This document provides practical, common guidelines for incorporating PCI Express interconnect layouts onto Printed Circuit Boards (PCB) ranging from 4-layer desktop baseboard designs to 10- layer or more server baseboard designs. Guidelines and constraints in this document are intended for use on both baseboard and add-in card PCB designs. This includes interconnects between PCI Express devices located on the same baseboard (chip-to-chip routing) and interconnects between a PCI Express device located “down” on the baseboard and a device located “up” on an add-in card attached through a connector. This document is intended to cover all major components of the physical interconnect including design guidelines for the PCB traces, vias and AC coupling capacitors, as well as add-in card edge-finger and connector considerations. The intent of the guidelines and examples is to help ensure that good high-speed signal design practices are used and that the timing/jitter and loss/attenuation budgets can also be met from end-to-end across the PCI Express interconnect. However, while general physical guidelines and suggestions are given, they may not necessarily guarantee adequate performance of the interconnect for all layouts and implementations. Therefore, designers should consider modeling and simulation of the interconnect in order to ensure compliance to all applicable specifications. The document is composed of two main sections. The first section provides an overview of general topology and interconnect guidelines. The second section concentrates on physical layout constraints where bulleted items at the beginning of a topic highlight important constraints, while the narrative that follows offers additional insight.
上传时间： 2013-10-15
上传用户：busterman
特点(FEATURES) 精确度0.1%满刻度 (Accuracy 0.1%F.S.) 可作各式数学演算式功能如:A+B/A-B/AxB/A/B/A&B(Hi or Lo)/|A| (Math functioA+B/A-B/AxB/A/B/A&B(Hi&Lo)/|A|/etc.....) 16 BIT 类比输出功能(16 bit DAC isolating analog output function) 输入/输出1/输出2绝缘耐压2仟伏特/1分钟(Dielectric strength 2KVac/1min. (input/output1/output2/power)) 宽范围交直流两用电源设计(Wide input range for auxiliary power) 尺寸小,稳定性高(Dimension small and High stability)
上传时间： 2013-11-24
上传用户：541657925
Abstract: A resistive feedback network is often used to set the output voltage of a power supply. A mechanical potentiometer (pot)conveniently solves the problem of adjusting a power supply. For easier automatic calibration, a mechanical pot can be replaced witha digital pot. This application note presents a calibration solution that uses a digital pot, because digipots are smaller, do not movewith age or vibration, and can be recalibrated remotely. This proposed solution reduces the susceptibility of the system to thetolerance of the digital pot's end-to-end resistance, making the solution optimal fordesigners. This application note also explainssome of the equations required to calculate the resistor chain values and to use a digital pot in this way. A spreadsheet withstandard reisistor values is available for easy calculations.
上传时间： 2013-10-31
上传用户：caiguoqing
/*--------- 8051内核特殊功能寄存器 -------------*/ sfr ACC = 0xE0; //累加器 sfr B = 0xF0; //B 寄存器 sfr PSW = 0xD0; //程序状态字寄存器 sbit CY = PSW^7; //进位标志位 sbit AC = PSW^6; //辅助进位标志位 sbit F0 = PSW^5; //用户标志位0 sbit RS1 = PSW^4; //工作寄存器组选择控制位 sbit RS0 = PSW^3; //工作寄存器组选择控制位 sbit OV = PSW^2; //溢出标志位 sbit F1 = PSW^1; //用户标志位1 sbit P = PSW^0; //奇偶标志位 sfr SP = 0x81; //堆栈指针寄存器 sfr DPL = 0x82; //数据指针0低字节 sfr DPH = 0x83; //数据指针0高字节 /*------------ 系统管理特殊功能寄存器 -------------*/ sfr PCON = 0x87; //电源控制寄存器 sfr AUXR = 0x8E; //辅助寄存器 sfr AUXR1 = 0xA2; //辅助寄存器1 sfr WAKE_CLKO = 0x8F; //时钟输出和唤醒控制寄存器 sfr CLK_DIV = 0x97; //时钟分频控制寄存器 sfr BUS_SPEED = 0xA1; //总线速度控制寄存器 /*----------- 中断控制特殊功能寄存器 --------------*/ sfr IE = 0xA8; //中断允许寄存器 sbit EA = IE^7; //总中断允许位 sbit ELVD = IE^6; //低电压检测中断控制位 8051
上传时间： 2013-10-30
上传用户：yxgi5
在理论分析循环码编码和译码基本原理的基础上，提出了基于单片机系统的(24，16)循环码软件实现编码、译码的方案。仿真结果表明(24，16)循环码能有效地克服来自通讯信道的干扰，保证数据通信的可靠及系统的稳定，使误码率大幅度降低。本论文对(24，16)循环码的研究结果表明，可以有效地降低错误概率和提高系统的吞吐量，实现纠错仅需要在接收端增加有限的存储空间和计算复杂度，具有一定的实用价值。 Abstract: Based on analyzing the theory of encoding and decoding of cyclic code， this paper showed the schemes of encoding and decoding of(24，16)cyclic code by the software and based on microcontroller. Simulation results show that using (24，16) cyclic codes can effectively overcome the interference from communication channel， ensure the reliability and stability of data communication systems， and reduce the bit error rate greatly. The results of this paper show that by using the (24，16) cyclic code， the error rate can be reduced and the system throughput can be improved. Meanwhile， the system only needs to enlarge limited storage space and computation the complexity at the receiving end to realize error correction. Thus the (24，16) cyclic code has a practical value.
