Get payload data from a raw Tcp/ip packet
上传时间： 2013-12-29
上传用户：hjshhyy
something useful for communication,source code based on FPGA
标签： communication something useful source
上传时间： 2015-08-15
上传用户：xfbs821
Examples of VHDL Descriptions ROM-based waveform generator
标签： Descriptions ROM-based generator Examples
上传时间： 2013-12-14
上传用户：jyycc
KVM (for Kernel-based Virtual Machine) is a full virtualization solution for Linux on x86 hardware. It consists of a loadable kernel module (kvm.ko) and a userspace component. Using KVM, one can run multiple virtual machines running unmodified Linux or Windows images. Each virtual machine has private virtualized hardware: a network card, disk, graphics adapter, etc. The kernel component of KVM is included in mainline Linux, and will appear in Linux 2.6.20. KVM is open source software.
标签： virtualization Kernel-based for hardware
上传时间： 2015-08-20
上传用户：lijianyu172
A-Moving-Object-Database-Model-Based-on-Road-NetWork一种基于道路网络的移动目标数据库模型
标签： A-Moving-Object-Database-Model-Ba sed-on-Road-NetWork 道路网络 移动
上传时间： 2014-01-01
上传用户：klin3139
Cracking the Code - Wireless Programming with J2ME This book is based on the unique concept of cracking the code and mastering the technology.The technologies covered are J2ME version 1.0.2 and the applications are also tested on version 1.0.3 Beta.
标签： Programming the Cracking Wireless
上传时间： 2015-08-20
上传用户：fhzm5658
Java Data Objects - Oreilly
上传时间： 2015-08-21
上传用户：whenfly
matlab例程MATLAB 6.x版的内建数据类型（Built-in data type）就有5种以上，此外还有许多其他专门设计的类（Class），如符号类、内联函数类、控制工具包中的线性时不变模型类、神经网络类等。就程序设计而言，MATLAB 6.x版采用了面向对象编程技术。数据和编程的改变使用户能更简捷而自然地解决复杂的计算问题（如符号计算问题、多变量控制系统问题、神经网络问题）。本章内容根据MATLAB6.5编写，但绝大部分内容适用于其他MATLAB6.x版本。
标签： Built-in matlab MATLAB data
上传时间： 2013-12-13
上传用户：agent
A New Identity-based Proxy Signature Scheme from Bilinear Pairings
标签： Identity-based Signature Bilinear Pairings
上传时间： 2015-08-22
上传用户：agent
ACM试题An Easy Problem Description As we known, data stored in the computers is in binary form. The problem we discuss now is about the positive integers and its binary form. Given a positive integer I, you task is to find out an integer J, which is the minimum integer greater than I, and the number of 1 s in whose binary form is the same as that in the binary form of I. For example, if "78" is given, we can write out its binary form, "1001110". This binary form has 4 1 s. The minimum integer, which is greater than "1001110" and also contains 4 1 s, is "1010011", i.e. "83", so you should output "83".
标签： Description computers Problem binary
上传时间： 2013-12-11
上传用户：libenshu01
