- XCS for Dynamic Environments + Continuous versions of XCS + Test problem: real multiplexer + Experiments: XCS is explored in dynamic environments with different magnitudes of change to the underlying concepts. +Reference papers: H.H. Dam, H.A. Abbass, C.J. Lokan, Evolutionary Online Data Mining – an Investigation in a Dynamic Environment. 2005, accepted for a book chapter in Springer Series on Studies in Computational Intelligence H.H. Dam, H.A. Abbass, C.J. Lokan, Be Real! XCS with Continuous-Valued Inputs. IWLCS 2005, (International Workshop on Learning Classifier Systems). Washington DC, June 2005.
标签： Environments multiplexer Continuous XCS
上传时间： 2015-07-04
上传用户：Avoid98
加密算法 Test Driver for Crypto++, a C++ Class Library of Cryptographic Primitives: - To generate an RSA key cryptest g - To encrypt and decrypt a string using RSA cryptest r - To calculate MD5, SHS, and RIPEMD-160 message digests: cryptest m file - To encrypt and decrypt a string using DES-EDE in CBC mode: cryptest t - To encrypt or decrypt a file cryptest e|d input output - To share a file into shadows: cryptest s <pieces> <pieces-needed> file (make sure file has no extension, if you re running this under DOS) - To reconstruct a file from shadows: cryptest j output file1 file2 [....] - To gzip a file: cryptest z <compression-level> input output - To gunzip a file: cryptest u input output - To run validation tests: cryptest v - To run benchmarks: cryptest b [time for each benchmark in seconds]
标签： Cryptographic Primitives generate Library
上传时间： 2015-07-16
上传用户：wqxstar
BISON-C: A one-dimensional transport and burnup calculation code with consideration of actinides and fission products Auteur(s) / Author(s) CETNAR J. (1) GRONEK P. (1) Affiliation(s) du ou des auteurs / Author(s) Affiliation(s) (1) University of Mining and Metallurgy, Faculty of Physics and Nuclear Techniques, 30 059 Cracow, POLOGNE
标签： one-dimensional consideration calculation and
上传时间： 2015-07-17
上传用户：royzhangsz
BISON-C: A one-dimensional transport and burnup calculation code with consideration of actinides and fission products Auteur(s) / Author(s) CETNAR J. (1) GRONEK P. (1) Affiliation(s) du ou des auteurs / Author(s) Affiliation(s) (1) University of Mining and Metallurgy, Faculty of Physics and Nuclear Techniques, 30 059 Cracow, POLOGNE
标签： one-dimensional consideration calculation and
上传时间： 2015-07-17
上传用户：wendy15
1)Learn more about the capabilities in Quartus: 2)Learn to use different design entry techniques 2)Design entry methods available within Quartus Text editor,Block diagram/schematic file editor, Quartus interface with design entry/synthesis tools from Exemplar, Synopsys, Synplicity and Viewlogic
标签： Learn capabilities techniques different
上传时间： 2014-01-18
上传用户：yxgi5
JavaTV Program source code Need to play Windows Media files and streams, mpeg4 video or DVDs in java? Access WDM capture devices? Control a firewire DVCam? Then maybe this can help you. dsj is an ongoing project to provide a java wrapper around Microsoft s DirectShow API. It offers a set of high level classes that give java easy access to functionality widely missed by java programmers and also lets you dive deeper into the interiors of Windows core api for 2D media. On the java side dsj tries to keep things open as possible - you may use it standalone or let it feed data into JMF or other APIs.
标签： Program Windows streams JavaTV
上传时间： 2013-12-17
上传用户：TF2015
％ 该Matlab程序基于牛顿－拉夫逊算法，用于计算已知导纳矩阵、PQ节点、PV节点、平衡节点(UA)的电力网络潮流 ％ U - 各节点母线电压 S - 各节点注入功率 S_net - 电力网络总损耗 ％ PQ_P - 实算PQ节点注入有功功率 PQ_Q - 实算PQ节点注入无功功率 ％ delt_PQ_P - 实算PQ节点有功功率修正值 delt_PQ_Q －实算PQ节点无功功率修正值 ％ delt_UA_P - 实平衡节点有功功率修正值 delt_U_2 - 实平衡节点电压平方修正值 ％ delt_PQV - 实算P Q U^2修正值 J - 雅可比矩阵 ％ e - 电压实部 f - 电压虚部 delt_ef - 电压实部与虚部修正值
上传时间： 2015-07-23
上传用户：王楚楚
给定n 个整数a ,a , ,an 1 2 组成的序列， a n i | |£ ，1 £ i £ n。如果对于i £ j ，有 0 = å = j k i k a ，则称序列区间i i j a , a , , a +1 为一个零和区间，相应的区间长度为j-i+1。
上传时间： 2015-07-23
上传用户：zhangzhenyu
给定n 个整数a ,a , ,an 1 2 组成的序列， a n i | |£ ，1 £ i £ n。如果对于i £ j ，有 0 = å = j k i k a ，则称序列区间i i j a , a , , a +1 为一个零和区间，相应的区间长度为j-i+1。
上传时间： 2013-12-21
上传用户：偷心的海盗
CrossPointNo=53 ％％％输入图中节点的总数目 对已知的边进行赋值，注意：有向图的Cost(i,j)=Cost(j,i)
标签： CrossPointNo 53 输入 节点
上传时间： 2015-08-08
上传用户：天诚24
