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找到约 10,000 项符合 7 的代码

xt7-7.cpp

#include using namespace std; #define NULL 0 struct student {long num; float score; student *next; }; int n; void print(student *head) {student *p;

chap7_7.mdl

Model { Name "chap7_7" Version 3.00 SimParamPage "Solver" SampleTimeColors off InvariantConstants off WideVectorLines off ShowLineWidths off ShowPortDataTypes

例7-7.txt

import java.util.*; class Student { String name ; int number; float score; Student(String name,int number,float score) { this.name=name; this.number=number;

chap7_7.mdl

Model { Name "chap7_7" Version 3.00 SimParamPage "Solver" SampleTimeColors off InvariantConstants off WideVectorLines off ShowLineWidths off ShowPortDataTypes

ex7_7.m

a=[1,2,-2;1,1,1;2,2,1]; b=[9;7;6]; [x,n]=jacobi(a,b,[0;0;0]) [x,n]=gauseidel(a,b,[0;0;0])

ch7_7.cpp

//********************* //** ch7_7.cpp ** //********************* #include int maximum(int[][4],int,int); void main() { int sg[3][4]={{68,77,73,86},

samp7_7.m

%Samp7_7 clf;N=1000;Fs=1000; %数据总数和采样频率 fc=200; n=[0:N-1];t=n/Fs; %时间序列 f1=50;f2=250; x=sin(2*pi*f1*t)+sin(2*pi*f2*t); %输入信号 b=fir1(40,fc*2/Fs); %设计40阶的低通滤波器,归一化截止频率据6-19式

example7_7.m

%首先,创建包含了期望的频率响应的矩阵Hd [f1,f2] = freqspace(21,'meshgrid'); Hd = zeros(21); Hd(7:15,7:15) = 1; Axis([-1 1 –1 1 0 1.2]), colormap(jet(64)) mesh(f1,f2,Hd) %期望的滤波器的频率响应见图7-16 %然后,设计通过此响应的滤波器 h