1.有三根杆子A,B,C。A杆上有若干碟子 2.每次移动一块碟子,小的只能叠在大的上面 3.把所有碟子从A杆全部移到C杆上 经过研究发现，汉诺塔的破解很简单，就是按照移动规则向一个方向移动金片： 如3阶汉诺塔的移动：A→C,A→B,C→B,A→C,B→A,B→C,A→C 此外，汉诺塔问题也是程序设计中的经典递归问题
上传时间： 2016-07-25
上传用户：gxrui1991
Recent advances in experimental methods have resulted in the generation of enormous volumes of data across the life sciences. Hence clustering and classification techniques that were once predominantly the domain of ecologists are now being used more widely. This book provides an overview of these important data analysis methods, from long-established statistical methods to more recent machine learning techniques. It aims to provide a framework that will enable the reader to recognise the assumptions and constraints that are implicit in all such techniques. Important generic issues are discussed first and then the major families of algorithms are described. Throughout the focus is on explanation and understanding and readers are directed to other resources that provide additional mathematical rigour when it is required. Examples taken from across the whole of biology, including bioinformatics, are provided throughout the book to illustrate the key concepts and each technique’s potential.
标签： experimental generation advances enormous
上传时间： 2016-10-23
上传用户：wkchong
1. 下列说法正确的是 （ ） A. Java语言不区分大小写 B. Java程序以类为基本单位 C. JVM为Java虚拟机JVM的英文缩写 D. 运行Java程序需要先安装JDK 2. 下列说法中错误的是 ( ) A. Java语言是编译执行的 B. Java中使用了多进程技术 C. Java的单行注视以//开头 D. Java语言具有很高的安全性 3. 下面不属于Java语言特点的一项是( ) A. 安全性 B. 分布式 C. 移植性 D. 编译执行 4. 下列语句中，正确的项是 ( ) A . int $e,a,b=10 B. char c,d=’a’ C. float e=0.0d D. double c=0.0f
上传时间： 2017-01-04
上传用户：netwolf
|- 数据科学速查表 - 0 B|- 迁移学习实战 - 0 B|- 零起点Python机器学习快速入门 - 0 B|- 《深度学习入门：基于Python的理论与实现》高清中文版PDF+源代码 - 0 B|- 《Python生物信息学数据管理》中文版PDF+英文版PDF+源代码 - 0 B|- 《Python深度学习》2018中文版pdf+英文版pdf+源代码 - 0 B|- 《Python编程：从入门到实践》中文版+源代码 - 0 B|- stanford machine learning - 0 B|- Python语言程序设计2018版电子教案 - 0 B|- Python网络编程第三版 （原版+中文版+源代码） - 0 B|- Python机器学习实践指南（中文版带书签）、原书代码、数据集 - 0 B|- python官方文档 - 0 B|- Python编程(第4版 套装上下册) - 0 B|- PyQt5快速开发与实战（pdf+源码） - 0 B|- linux - 0 B|- 征服PYTHON-语言基础与典型应用.pdf - 67.40 MB|- 与孩子一起学编程_中文版_详细书签.pdf - 69.10 MB|- 用Python做科学计算.pdf - 6.10 MB|- 用Python写网络爬虫.pdf - 9.90 MB|- 用Python进行自然语言处理(中文翻译NLTK).pdf - 4.40 MB|- 像计算机科学家那样思考 Python中文版第二版.pdf - 712.00 kB|- 网络爬虫－Python和数据分析.pdf - 6.90 MB|- 图解机器学习.pdf - 59.40 MB|- 凸优化.pdf - 5.70 MB|- 数据挖掘导论.pdf - 2.50 MB|- 数据科学入门.pdf - 13.30 MB|- 数据结构与算法__Python语言描述_裘宗燕编著_北京：机械工业出版社_，_2016.01_P346.pdf - 74.30 MB|- 神经网络与深度学习.pdf - 92.60 MB|- 深入Python3...
标签： python
上传时间： 2022-06-06
上传用户：
Learning Kernel Classifiers: Theory and Algorithms, Introduction This chapter introduces the general problem of machine learning and how it relates to statistical inference. 1.1 The Learning Problem and (Statistical) Inference It was only a few years after the introduction of the first computer that one of man’s greatest dreams seemed to be realizable—artificial intelligence. Bearing in mind that in the early days the most powerful computers had much less computational power than a cell phone today, it comes as no surprise that much theoretical research on the potential of machines’ capabilities to learn took place at this time. This becomes a computational problem as soon as the dataset gets larger than a few hundred examples.
标签： Introduction Classifiers Algorithms introduces
上传时间： 2015-10-20
上传用户：aeiouetla
The present era of research and development is all about interdisciplinary studies attempting to better comprehend and model our understanding of this vast universe. The fields of biology and computer science are no exception. This book discusses some of the innumerable ways in which computational methods can be used to facilitate research in biology and medicine—from storing enormous amounts of biological data to solving complex biological problems and enhancing the treatment of various diseases.
