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找到约 10,000 项符合 7 的代码

ex7_7.m

a=[1,2,-2;1,1,1;2,2,1]; b=[9;7;6]; [x,n]=jacobi(a,b,[0;0;0]) [x,n]=gauseidel(a,b,[0;0;0])

demo7_7.cpp

// DEMO7_7.CPP 16-bit surface to surface blitter demo // INCLUDES /////////////////////////////////////////////// #define WIN32_LEAN_AND_MEAN // just say no to MFC #define INITGUID #inclu

example7_7.m

%首先,创建包含了期望的频率响应的矩阵Hd [f1,f2] = freqspace(21,'meshgrid'); Hd = zeros(21); Hd(7:15,7:15) = 1; Axis([-1 1 –1 1 0 1.2]), colormap(jet(64)) mesh(f1,f2,Hd) %期望的滤波器的频率响应见图7-16 %然后,设计通过此响应的滤波器 h

example7_7.m

%装载并图示原始图像 load gatlin2; subplot(2,2,1); image(X); colormap(map); title('原始图像'); axis square; %============================== %生成含噪图像并图示 init=2055615866; randn('seed',init); X1=X+10*randn(s

ex7_7.m

a=[1,2,-2;1,1,1;2,2,1]; b=[9;7;6]; [x,n]=jacobi(a,b,[0;0;0]) [x,n]=gauseidel(a,b,[0;0;0])

plot_7_7.m

% make figure 7.7 Z2=zeros(4,491); load run2 tail=[0 5 8 66]; z=sum(real(E).^2,2); [y ind]=sort(z); newE=E(ind,:); for i=1:4, Z2(i,:)=sum((real(newE(1:400-tail(i),:)).^2))/(400-tail(i));

xt7-7.cpp

#include using namespace std; #define NULL 0 struct student {long num; float score; student *next; }; int n; void print(student *head) {student *p;