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load gas price2 [h,sig,ci] = ttest( price2 ,115)

t=78:87; x=[23.8,27.6,31.6,32.4,33.7,34.9,43.2,52.8,63.8,73.4]; y=[41.4,51.8,61.7,67.9,68.7,77.5,95.9,137.4,155.0,175.0]; save data t x y

data=[78 79 80 81 82 83 84 85 86 87; 23.8,27.6,31.6,32.4,33.7,34.9,43.2,52.8,63.8,73.4; 41.4,51.8,61.7,67.9,68.7,77.5,95.9,137.4,155.0,175.0]; save data1 data;

x=-6:0.01:6; y=normpdf(x); z=normpdf(x,0,2); plot(x,y,x,z)

load dj normplot(x)

u=norminv(0.975)

x1=[459 362 624 542 509 584 433 748 815 505]; x2=[612 452 434 982 640 742 565 706 593 680]; x3=[926 653 164 487 734 608 428 1153 593 844]; x4=[527 552 513 781 474

c=[-0.4 -0.28 -0.32 -0.72 -0.64 -0.6]; A=[0.01 0.01 0.01 0.03 0.03 0.03;0.02 0 0 0.05 0 0;0 0.02 0 0 0.05 0;0 0 0.03 0 0 0.08]; b=[850;700;100;900]; Aeq=[]; beq=[]; vlb=[0

%首先输入下列系数： f = [13 9 10 11 12 8]; A = [0.4 1.1 1 0 0 0 0 0 0 0.5 1.2 1.3]; b = [800; 900]; Aeq=[1 0 0 1 0 0 0 1 0 0 1 0 0 0 1 0 0 1]; beq=[400 600 500]; vlb = zeros(6,1); vu

c=[6 3 4]; A=[0 1 0]; b=[50]; Aeq=[1 1 1]; beq=[120]; vlb=[30,0,20]; vub=[]; [x,fval]=linprog(c,A,b,Aeq,beq,vlb,vub)