Step-up

k-step ahead predictions determined by simulation of the ％ one-step ahead neural network predictor.

k-step ahead predictions determined by simulation of the ％ one-step ahead neural network predictor. For NNARMAX ％ models the residuals are set to zero when calculating the ％ predictions. The predictions are compared to the observed output. ％

标签： ahead predictions determined simulation

上传时间： 2016-12-27

上传用户：busterman
this is a download speed up tool at the internet

this is a download speed up tool at the internet

标签： download internet speed this

上传时间： 2014-01-12

上传用户：498732662
FOR ADS STUDY ,ABOUT ADS APPLY AND STEP.

FOR ADS STUDY ,ABOUT ADS APPLY AND STEP.

标签： ADS ABOUT APPLY STUDY

上传时间： 2017-01-07

上传用户：417313137
up-techpxa270 bootloader 文件

up-techpxa270 bootloader 文件

标签： up-techpxa bootloader 270

上传时间： 2017-01-08

上传用户：stella2015
step motor driver, very important c code.thanks.

step motor driver, very important c code.thanks.

标签： important driver thanks motor

上传时间： 2017-01-12

上传用户：515414293
电力市场下确定无功源价值的方法探讨因此提出了4种确定无功价值的方法：Vs法、PV曲线法、ERC法和Back．up法

电力市场下确定无功源价值的方法探讨因此提出了4种确定无功价值的方法：Vs法、PV曲线法、ERC法和Back．up法，分析了不同方法的特点，最后以IEEE30节点系统为例进行了仿真计算，仿真结果表明无功源的价值取决于电网的结构、无功源的位置以及系统的运行状态。

标签： Back ERC 价值电力市场

上传时间： 2017-01-17

上传用户：003030
void Knight(int i , int j) { // printf("％d ％dn",i,j) if (board[i][j] != 0 || i < 0 || i >=

void Knight(int i , int j) { // printf("％d ％dn",i,j) if (board[i][j] != 0 || i < 0 || i >= Size || j < 0 || j >= Size ) { return } step++ board[i][j]=step if (step == Size*Size) { showboard() system("PAUSE") return } //DFS Knight(i-2,j-1) //left Knight(i-2,j+1) Knight(i+2,j-1) //right Knight(i+2,j+1) Knight(i-1,j-2) //up Knight(i+1,j-2) Knight(i+1,j+2) //down Knight(i-1,j+2) // board[i][j]=0 step-- }

标签： int Knight printf board

上传时间： 2014-01-17

上传用户：cxl274287265
算法设计的实验报告包括Bottom-Up Merge Sorting算法、插入排序算法Heaps的创建堆、堆排序算法、按秩合并算法以及带路径压缩算法、实现查找第K小元素算法、实现快速排序算法、实现

算法设计的实验报告包括Bottom-Up Merge Sorting算法、插入排序算法Heaps的创建堆、堆排序算法、按秩合并算法以及带路径压缩算法、实现查找第K小元素算法、实现快速排序算法、实现平面内最接近点对算法、实现最长公共子序列算法、实现矩阵链相乘算法、实现0/1背包问题算法、实现Dijistra’s算法、Prim算法、Kruskal算法、文件压缩算法

标签： Bottom-Up Sorting Merge Heaps

上传时间： 2017-02-02

上传用户：恋天使569
bootup code for Barebone, it s useful for bring up new chip

bootup code for Barebone, it s useful for bring up new chip

标签： for Barebone bootup useful

上传时间： 2017-02-13

上传用户：ryb
Input : A set S of planar points Output : A convex hull for S Step 1: If S contains no more than f

Input : A set S of planar points Output : A convex hull for S Step 1: If S contains no more than five points, use exhaustive searching to find the convex hull and return. Step 2: Find a median line perpendicular to the X-axis which divides S into SL and SR SL lies to the left of SR . Step 3: Recursively construct convex hulls for SL and SR. Denote these convex hulls by Hull(SL) and Hull(SR) respectively. Step 4: Apply the merging procedure to merge Hull(SL) and Hull(SR) together to form a convex hull. Time complexity: T(n) = 2T(n/2) + O(n) = O(n log n)

标签： contains Output convex planar

上传时间： 2017-02-19

上传用户：wyc199288