代码搜索:TI C2000 有哪些应用?

找到约 10,000 项符合「TI C2000 有哪些应用?」的源代码

代码结果 10,000
www.eeworm.com/read/407780/11410902

txt pku 3399 贪心,考虑多种情况.txt

#include #include #include #include #include #include #include using namespace std; //PKU 3399 贪心,考虑多种情况 #define NMA
www.eeworm.com/read/157089/11740117

txt w77e58.txt

#include" w77c32.h" static int flag_1,flag_0; char c1[]="hello china"; char c2[]="hello World"; main() { int i; flag_1=1; flag_0=1; //system init ,其中串口0用定时器2,串口1用定时器1
www.eeworm.com/read/257061/11954276

m 8.9.m

K=tf(1,[1 0]); P0=tf([1 1],[1 0.2 5]); S0=1/(1+P0*K); %8.9.1 M=minreal(K*S0); h=normhinf(M); r=1./h %8.9.2 Ti=1-1/(1+K*P0); W=tf([0.2 2],[1 50]); M=minreal(Ti*W); h=normhinf(M); r=1./h %8
www.eeworm.com/read/342712/12005102

m yuce.m

function [outo,d,ave]=yuce(ti,to,IM,MT,hilayers) [samples,inum]=size(ti); %归一化 for i=1:inum %找出最大最小值 max(1,i)=ti(1,i); min(1,i)=ti(1,i); end for i=1:inum
www.eeworm.com/read/153044/12064409

m splinesafe.m

function theResult = splinesafe(t, z, ti, theSlopeFlag) % splinesafe -- Spline interpolation with end-slope control. % splinesafe(t, z, theSlopeFlag) returns "pp" coefficients for % interpolating
www.eeworm.com/read/153044/12064462

m splineq.m

function [ti, pp] = splineq(t, z, nPoints, theSlopeFlag) % splineq -- Equally-spaced spline interpolation. % [ti, pp] = splineq(t, z, nPoints, theSlopeFlag) interpolates % complex z(t) at nPoints
www.eeworm.com/read/152270/12129478

c myc1.c

#include "math.h" void fft(double *p,double *q,int n) { int i,j,k,l,m,n1,n2; double c,c1,e,s,s1,t,tr,ti; for(j=1,i=1;i
www.eeworm.com/read/152270/12129545

h myc1.h

#include "math.h" void fft(double *x,double *y,int n) { int i,j,k,l,m,n1,n2; double c,c1,e,s,s1,t,tr,ti; for(j=1,i=1;i
www.eeworm.com/read/340606/12145203

h l1p_ver.h

/************* Revision Controle System Header ************* * GSM Layer 1 software * L1P_VER.H * * Filename l1p_ver.h * Copyright 2003 (C) Texas Instruments *
www.eeworm.com/read/125507/14489299

winbond

/* winbond的w77e58双串口测试程(dhd0)*/ #include" w77c32.h" static int flag_1,flag_0; char c1[]="hello china"; char c2[]="hello World"; main() { int i; flag_1=1; flag_0=1;