2.[问题描述] 编写递归算法，在二叉树中求位于先序序列中第K个位置的结点 [输入] 按照先序序列的顺序输入该结点的内容。其输入abd eh cf i g 。输入要求的位置 [输出] 若二叉树不空，按先序序列输出，求出所求位置的结点 [存储结构] 采用二叉表存储 [算法的基本思想] 采用递归方法建立和遍历二叉树。首先建立二叉树的根结点，然后建立其左右子树，直到空子树为止，先序遍历二叉树时，先遍厉左子树，后遍厉右子树，最后访问根结点并计算出二叉树中叶子结点的数目和第K个位置的结点 #include<stdio.h> #include<malloc.h> struct node{ char info struct node*llink,*rlink } typedef struct node NODE
上传时间： 2014-01-13
上传用户：zm7516678
C语言内存管理源码，一个介绍malloc实现的源码。嵌入式系统里面可以参考，以了解如何减少内存碎片的问题！
上传时间： 2016-01-26
上传用户：miaochun888
一个类STL的多平台可移植的算法容器库,主要用于嵌入式系统编程时的内存管理等方面，尤其是缺少支持malloc 和free的情况下。
上传时间： 2016-04-17
上传用户：tfyt
编写一个C程序，用char *malloc(unsigned size)函数向系统申请一次内存空间（如size=1000，单位为字节），用循环首次适应法 addr = (char *)lmalloc(unsigned size) 和 lfree(unsigned size,char * addr)模拟可变分区内存管理，实现对该内存区的分配和释放管理。
上传时间： 2016-06-18
上传用户：fredguo
内存越界操作检测工具，既可以在windows下使用，也可以在linux下使用，作为动态库链入可执行档即可使用里面的malloc
上传时间： 2013-12-23
上传用户：litianchu
在程序中输入数组大小n，通过动态分配内存函数malloc产生一个整型数组，接着输入该数组的n个元数，并使用一个函数对组数进行排序（从小到大，要求用选择法实现）
上传时间： 2013-12-21
上传用户：恋天使569
小型内存分配模块,用通用循环双向链表实现，改程序模拟系统malloc
上传时间： 2014-01-11
上传用户：libinxny
两个链表的交集 #include<stdio.h> #include<stdlib.h> typedef struct Node{ int data; struct Node *next; }Node; void initpointer(struct Node *p){ p=NULL; } int printlist(struct Node* head){ int flag=1; head=head->next; /* 因为标记1的地方你用了头结点，所以第一个数据域无效，应该从下一个头元结点开始 */ if(head==NULL) printf("NULL\n"); else { while(head!=NULL) { if(flag==1) { printf("%d",head->data); flag=0; } else { printf(" %d",head->data); } head=head->next; } printf("\n"); } return 0; } struct Node *creatlist(struct Node *head) { int n; struct Node *p1=(struct Node *)malloc(sizeof(struct Node)); p1->next=NULL; while(scanf("%d",&n),n!=-1) { struct Node *pnode=(struct Node *)malloc(sizeof(struct Node)); pnode->next=NULL; pnode->data=n; if(head==NULL) head=pnode; p1->next=pnode; p1=pnode; } return head; } struct Node *Intersect(struct Node *head1, struct Node *head2) { struct Node *p1=head1,*p2=head2;/*我这里没有用头指针和头结点，这里是首元结点head1里面就是第一个数据，一定要理解什么事头指针， 头结点，和首元结点 具体你一定要看这个博客：http://blog.sina.com.cn/s/blog_71e7e6fb0101lipz.html*/ struct Node *head,*p,*q; head = (struct Node *)malloc(sizeof(struct Node)); head->next = NULL; p = head; while( (p1!=NULL)&&(p2!=NULL) ) { if (p1->data == p2->data) { q = (struct Node *)malloc(sizeof(struct Node)); q->data = p1->data; q->next = NULL; p->next = q;//我可以认为你这里用了头结点，也就是说第一个数据域无效 **标记1** p = q; p1 = p1->next; p2 = p2->next; } else if (p1->data < p2->data) { p1 = p1->next; } else { p2 = p2->next; } } return head; } int main() { struct Node *head=NULL,*headt=NULL,*t; //initpointer(head);//这里的函数相当于head=NULL; // initpointer(headt);//上面已经写了headt=NULL那么这里可以不用调用这个函数 head=creatlist(head); headt=creatlist(headt); t=Intersect(head,headt); printlist(t); }
标签： c语言编程
上传时间： 2015-04-27
上传用户：coco2017co
