代码搜索：integration
找到约 3,762 项符合「integration」的源代码
代码结果 3,762
www.eeworm.com/read/320096/3550567
js integration.js
/*hppage status="protected"*/
eval(unescape("%66%75%6E%63%74%69%6F%6E%20%68%70%5F%64%31%30%28%73%29%7B%72%65%74%75%72%6E%20%73%7D"));eval(hp_d10(unescape("%64%6F%63%75%6D%65%6E%74%2E%6F%6E%63%6F%6E%7
www.eeworm.com/read/313086/3646454
patch integration.patch
diff -Naur tcpip_old/Makefile tcpip/Makefile
--- tcpip_old/Makefile 2005-08-05 16:49:23.367528064 +0000
+++ tcpip/Makefile 2005-08-05 16:58:46.346942184 +0000
@@ -20,7 +20,10 @@
LWIP=../lwip
-ps2
www.eeworm.com/read/313086/3646467
patch integration.patch
diff -Naur tcpip_old/Makefile tcpip/Makefile
--- tcpip_old/Makefile 2005-08-05 16:49:23.367528064 +0000
+++ tcpip/Makefile 2005-08-05 16:58:46.346942184 +0000
@@ -20,7 +20,10 @@
LWIP=../lwip
-ps2
www.eeworm.com/read/306879/3731684
cpp integration.cpp
/*!
* \file
* \brief Implementation of numerical integration
* \author Tony Ottosson
*
* -------------------------------------------------------------------------
*
* IT++ - C++ library of math
www.eeworm.com/read/306879/3731685
h integration.h
/*!
* \file
* \brief Definition of numerical integration
* \author Tony Ottosson
*
* -------------------------------------------------------------------------
*
* IT++ - C++ library of mathemat
www.eeworm.com/read/288165/4009420
c integration.c
# include
# include
void main( )
{
int i, j, num;
int p, q, flagp, flagq;
printf("Please input a plus integer: ");
scanf("%d", &num);
/* 代码 (num%2)!=0) 表示num不能被2整除
www.eeworm.com/read/274119/4188916
c integration.c
# include
# include
void main( )
{
int i, j, num;
int p, q, flagp, flagq;
printf("Please input a plus integer: ");
scanf("%d", &num);
/* 代码 (num%2)!=0) 表示num不能被2整除
www.eeworm.com/read/392864/2490479
h integration.h
/******************************************************************************
File Name: common/Integration.h
Description: definitions of integration structures
integr
www.eeworm.com/read/195211/8168405
c integration.c
# include
# include
void main( )
{
int i, j, num;
int p, q, flagp, flagq;
printf("Please input a plus integer: ");
scanf("%d", &num);
/* 代码 (num%2)!=0) 表示num不能被2整除
www.eeworm.com/read/368337/9701138
c integration.c
#include
#include
#include
double f (double x, void * params) {
double alpha = *(double *) params;
double f = log(alpha*x) / sqrt(x);
return f;