代码搜索:Probability

找到约 4,670 项符合「Probability」的源代码

代码结果 4,670
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py channels.py

""" Copyright 2003 Mitsubishi Electric Research Laboratories All Rights Reserved. Permission to use, copy and modify this software and its documentation without fee for educational, r
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java radio.java

// $Id: Radio.java,v 1.5 2004/06/14 21:30:36 mikedemmer Exp $ /* * * * "Copyright (c) 2004 and The Regents of the University * of California. All rights reserved. * * Permission to use, copy,
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java empiricalmodel.java

// $Id: EmpiricalModel.java,v 1.9 2004/06/11 21:30:14 mikedemmer Exp $ /* tab:2 * * * "Copyright (c) 2000 and The Regents of the University * of California. All rights reserved. * * P
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java geneticalgorithm.java

/* * YALE - Yet Another Learning Environment * Copyright (C) 2001-2004 * Simon Fischer, Ralf Klinkenberg, Ingo Mierswa, * Katharina Morik, Oliver Ritthoff * Artificial
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java selectionmutation.java

/* * YALE - Yet Another Learning Environment * Copyright (C) 2001-2004 * Simon Fischer, Ralf Klinkenberg, Ingo Mierswa, * Katharina Morik, Oliver Ritthoff * Artificial
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java yagga.java

/* * YALE - Yet Another Learning Environment * Copyright (C) 2001-2004 * Simon Fischer, Ralf Klinkenberg, Ingo Mierswa, * Katharina Morik, Oliver Ritthoff * Artificial
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c bdtrl.c

/* bdtrl.c * * Binomial distribution * * * * SYNOPSIS: * * int k, n; * long double p, y, bdtrl(); * * y = bdtrl( k, n, p ); * * * * DESCRIPTION: * * Returns the sum of the terms
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c bdtrf.c

/* bdtrf.c * * Binomial distribution * * * * SYNOPSIS: * * int k, n; * float p, y, bdtrf(); * * y = bdtrf( k, n, p ); * * * * DESCRIPTION: * * Returns the sum of the terms 0 thr
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c bdtr.c

/* bdtr.c * * Binomial distribution * * * * SYNOPSIS: * * int k, n; * double p, y, bdtr(); * * y = bdtr( k, n, p ); * * DESCRIPTION: * * Returns the sum of the terms 0 through k o
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c userint.c

/*************************************************************************/ /* */ /* User interface for consulting trees and rulesets */ /* -----------------------------------------------