E:\Visual_C__MFC扩展编程实例 例18 动态地抓取应用程序的屏幕图像并将其打印。 上一个实例打印的是文档的报表，而不是当前出现在屏幕上的内容。在本例中，将实现 屏幕抓取并打印其内容。M F C 为打印视提供了有限的支持， 但只要用M F C 在 C Vi e w : : O n D r a w ( )中所提供的设备环境，就可以绘制自己的视。在打印视的时候， M F C只需调 用具备打印机设备环境的O n D r a w ( )函数即可。但是，如果不绘制自己的视，例如，用一个或 者一个以上的控件窗口填充自己的视就不会打印任何东西。每个控件将使用自己的设备环境 将自己打印到屏幕，因此打印视的唯一途径就是抓取屏幕(拷贝其内容到一个位图对象)并将其 打印到打印机。由于该功能整个与位图相关，因此将该功能封装到了位图类中。
上传时间： 2015-10-18
上传用户：asddsd
This book is the most accurate and up-to-date source of information the STL currently available. ... It has an approach and appeal of its own: it explains techniques for building data structures and algorithms on top of the STL, and in this way appreciates the STL for what it is - a framework. Angelika Langer, Independent Consultant and C++ Report Columnist "A superbly authored treatment of the STL......an excellent book which belongs in any serious C++ developer s library." Jim Armstrong, President 2112 F/X, Texas. \n The C++ Standard Template Library (STL) represents a breakthrough in C++ programming techniques. With it, software developers can achieve vast improvements in the reliability of their software, and increase their own productivity.
标签： information up-to-date available currently
上传时间： 2015-10-31
上传用户：CHINA526
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
标签： represented integers group items
上传时间： 2016-01-17
上传用户：jeffery
Sherwood算法消除最坏实例，以达到对任何实例都能有好的性能的效果 文件： rd_list.c --> create a random sequence of n integers not equal to each other list.c --> create a descending sequence of n integers not equal to each other sherwood.c --> 就是该算法，静态链表的长度默认设为1000，可在宏定义处修改 用法： gcc -o sherwood sherwood.c gcc -o rd_list rd_list.c gcc -o list list.c ./rd_list s.txt 1000 产生一个长度为1000的互不相等的随机序列，保存在s.txt中 ./list s1.txt 1000 产生一个长度为1000的互不相等的降序序列，保存杂s1.txt中 ./sherwood s1.txt 运行算法，比较其中的4个算法的性能差异
上传时间： 2016-01-20
上传用户：ainimao
The XML Toolbox converts MATLAB data types (such as double, char, struct, complex, sparse, logical) of any level of nesting to XML format and vice versa. For example, >> project.name = MyProject >> project.id = 1234 >> project.param.a = 3.1415 >> project.param.b = 42 becomes with str=xml_format(project, off ) "<project> <name>MyProject</name> <id>1234</id> <param> <a>3.1415</a> <b>42</b> </param> </project>" On the other hand, if an XML string XStr is given, this can be converted easily to a MATLAB data type or structure V with the command V=xml_parse(XStr).
标签： converts Toolbox complex logical
上传时间： 2016-02-12
上传用户：a673761058
java做书箱管理系统，C／S结构的，数据库是access2003的
上传时间： 2014-01-16
上传用户：GavinNeko
java做的学生管理系统，C／S结构，数据库是access2003.
上传时间： 2016-02-25
上传用户：牛津鞋
turbo码simulink编码程序，可以用来学如何用c++编写s函数。
上传时间： 2016-03-29
上传用户：baitouyu
微分方程的数值解法MATLAB Matlab. 程序. (. 主程序：. ZCX). global P. t0，Y0，h，N ％输入初始条件、计算步长和迭代次数. M, K, C ％输入结构参数. A=[0, I -M
上传时间： 2014-01-15
上传用户：D&L37
武汉理工大学的WEB技术课件，讲述了JSP的M,V,C三个层，以及JAVA的一些
上传时间： 2013-12-27
上传用户：hasan2015