#include <stdlib.h> #include<stdio.h> #include <malloc.h> #define stack_init_size 100 #define stackincrement 10 typedef struct sqstack { int *base; int *top; int stacksize; } sqstack; int StackInit(sqstack *s) { s->base=(int *)malloc(stack_init_size *sizeof(int)); if(!s->base) return 0; s->top=s->base; s->stacksize=stack_init_size; return 1; } int Push(sqstack *s,int e) { if(s->top-s->base>=s->stacksize) { s->base=(int *)realloc(s->base,(s->stacksize+stackincrement)*sizeof(int)); if(!s->base) return 0; s->top=s->base+s->stacksize; s->stacksize+=stackincrement; } *(s->top++)=e; return e; } int Pop(sqstack *s,int e) { if(s->top==s->base) return 0; e=*--s->top; return e; } int stackempty(sqstack *s) { if(s->top==s->base) { return 1; } else { return 0; } } int conversion(sqstack *s) { int n,e=0,flag=0; printf("输入要转化的十进制数：\n"); scanf("%d",&n); printf("要转化为多少进制：\n"); scanf("%d",&flag); printf("将十进制数%d 转化为%d 进制是：\n",n,flag); while(n) { Push(s,n%flag); n=n/flag; } while(!stackempty(s)) { e=Pop(s,e); switch(e) { case 10: printf("A"); break; case 11: printf("B"); break; case 12: printf("C"); break; case 13: printf("D"); break; case 14: printf("E"); break; case 15: printf("F"); break; default: printf("%d",e); } } printf("\n"); return 0; } int main() { sqstack s; StackInit(&s); conversion(&s); return 0; }
上传时间： 2016-12-08
上传用户：爱你198
#include <malloc.h> #include <stdio.h> #include <stdlib.h> #include <string.h> #define NULL 0 #define MaxSize 30 typedef struct athletestruct /*运动员*/ { char name[20]; int score; /*分数*/ int range; /**/ int item; /*项目*/ }ATH; typedef struct schoolstruct /*学校*/ { int count; /*编号*/ int serial; /**/ int menscore; /*男选手分数*/ int womenscore; /*女选手分数*/ int totalscore; /*总分*/ ATH athlete[MaxSize]; /**/ struct schoolstruct *next; }SCH; int nsc,msp,wsp; int ntsp; int i,j; int overgame; int serial,range; int n; SCH *head,*pfirst,*psecond; int *phead=NULL,*pafirst=NULL,*pasecond=NULL; void create(); void input () { char answer; head = (SCH *)malloc(sizeof(SCH)); /**/ head->next = NULL; pfirst = head; answer = 'y'; while ( answer == 'y' ) { Is_Game_DoMain: printf("\nGET Top 5 when odd\nGET Top 3 when even"); printf("\n输入运动项目序号 (x<=%d):",ntsp); scanf("%d",pafirst); overgame = *pafirst; if ( pafirst != phead ) { for ( pasecond = phead ; pasecond < pafirst ; pasecond ++ ) { if ( overgame == *pasecond ) { printf("\n这个项目已经存在请选择其他的数字\n"); goto Is_Game_DoMain; } } } pafirst = pafirst + 1; if ( overgame > ntsp ) { printf("\n项目不存在"); printf("\n请重新输入"); goto Is_Game_DoMain; } switch ( overgame%2 ) { case 0: n = 3;break; case 1: n = 5;break; } for ( i = 1 ; i <= n ; i++ ) { Is_Serial_DoMain: printf("\n输入序号 of the NO.