代码搜索:Microphone array
找到约 10,000 项符合「Microphone array」的源代码
代码结果 10,000
www.eeworm.com/read/269943/11053852
cpp cmpnt2.cpp
//
// Cmpnt2.cpp - Component 2
//
#include
#include "Iface.h"
#include "Util.h"
#include "CUnknown.h"
#include "Cmpnt2.h"
static inline void trace(char* msg)
{ Util::Trace("C
www.eeworm.com/read/335795/12499120
c main04.c
#include "Array_RC_S.h"
#include "try_array.C"
#include
int main()
{
static int ia[ 10 ] = { 12,7,14,9,128,17,6,3,27,5 };
static string sa[ 7 ] = {
"Eeyore", "Pooh", "Tig
www.eeworm.com/read/247673/12633446
c main04.c
#include "Array_RC_S.h"
#include "try_array.C"
#include
int main()
{
static int ia[ 10 ] = { 12,7,14,9,128,17,6,3,27,5 };
static string sa[ 7 ] = {
"Eeyore", "Pooh", "Tig
www.eeworm.com/read/146312/12659444
cpp dstring.cpp
#include
#include
#include
#include
#include "dstring.h"
#include "genarray.h"
#include
#pragma intrinsic strcpy
#pragma intrinsic memset
#pragma
www.eeworm.com/read/135898/13889098
c main04.c
#include "Array_RC_S.h"
#include "try_array.C"
#include
int main()
{
static int ia[ 10 ] = { 12,7,14,9,128,17,6,3,27,5 };
static string sa[ 7 ] = {
"Eeyore", "Pooh", "Tig
www.eeworm.com/read/237003/13983058
h listinit.h
/***************************************************************************
* blitz/listinit.h Classes for initialization lists
*
* $Id: listinit.h,v 1.4 2003/12/11 03:44:22 julianc Exp $
*
www.eeworm.com/read/237003/13984026
cpp peter-bienstman-5.cpp
// Creating arrays from array-expressions
#include "testsuite.h"
#include
BZ_USING_NAMESPACE(blitz)
int main()
{
Array A(4,3,fortranArray);
Array B(4,3,fort
www.eeworm.com/read/236649/14006392
c main04.c
#include "Array_RC_S.h"
#include "try_array.C"
#include
int main()
{
static int ia[ 10 ] = { 12,7,14,9,128,17,6,3,27,5 };
static string sa[ 7 ] = {
"Eeyore", "Pooh", "Tig
www.eeworm.com/read/204876/15332198
txt 新建 文本文档 (5).txt
小波模极大值与边缘提取
不做小波很久,陆续接到网友的很多询问,不少信件关于这个话题。本不想花功夫写程序,因为毕竟研究方向是计算电磁学,然对小波的好奇仍是一种抗拒不了的力量。再加上网友的一遍遍不厌其烦的请教,我也就利用半天时间,将这一话题做了一个程序,拿出来分享。
1。什么是模极大值?一般信号的主要信息,由拐点(二阶导数为零的点)确定,而由于噪声的影响,直接求拐点显然困难。于是,我们求一阶导 ...