Many CAD users dismiss schematic capture as a necessary evil in the process of creating PCB layout but we have always disputed this point of view. With PCB layout now offering automation of both component placement and track routing, getting the design into the computer can often be the most time consuming element of the exercise. And if you use circuit simulation to develop your ideas, you are going to spend even more time working on the schematic.
标签： schematic necessary creating dismiss
上传时间： 2014-01-25
上传用户：WMC_geophy
* Use 10 MHz crystal frequency. * Use Timer0 for ten millisecond looptime. * Blink "Alive" LED every two and a half seconds. * Use pushbutton to exercise Screens utility.
标签： millisecond Use frequency looptime
上传时间： 2017-04-23
上传用户：偷心的海盗
PIC_Hi-Tech_C_Mike_Pearces_I2C_routines * Use 10 MHz crystal frequency. * Use Timer0 for ten millisecond looptime. * Blink "Alive" LED every two and a half seconds. * Use pushbutton to exercise Screens utility.
标签： PIC_Hi-Tech_C_Mike_Pearces_I C_routines Use frequency
上传时间： 2013-12-19
上传用户：标点符号
his procedure is the power spectral density of the simulation, 3 signal source on the specific circumstances, see the "modern digital signal processing" Introduction to the first volume, P202, Exercise 5. Experimental Methods
标签： the simulation procedure spectral
上传时间： 2014-01-17
上传用户：金宜
SSD3参考答案 EXERCISE中缺少EXERCISE4之后的部分
标签： SSD3
上传时间： 2016-06-12
上传用户：EnumaElish
Dynasty 350, 700 208/575 Volt Models W/Auto-Line Maxstar 350, 700 File: TIG (GTAW) Including Optional Cart And Cooler CE And Non-CE Models
上传时间： 2017-03-11
上传用户：zosoong
1．Describe a Θ(n lg n)-time algorithm that, given a set S of n integers and another integer x, determines whether or not there exist two elements in S whose sum is exactly x. (Implement exercise 2.3-7.)
上传时间： 2017-04-01
上传用户：糖儿水嘻嘻
1．Describe a Θ(n lg n)-time algorithm that, given a set S of n integers and another integer x, determines whether or not there exist two elements in S whose sum is exactly x. (Implement exercise 2.3-7.) #include<stdio.h> #include<stdlib.h> void merge(int arr[],int low,int mid,int high){ int i,k; int *tmp=(int*)malloc((high-low+1)*sizeof(int)); int left_low=low; int left_high=mid; int right_low=mid+1; int right_high=high; for(k=0;left_low<=left_high&&right_low<=right_high;k++) { if(arr[left_low]<=arr[right_low]){ tmp[k]=arr[left_low++]; } else{ tmp[k]=arr[right_low++]; } } if(left_low<=left_high){ for(i=left_low;i<=left_high;i++){ tmp[k++]=arr[i]; } } if(right_low<=right_high){ for(i=right_low;i<=right_high;i++) tmp[k++]=arr[i]; } for(i=0;i<high-low+1;i++) arr[low+i]=tmp[i]; } void merge_sort(int a[],int p,int r){ int q; if(p<r){ q=(p+r)/2; merge_sort(a,p,q); merge_sort(a,q+1,r); merge(a,p,q,r); } } int main(){ int a[8]={3,5,8,6,4,1,1}; int i,j; int x=10; merge_sort(a,0,6); printf("after Merging-Sort:\n"); for(i=0;i<7;i++){ printf("%d",a[i]); } printf("\n"); i=0;j=6; do{ if(a[i]+a[j]==x){ printf("exist"); break; } if(a[i]+a[j]>x) j--; if(a[i]+a[j]<x) i++; }while(i<=j); if(i>j) printf("not exist"); system("pause"); return 0; }
上传时间： 2017-04-01
上传用户：糖儿水嘻嘻
ADSP Computer Exercise
标签： ADSP
上传时间： 2017-12-23
上传用户：詹姆斯邵
The family of recent wireless standards included the optional employment of Multiple-Input Multiple-Output(MIMO)techniques.This was motivatedby the observationaccordingto the classic Shannon–Hartley law that the achievable channel capacity increases logarithmically with the transmit power. In contrast, the MIMO capacity increases linearly with the number of transmit antennas, provided that the number of receive antennas is equal to the number of transmit antennas. With the further proviso that the total transmit power is increased in proportion to the number of transmit antennas, a linear capacity increase is achieved upon increasing the transmit power, which justifies the spectacular success of MIMO systems.
标签： Multi-Functional Systems MIMO
上传时间： 2020-05-31
上传用户：shancjb
