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3.16.c
<mark>3</mark>.16② 假设如题<mark>3</mark>.1所述火车调度站的入口处有n节
硬席或软席车厢（分别以H和S表示）等待调度，试编
写算法， 输出对这n节车厢进行调度的操作（即入栈
或出栈操作）序列，以使所有的软席车厢都被调整到
硬席车厢之前。
实现下列函数：
void SwitchYard(SqList train, char *s);
/* 顺序表train表示列车，其元素取值H或S ...
3.19.c
◆<mark>3</mark>.19④ 假设一个算术表达式中可以包含三种括号：圆括号"(" 和
")"，方括号"["和"]"和花括号"{"和"}"，且这三种括号可按任意的
次序嵌套使用（如：…[…{…}…[…]…]…[…]…(…)…）。编写判别给定表达
式中所含括号是否正确配对出现的算法(已知表达式已存入数据元素
为字符的顺序表中)。
实现下列函数：
Status MatchCheck(SqList e ...
gap0.out
3.2
gap2.out
3.6896
berofdmda.dat
3.000000 3.706250e-002 1.000000e+000 1000 150
3.000000 3.692949e-002 1.000000e+000 1000 150
3.000000 3.735577e-002 1.000000e+000 1000 150
金属.dat
"3","*******","*******","13","*******","*******","31","*******","*******","","*******","*******","","*******","*******","","*******","*******","","*******","*******","","*******","*******","","*******
data_q_train_word_2_i0_256.txt
3.0000000e+000 -3.0000000e+000 -3.0000000e+000 -3.0000000e+000 3.0000000e+000 -3.0000000e+000 3.0000000e+000 -3.0000000e+000 -3.0000000e+000 -3.0000000e+000 3.0000000e+000 3.0000000e+000 -3.0000000e+0
data_i_train_word_2_i0_256.txt
3.0000000e+000 -3.0000000e+000 3.0000000e+000 3.0000000e+000 3.0000000e+000 -3.0000000e+000 -3.0000000e+000 3.0000000e+000 -3.0000000e+000 3.0000000e+000 3.0000000e+000 3.0000000e+000 -3.0000000e+000
data_q_train_word_2_i0_256.txt
3.0000000e+000 -3.0000000e+000 -3.0000000e+000 -3.0000000e+000 3.0000000e+000 -3.0000000e+000 3.0000000e+000 -3.0000000e+000 -3.0000000e+000 -3.0000000e+000 3.0000000e+000 3.0000000e+000 -3.0000000e+0
data_i_train_word_2_i0_256.txt
3.0000000e+000 -3.0000000e+000 3.0000000e+000 3.0000000e+000 3.0000000e+000 -3.0000000e+000 -3.0000000e+000 3.0000000e+000 -3.0000000e+000 3.0000000e+000 3.0000000e+000 3.0000000e+000 -3.0000000e+000