上传时间： 2020-06-10
上传用户：shancjb
特点： 精确度0.1%满刻度 可作各式數學演算式功能如:A+B/A-B/AxB/A/B/A&B(Hi or Lo)/|A|/ 16 BIT类比输出功能 输入与输出绝缘耐压2仟伏特/1分钟(input/output/power) 宽范围交直流兩用電源設計 尺寸小,穩定性高
上传时间： 2014-12-23
上传用户：ydd3625
特点(FEATURES) 精确度0.1%满刻度 (Accuracy 0.1%F.S.) 可作各式数学演算式功能如:A+B/A-B/AxB/A/B/A&B(Hi or Lo)/|A| (Math functioA+B/A-B/AxB/A/B/A&B(Hi&Lo)/|A|/etc.....) 16 BIT 类比输出功能(16 bit DAC isolating analog output function) 输入/输出1/输出2绝缘耐压2仟伏特/1分钟(Dielectric strength 2KVac/1min. (input/output1/output2/power)) 宽范围交直流两用电源设计(Wide input range for auxiliary power) 尺寸小,稳定性高(Dimension small and High stability)
上传时间： 2013-11-24
上传用户：541657925
/*--------- 8051内核特殊功能寄存器 -------------*/ sfr ACC = 0xE0; //累加器 sfr B = 0xF0; //B 寄存器 sfr PSW = 0xD0; //程序状态字寄存器 sbit CY = PSW^7; //进位标志位 sbit AC = PSW^6; //辅助进位标志位 sbit F0 = PSW^5; //用户标志位0 sbit RS1 = PSW^4; //工作寄存器组选择控制位 sbit RS0 = PSW^3; //工作寄存器组选择控制位 sbit OV = PSW^2; //溢出标志位 sbit F1 = PSW^1; //用户标志位1 sbit P = PSW^0; //奇偶标志位 sfr SP = 0x81; //堆栈指针寄存器 sfr DPL = 0x82; //数据指针0低字节 sfr DPH = 0x83; //数据指针0高字节 /*------------ 系统管理特殊功能寄存器 -------------*/ sfr PCON = 0x87; //电源控制寄存器 sfr AUXR = 0x8E; //辅助寄存器 sfr AUXR1 = 0xA2; //辅助寄存器1 sfr WAKE_CLKO = 0x8F; //时钟输出和唤醒控制寄存器 sfr CLK_DIV = 0x97; //时钟分频控制寄存器 sfr BUS_SPEED = 0xA1; //总线速度控制寄存器 /*----------- 中断控制特殊功能寄存器 --------------*/ sfr IE = 0xA8; //中断允许寄存器 sbit EA = IE^7; //总中断允许位 sbit ELVD = IE^6; //低电压检测中断控制位 8051
上传时间： 2013-10-30
上传用户：yxgi5
TLC2543是TI公司的12位串行模数转换器，使用开关电容逐次逼近技术完成A/D转换过程。由于是串行输入结构，能够节省51系列单片机I/O资源；且价格适中，分辨率较高，因此在仪器仪表中有较为广泛的应用。 TLC2543的特点 （1）12位分辩率A/D转换器； （2）在工作温度范围内10μs转换时间； （3）11个模拟输入通道； （4）3路内置自测试方式； （5）采样率为66kbps； （6）线性误差±1LSBmax； （7）有转换结束输出EOC； （8）具有单、双极性输出； （9）可编程的MSB或LSB前导； （10）可编程输出数据长度。 TLC2543的引脚排列及说明 TLC2543有两种封装形式：DB、DW或N封装以及FN封装，这两种封装的引脚排列如图1，引脚说明见表1 TLC2543电路图和程序欣赏 #include<reg52.h> #include<intrins.h> #define uchar unsigned char #define uint unsigned int sbit clock=P1^0; sbit d_in=P1^1; sbit d_out=P1^2; sbit _cs=P1^3; uchar a1,b1,c1,d1; float sum,sum1; double sum_final1; double sum_final; uchar duan[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f}; uchar wei[]={0xf7,0xfb,0xfd,0xfe}; void delay(unsigned char b) //50us { unsigned char a; for(;b>0;b--) for(a=22;a>0;a--); } void display(uchar a,uchar b,uchar c,uchar d) { P0=duan[a]|0x80; P2=wei[0]; delay(5); P2=0xff; P0=duan[b]; P2=wei[1]; delay(5); P2=0xff; P0=duan[c]; P2=wei[2]; delay(5); P2=0xff; P0=duan[d]; P2=wei[3]; delay(5); P2=0xff; } uint read(uchar port) { uchar i,al=0,ah=0; unsigned long ad; clock=0; _cs=0; port<<=4; for(i=0;i<4;i++) { d_in=port&0x80; clock=1; clock=0; port<<=1; } d_in=0; for(i=0;i<8;i++) { clock=1; clock=0; } _cs=1; delay(5); _cs=0; for(i=0;i<4;i++) { clock=1; ah<<=1; if(d_out)ah|=0x01; clock=0; } for(i=0;i<8;i++) { clock=1; al<<=1; if(d_out) al|=0x01; clock=0; } _cs=1; ad=(uint)ah; ad<<=8; ad|=al; return(ad); } void main() { uchar j; sum=0;sum1=0; sum_final=0; sum_final1=0; while(1) { for(j=0;j<128;j++) { sum1+=read(1); display(a1,b1,c1,d1); } sum=sum1/128; sum1=0; sum_final1=(sum/4095)*5; sum_final=sum_final1*1000; a1=(int)sum_final/1000; b1=(int)sum_final%1000/100; c1=(int)sum_final%1000%100/10; d1=(int)sum_final%10; display(a1,b1,c1,d1); } }
上传时间： 2013-11-19
上传用户：shen1230
