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SDKs-And-Demos-<b>Cs</b>

  • About: hamsterdb is a database engine written in ANSI C. It supports a B+Tree index structure, uses

    About: hamsterdb is a database engine written in ANSI C. It supports a B+Tree index structure, uses memory mapped I/O (if available), supports cursors, and can create in-memory databases. Release focus: Major feature enhancements Changes: This release comes with many changes and new features. It can manage multiple databases in one file. A new flag (HAM_LOCK_EXCLUSIVE) places an exclusive lock on the file. hamsterdb was ported to Windows CE, and the Solution file for Visual Studio 2005 now supports builds for x64. Several minor bugs were fixed, performance was improved, and small API changes occurred. Pre-built libraries for Windows (32-bit and 64-bit) are available for download. Author: cruppstahl

    标签: C. hamsterdb structure database

    上传时间: 2013-12-11

    上传用户:LouieWu

  • 使用DVCC实验系统中的并行接口芯片8255A的B口作输入口

    使用DVCC实验系统中的并行接口芯片8255A的B口作输入口,使工作于方式1,将PB0~PB7连接到手动开关K1~K8,将手动脉冲信号SP作为8255B口的选通信号,连接到PC2。将B品工作于方式1时的中断请求信号(PC0)连接到8255A的IR3,8255A的片选信号无需连接(系统已连接好)。8259A的CS连接地址译码输出端Y6,8259A的端口地址为60H、61H

    标签: 8255A DVCC 实验系统 并行接口

    上传时间: 2013-12-28

    上传用户:xinyuzhiqiwuwu

  • B树算法实现

    B树算法实现,非常难得!btree implementation for random lookups, transaction handling, sequential access methods, and a small embeddable footprint.

    标签: 算法

    上传时间: 2014-01-10

    上传用户:王小奇

  • Floyd-Warshall算法描述 1)适用范围: a)APSP(All Pairs Shortest Paths) b)稠密图效果最佳 c)边权可正可负 2)算法描述: a)初始化:d

    Floyd-Warshall算法描述 1)适用范围: a)APSP(All Pairs Shortest Paths) b)稠密图效果最佳 c)边权可正可负 2)算法描述: a)初始化:dis[u,v]=w[u,v] b)For k:=1 to n For i:=1 to n For j:=1 to n If dis[i,j]>dis[i,k]+dis[k,j] Then Dis[I,j]:=dis[I,k]+dis[k,j] c)算法结束:dis即为所有点对的最短路径矩阵 3)算法小结:此算法简单有效,由于三重循环结构紧凑,对于稠密图,效率要高于执行|V|次Dijkstra算法。时间复杂度O(n^3)。 考虑下列变形:如(I,j)∈E则dis[I,j]初始为1,else初始为0,这样的Floyd算法最后的最短路径矩阵即成为一个判断I,j是否有通路的矩阵。更简单的,我们可以把dis设成boolean类型,则每次可以用“dis[I,j]:=dis[I,j]or(dis[I,k]and dis[k,j])”来代替算法描述中的蓝色部分,可以更直观地得到I,j的连通情况。

    标签: Floyd-Warshall Shortest Pairs Paths

    上传时间: 2013-12-01

    上传用户:dyctj

  • I wrote this code early this year using ColdFire MCF5213 in codewarrior IDE. The LCD is STN B/W 320x

    I wrote this code early this year using ColdFire MCF5213 in codewarrior IDE. The LCD is STN B/W 320x240 dot matrix LCD. The code include 3 different fonts, and basic LCD driver. All original!

    标签: this codewarrior ColdFire wrote

    上传时间: 2013-12-20

    上传用户:皇族传媒

  • This a linux device driver for Ralink RT2500USB b/g WLAN Card. This driver implements basic 802.11

    This a linux device driver for Ralink RT2500USB b/g WLAN Card. This driver implements basic 802.11 function. Infrastructure and Ad-hoc mode with open or shared or wpapsk or wpa2psk authentication method. WEP-40 and WEP-104 or tkip or aes encryption.

    标签: driver This implements Ralink

    上传时间: 2016-03-10

    上传用户:cc1015285075

  • A* sudo sudo/* B* adduser script adduser C* rmuser script rmuser E* tout tout/*

    A* sudo sudo/* B* adduser script adduser C* rmuser script rmuser E* tout tout/* F* dumdum dumdum G* lostfile lostfile H* Mkfl.localsys Makefile.localsys I* spacegripe spacegripe J* sendmail.cf sendmail.cf N* remote remote.c O* distributed conrol distrib/* P* hosts and name server makerevhosts Q* xargs xargs/*

    标签: adduser script rmuser sudo

    上传时间: 2016-03-29

    上传用户:gxrui1991

  • Problem B:Longest Ordered Subsequence A numeric sequence of ai is ordered if a1 < a2 < ... &l

    Problem B:Longest Ordered Subsequence A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence (a1, a2, ..., aN) be any sequence (ai1, ai2, ..., aiK), where 1 <= i1 < i2 < ... < iK <= N. For example, sequence (1, 7, 3, 5, 9, 4, 8) has ordered subsequences, e. g., (1, 7), (3, 4, 8) and many others. All longest ordered subsequences are of length 4, e. g., (1, 3, 5, 8).

    标签: Subsequence sequence Problem Longest

    上传时间: 2016-12-08

    上传用户:busterman

  • 5位的操作数X和Y输入后暂存在寄存器A和B中

    5位的操作数X和Y输入后暂存在寄存器A和B中,两位的操作控制码control暂存在寄存器C中,按照control码的不同,分布实现下列操作: 00控制X+Y 01控制X-Y 10控制X and Y 11控制 X xor Y 运算结果暂存在寄存器D中,然后输出。

    标签: 操作 寄存器 输入 暂存

    上传时间: 2014-01-18

    上传用户:yyyyyyyyyy

  • 5位的操作数X和Y输入后暂存在寄存器A和B中

    5位的操作数X和Y输入后暂存在寄存器A和B中,两位的操作控制码control暂存在寄存器C中,按照control码的不同,分布实现下列操作: 00控制X+Y 01控制X-Y 10控制X and Y 11控制 X xor Y 运算结果暂存在寄存器D中,然后输出。

    标签: 操作 寄存器 输入 暂存

    上传时间: 2014-01-09

    上传用户:凌云御清风