上传时间： 2013-11-09
上传用户：gaoliangncepu
摘要: 串行传输技术具有更高的传输速率和更低的设计成本, 已成为业界首选, 被广泛应用于高速通信领域。提出了一种新的高速串行传输接口的设计方案, 改进了Aurora 协议数据帧格式定义的弊端, 并采用高速串行收发器Rocket I/O, 实现数据率为2.5 Gbps的高速串行传输。关键词: 高速串行传输; Rocket I/O; Aurora 协议 为促使FPGA 芯片与串行传输技术更好地结合以满足市场需求, Xilinx 公司适时推出了内嵌高速串行收发器RocketI/O 的Virtex II Pro 系列FPGA 和可升级的小型链路层协议———Aurora 协议。Rocket I/O支持从622 Mbps 至3.125 Gbps的全双工传输速率, 还具有8 B/10 B 编解码、时钟生成及恢复等功能, 可以理想地适用于芯片之间或背板的高速串行数据传输。Aurora 协议是为专有上层协议或行业标准的上层协议提供透明接口的第一款串行互连协议, 可用于高速线性通路之间的点到点串行数据传输, 同时其可扩展的带宽, 为系统设计人员提供了所需要的灵活性[4]。但该协议帧格式的定义存在弊端,会导致系统资源的浪费。本文提出的设计方案可以改进Aurora 协议的固有缺陷,提高系统性能, 实现数据率为2.5 Gbps 的高速串行传输, 具有良好的可行性和广阔的应用前景。
上传时间： 2013-11-06
上传用户：smallfish
摘要: 串行传输技术具有更高的传输速率和更低的设计成本, 已成为业界首选, 被广泛应用于高速通信领域。提出了一种新的高速串行传输接口的设计方案, 改进了Aurora 协议数据帧格式定义的弊端, 并采用高速串行收发器Rocket I/O, 实现数据率为2.5 Gbps的高速串行传输。关键词: 高速串行传输; Rocket I/O; Aurora 协议 为促使FPGA 芯片与串行传输技术更好地结合以满足市场需求, Xilinx 公司适时推出了内嵌高速串行收发器RocketI/O 的Virtex II Pro 系列FPGA 和可升级的小型链路层协议———Aurora 协议。Rocket I/O支持从622 Mbps 至3.125 Gbps的全双工传输速率, 还具有8 B/10 B 编解码、时钟生成及恢复等功能, 可以理想地适用于芯片之间或背板的高速串行数据传输。Aurora 协议是为专有上层协议或行业标准的上层协议提供透明接口的第一款串行互连协议, 可用于高速线性通路之间的点到点串行数据传输, 同时其可扩展的带宽, 为系统设计人员提供了所需要的灵活性[4]。但该协议帧格式的定义存在弊端,会导致系统资源的浪费。本文提出的设计方案可以改进Aurora 协议的固有缺陷,提高系统性能, 实现数据率为2.5 Gbps 的高速串行传输, 具有良好的可行性和广阔的应用前景。
上传时间： 2013-10-13
上传用户：lml1234lml
This document provides practical, common guidelines for incorporating PCI Express interconnect layouts onto Printed Circuit Boards (PCB) ranging from 4-layer desktop baseboard designs to 10- layer or more server baseboard designs. Guidelines and constraints in this document are intended for use on both baseboard and add-in card PCB designs. This includes interconnects between PCI Express devices located on the same baseboard (chip-to-chip routing) and interconnects between a PCI Express device located “down” on the baseboard and a device located “up” on an add-in card attached through a connector. This document is intended to cover all major components of the physical interconnect including design guidelines for the PCB traces, vias and AC coupling capacitors, as well as add-in card edge-finger and connector considerations. The intent of the guidelines and examples is to help ensure that good high-speed signal design practices are used and that the timing/jitter and loss/attenuation budgets can also be met from end-to-end across the PCI Express interconnect. However, while general physical guidelines and suggestions are given, they may not necessarily guarantee adequate performance of the interconnect for all layouts and implementations. Therefore, designers should consider modeling and simulation of the interconnect in order to ensure compliance to all applicable specifications. The document is composed of two main sections. The first section provides an overview of general topology and interconnect guidelines. The second section concentrates on physical layout constraints where bulleted items at the beginning of a topic highlight important constraints, while the narrative that follows offers additional insight.
上传时间： 2014-01-24
上传用户：s363994250
题目：利用条件运算符的嵌套来完成此题：学习成绩>=90分的同学用A表示，60-89分之间的用B表示，60分以下的用C表示。 1.程序分析：(a>b)?a:b这是条件运算符的基本例子。
上传时间： 2015-01-08
上传用户：lifangyuan12
RSA算法 :首先, 找出三个数, p, q, r, 其中 p, q 是两个相异的质数, r 是与 (p-1)(q-1) 互质的数...... p, q, r 这三个数便是 person_key，接著, 找出 m, 使得 r^m == 1 mod (p-1)(q-1)..... 这个 m 一定存在, 因为 r 与 (p-1)(q-1) 互质, 用辗转相除法就可以得到了..... 再来, 计算 n = pq....... m, n 这两个数便是 public_key ，编码过程是, 若资料为 a, 将其看成是一个大整数, 假设 a < n.... 如果 a >= n 的话, 就将 a 表成 s 进位 (s
标签： person_key RSA 算法
上传时间： 2013-12-14
上传用户：zhuyibin
