Insurance A Vehicle Vehicle Insured In Accident Vehicle Inspected Online fprms goto insurer Claim Approved Vehicle Repaired Insurer Pays All data should be saved to the data base
标签： Vehicle Insurance Inspected Accident
上传时间： 2017-09-01
上传用户：xz85592677
实验源代码 //Warshall.cpp #include<stdio.h> void warshall(int k,int n) { int i , j, t; int temp[20][20]; for(int a=0;a<k;a++) { printf("请输入矩阵第%d 行元素:",a); for(int b=0;b<n;b++) { scanf ("%d",&temp[a][b]); } } for(i=0;i<k;i++){ for( j=0;j<k;j++){ if(temp[ j][i]==1) { for(t=0;t<n;t++) { temp[ j][t]=temp[i][t]||temp[ j][t]; } } } } printf("可传递闭包关系矩阵是:\n"); for(i=0;i<k;i++) { for( j=0;j<n;j++) { printf("%d", temp[i][ j]); } printf("\n"); } } void main() { printf("利用 Warshall 算法求二元关系的可传递闭包\n"); void warshall(int,int); int k , n; printf("请输入矩阵的行数 i: "); scanf("%d",&k); 四川大学实验报告 printf("请输入矩阵的列数 j: "); scanf("%d",&n); warshall(k,n); }
上传时间： 2016-06-27
上传用户：梁雪文以
#include "iostream" using namespace std; class Matrix { private: double** A; //矩阵A double *b; //向量b public: int size; Matrix(int ); ~Matrix(); friend double* Dooli(Matrix& ); void Input(); void Disp(); }; Matrix::Matrix(int x) { size=x; //为向量b分配空间并初始化为0 b=new double [x]; for(int j=0;j<x;j++) b[j]=0; //为向量A分配空间并初始化为0 A=new double* [x]; for(int i=0;i<x;i++) A[i]=new double [x]; for(int m=0;m<x;m++) for(int n=0;n<x;n++) A[m][n]=0; } Matrix::~Matrix() { cout<<"正在析构中~~~~"<<endl; delete b; for(int i=0;i<size;i++) delete A[i]; delete A; } void Matrix::Disp() { for(int i=0;i<size;i++) { for(int j=0;j<size;j++) cout<<A[i][j]<<" "; cout<<endl; } } void Matrix::Input() { cout<<"请输入A:"<<endl; for(int i=0;i<size;i++) for(int j=0;j<size;j++){ cout<<"第"<<i+1<<"行"<<"第"<<j+1<<"列:"<<endl; cin>>A[i][j]; } cout<<"请输入b:"<<endl; for(int j=0;j<size;j++){ cout<<"第"<<j+1<<"个:"<<endl; cin>>b[j]; } } double* Dooli(Matrix& A) { double *Xn=new double [A.size]; Matrix L(A.size),U(A.size); //分别求得U，L的第一行与第一列 for(int i=0;i<A.size;i++) U.A[0][i]=A.A[0][i]; for(int j=1;j<A.size;j++) L.A[j][0]=A.A[j][0]/U.A[0][0]; //分别求得U，L的第r行，第r列 double temp1=0,temp2=0; for(int r=1;r<A.size;r++){ //U for(int i=r;i<A.size;i++){ for(int k=0;k<r-1;k++) temp1=temp1+L.A[r][k]*U.A[k][i]; U.A[r][i]=A.A[r][i]-temp1; } //L for(int i=r+1;i<A.size;i++){ for(int k=0;k<r-1;k++) temp2=temp2+L.A[i][k]*U.A[k][r]; L.A[i][r]=(A.A[i][r]-temp2)/U.A[r][r]; } } cout<<"计算U得:"<<endl; U.Disp(); cout<<"计算L的:"<<endl; L.Disp(); double *Y=new double [A.size]; Y[0]=A.b[0]; for(int i=1;i<A.size;i++ ){ double temp3=0; for(int k=0;k<i-1;k++) temp3=temp3+L.A[i][k]*Y[k]; Y[i]=A.b[i]-temp3; } Xn[A.size-1]=Y[A.size-1]/U.A[A.size-1][A.size-1]; for(int i=A.size-1;i>=0;i--){ double temp4=0; for(int k=i+1;k<A.size;k++) temp4=temp4+U.A[i][k]*Xn[k]; Xn[i]=(Y[i]-temp4)/U.A[i][i]; } return Xn; } int main() { Matrix B(4); B.Input(); double *X; X=Dooli(B); cout<<"~~~~解得:"<<endl; for(int i=0;i<B.size;i++) cout<<"X["<<i<<"]:"<<X[i]<<" "; cout<<endl<<"呵呵呵呵呵"; return 0; }
标签： 道理特分解法
上传时间： 2018-05-20
上传用户：Aa123456789
Mobile communication devices like smart phones or tablet PCs enable us to consume information at every location and at every time. The rapid development of new applications and new services and the demand to access data in real time create an increasing throughput demand. The data have to be transmitted reliably to ensure the desired quality of service. Furthermore, an improved utilization of the bandwidth is desired to reduce the cost of transmission.
