代码搜索：Bandwidth
找到约 1,693 项符合「Bandwidth」的源代码
代码结果 1,693
www.eeworm.com/read/277960/10590660
m exa4_7.m
% exa4-7_lp2bs for example4-7
% chebshev I analog lowpass filter prototype to bandstop filter
clear all;
N=9;
Rp=3;
wl=200*pi;
wh=1000*pi;
% Chebyshev analog lowpass filter prototype
[z,p,k
www.eeworm.com/read/422591/10627072
rd ks-package.rd
\name{ks}
\alias{ks}
\docType{package}
\title{
ks
}
\description{
Kernel density estimation and kernel discriminant analysis for
data from 1- to 6-dimensions, with display functions.
}
\details
www.eeworm.com/read/277084/10670135
cpp newmat4.cpp
//$$ newmat4.cpp Constructors, ReSize, basic utilities
// Copyright (C) 1991,2,3,4,8,9: R B Davies
#include "include.h"
#include "newmat.h"
#include "newmatrc.h"
#ifdef use_namespac
www.eeworm.com/read/420197/10811071
m calculatepllcoef.m
function [c1,c2] = calculatePLLCoef(zeta,bandwidth);
% Calculates coefficients used in the carrier tracking loop(PLL)
% zeta : tamping factor
% bandwidth : nosie bandwidth
tUpd = 0.001; %integrat
www.eeworm.com/read/467324/7009731
m ip_08_02.m
% MATLAB script for Illustrative Problem 2, Chapter 8.
echo on
pn0_db=[-20:0.1:30];
pn0=10.^(pn0_db./10);
capacity=3000.*log2(1+pn0/3000);
pause % Press a key to see a plot of channel capacity vs
www.eeworm.com/read/254517/7072427
m binomialxfrmrbw.m
% BINOMIALXFRMRBW Calculate the bandwidth of a binomial transformer
%
% [BW] = BINOMIALXFRMRBW (Zl, Z0, N, GammaM) calcultaes the relative bandwidth
% of an N section binomial trans
www.eeworm.com/read/463748/7176042
m ip_08_02.m
% MATLAB script for Illustrative Problem 8.2.
echo on
pn0_db=[-20:0.1:30];
pn0=10.^(pn0_db./10);
capacity=3000.*log2(1+pn0/3000);
pause % Press a key to see a plot of channel capacity vs. P/N0.
www.eeworm.com/read/462321/7202793
m ip_08_02.m
% MATLAB script for Illustrative Problem 8.2.
echo on
pn0_db=[-20:0.1:30];
pn0=10.^(pn0_db./10);
capacity=3000.*log2(1+pn0/3000);
pause % Press a key to see a plot of channel capacity vs. P/N0.
www.eeworm.com/read/456354/7351391
m ip_08_02.m
% MATLAB script for Illustrative Problem 2, Chapter 8.
echo on
pn0_db=[-20:0.1:30];
pn0=10.^(pn0_db./10);
capacity=3000.*log2(1+pn0/3000);
pause % Press a key to see a plot of channel capacity vs. P/N