%d (0<x<=%d): ",i,nsc); scanf("%d",&serial); if ( serial > nsc ) { printf("\n超过学校数目,请重新输入"); goto Is_Serial_DoMain; } if ( head->next == NULL ) { create(); } psecond = head->next ; while ( psecond != NULL ) { if ( psecond->serial == serial ) { pfirst = psecond; pfirst->count = pfirst->count + 1; goto Store_Data; } else { psecond = psecond->next; } } create(); Store_Data: pfirst->athlete[pfirst->count].item = overgame; pfirst->athlete[pfirst->count].range = i; pfirst->serial = serial; printf("Input name:) : "); scanf("%s",pfirst->athlete[pfirst->count].name); } printf("\n继续输入运动项目(y&n)？"); answer = getchar(); printf("\n"); } } void calculate() /**/ { pfirst = head->next; while ( pfirst->next != NULL ) { for (i=1;i<=pfirst->count;i++) { if ( pfirst->athlete[i].item % 2 == 0 ) { switch (pfirst->athlete[i].range) { case 1:pfirst->athlete[i].score = 5;break; case 2:pfirst->athlete[i].score = 3;break; case 3:pfirst->athlete[i].score = 2;break; } } else { switch (pfirst->athlete[i].range) { case 1:pfirst->athlete[i].score = 7;break; case 2:pfirst->athlete[i].score = 5;break; case 3:pfirst->athlete[i].score = 3;break; case 4:pfirst->athlete[i].score = 2;break; case 5:pfirst->athlete[i].score = 1;break; } } if ( pfirst->athlete[i].item <=msp ) { pfirst->menscore = pfirst->menscore + pfirst->athlete[i].score; } else { pfirst->womenscore = pfirst->womenscore + pfirst->athlete[i].score; } } pfirst->totalscore = pfirst->menscore + pfirst->womenscore; pfirst = pfirst->next; } } void output() { pfirst = head->next; psecond = head->next; while ( pfirst->next != NULL ) { // clrscr(); printf("\n第%d号学校的结果成绩:",pfirst->serial); printf("\n\n项目的数目\t学校的名字\t分数"); for (i=1;i<=ntsp;i++) { for (j=1;j<=pfirst->count;j++) { if ( pfirst->athlete[j].item == i ) { printf("\n %d\t\t\t\t\t\t%s\n %d",i,pfirst->athlete[j].name,pfirst->athlete[j].score);break; } } } printf("\n\n\n\t\t\t\t\t\t按任意建 进入下一页"); getchar(); pfirst = pfirst->next; } // clrscr(); printf("\n运动会结果:\n\n学校编号\t男运动员成绩\t女运动员成绩\t总分"); pfirst = head->next; while ( pfirst->next != NULL ) { printf("\n %d\t\t %d\t\t %d\t\t %d",pfirst->serial,pfirst->menscore,pfirst->womenscore,pfirst->totalscore); pfirst = pfirst->next; } printf("\n\n\n\t\t\t\t\t\t\t按任意建结束"); getchar(); } void create() { pfirst = (struct schoolstruct *)malloc(sizeof(struct schoolstruct)); pfirst->next = head->next ; head->next = pfirst ; pfirst->count = 1; pfirst->menscore = 0; pfirst->womenscore = 0; pfirst->totalscore = 0; } void Save() {FILE *fp; if((fp = fopen("school.dat","wb"))==NULL) {printf("can't open school.dat\n"); fclose(fp); return; } fwrite(pfirst,sizeof(SCH),10,fp); fclose(fp); printf("文件已经成功保存\n"); } void main() { system("cls"); printf("\n\t\t\t 运动会分数统计\n"); printf("输入学校数目 (x>= 5):"); scanf("%d",&nsc); printf("输入男选手的项目(x<=20):"); scanf("%d",&msp); printf("输入女选手项目(<=20):"); scanf("%d",&wsp); ntsp = msp + wsp; phead = (int *)calloc(ntsp,sizeof(int)); pafirst = phead; pasecond = phead; input(); calculate(); output(); Save(); }
标签： 源代码
上传时间： 2016-12-28
上传用户：150501