标签： Architectures Processing Baseband Signal for
上传时间： 2020-05-26
上传用户：shancjb
Long-TermEvolution(LTE)isarguablyoneofthemostimportantstepsinthecurrentphaseof the development of modern mobile communications. It provides a suitable base for enhanced services due to increased data throughput and lower latency figures, and also gives extra impetus to the modernization of telecom architectures. The decision to leave the circuit- switched domainoutofthescope ofLTE/SAEsystem standardization might soundradical but itindicatesthatthetelecomworldisgoingstronglyfortheall-IPconcept----andthedeployment of LTE/SAE is concrete evidence of this global trend.
标签： Deployment Handbook LTE-SAE The
上传时间： 2020-06-01
上传用户：shancjb
This book intends to prepare you to define Unified Communications (UC) for yourself and then get it to work for you. Each vendor pulls together from its available products a package of features related to voice, data, messaging, and image communications. That’s UC for one vendor, but it’s unlikely to match exactly the UC from another vendor. You need a detailed specification to know what you’ll see installed.
标签： Communications Unified VoIP and
上传时间： 2020-06-01
上传用户：shancjb
Identification is pervasive nowadays in daily life due to many complicated activities such as bank and library card reading, asset tracking, toll collecting, restricted access to sensitive data and procedures and target identification. This kind of task can be realized by passwords, bio- metric data such as fingerprints, barcode, optical character recognition, smart cards and radar. Radiofrequencyidentification(RFID)isatechniquetoidentifyobjectsbyusingradiosystems. It is a contactless, usually short distance, wireless data transmission and reception technique for identification of objects. An RFID system consists of two components: the tag (also called transponder) and the reader (also called interrogator).
标签： Processing Digital Signal RFID for
上传时间： 2020-06-08
上传用户：shancjb
高清电子书-C++ Primer Plus, 第6版英文版 1438页Learning C++ is an adventure of discovery, particularly because the language accommodates several programming paradigms, including object-oriented programming, generic programming, and the traditional procedural programming.The fifth edition of this book described the language as set forth in the ISO C++ standards, informally known as C++99 and C++03, or, sometimes as C++99/03. (The 2003 version was largely a technical correction to the 1999 standard and didn’t add any new features.) Since then, C++ continues to evolve.As this book is written, the international C++ Standards Committee has just approved a new version of the standard.This standard had the informal name of C++0x while in development, and now it will be known as C++11. Most contemporary compilers support C++99/03 quite well, and most of the examples in this book comply with that standard. But many features of the new standard already have appeared in some implementations, and this edition of C++ Primer Plus explores these new features. C++ Primer Plus discusses the basic C language and presents C++ features, making this book self-contained. It presents C++ fundamentals and illustrates them with short, to-the-point programs that are easy to copy and experiment with.You learn about input/output (I/O), how to make programs perform repetitive tasks and make choices, the many ways to handle data, and how to use functions.You learn about the many features C++ has added to C, including the followi
标签： C++
上传时间： 2022-02-19
上传用户：trh505
说明： STM8S单片机驱动CC1101 433无线模块 实现发送数据和接收数据。(STM8S single-chip microcomputer drives CC1101 433 wireless module to transmit data and receive data)
上传时间： 2022-05-16
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In this presentation, we will look at what the Serial Peripheral Interface, otherwise known as the SPI, is. and how it is used to communicate data to and from the PICmicro microcontroller.SPl is frequently used when few 1/O lines are available, but communication between two or more devices must be fast and easy to implement.In this presentation, we will discuss the following topics: We will first cover an Overview of SPI This section of the tutorial will introduce you to SPI and its concepts.Next, we will examine the use of SPI on the PICmicro MCU.The details of how SPI is implemented on a PICmicro device will be examined.Then, a Code Walkthrough will be given.The walkthough will explore code for both an SPI Master and SPI Slave. The example will have the Master generate data for sending to the slave.Finally, there will be a few resources given at the end of the presentation. These resources will allow you to explore in more detail the SPI interface
标签： spi协议
上传时间： 2022-06-20
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