "bfs.h" extern HASH tree; CString BFS::getIntroduction(){ CString intro = "广度优先搜索\r\n\r\n" "能保证找到最优解,搜索方式为逐层搜索。"; return intro; } int BFS::searc
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cpp astar1.cpp

#include "stdafx.h" #include "astar1.h" struct cmp{ inline bool operator()(const int & a, const int & b) const{ if(open[a].val == open[b].val) return open[a].step > open[b].step;
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cpp astar2.cpp

#include "stdafx.h" #include "astar2.h" struct cmp{ bool operator()(const int & a, const int & b) const{ if(open[a].val == open[b].val) return open[a].step > open[b].step; return
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cpp ida.cpp

#include "stdafx.h" #include "ida.h" extern HASH tree; CString IDA::getResult(){ CString str = searcher::getResult(); if(result == SUCCESS){ char ss[50]; sprintf(ss, "\r\n迭代时最多扩展出%d
www.eeworm.com/read/256636/11982637

cpp dfs.cpp

#include "stdafx.h" #include "dfs.h" CString DFS::getIntroduction(){ CString intro = "深度优先搜索\r\n\r\n" "搜索时优先搜索子树," "但是不能保证找到最优解。"; return intro; } int DFS::search(int b