计算全息close all clc clear A=zeros(64) A(15:20,20:40)=1 A(15:50,20:25)=1 A(45:50,20:40)=1 A(30:34,20:35)=1 ％ ppp=exp(rand(64)*pi*2*i) A=A.*ppp ％ Author s email: zjliu2001@163.com figure imshow(abs(A),[]) Fa=fft2(fftshift(A)) Fs=fftshift(Fa) Am=abs(Fs) ％ amplitude Ph=angle(Fs) ％ phase s=11 ％ 这表示边长吗？ cgh=zeros(64*s) th=max(max(abs(Fs)))
上传时间： 2014-10-13
上传用户：wweqas
void insert_sort(int *a,int n) { if(n==1) return insert_sort(a,n-1) int temp=a[n-1] for(int i=n-2 i>=0 i--) { if(temp<a[i]) a[i+1]=a[i] else break } a[i+1]=temp }
标签： insert_sort int return void
上传时间： 2014-01-22
上传用户：banyou
设存在集合A，R是A上的关系，检查R是否为等价关系。并且生成R的自反闭包、对称闭包和传递闭包。R既可以由用户输入，也可以由程序随机生成。【最大选题人数：8】 提示：集合A中的元素可以是任何类型，甚至是对象。
标签：
上传时间： 2013-12-17
上传用户：sunjet
开源备份软件源码 AMANDA, the Advanced Maryland Automatic Network Disk Archiver, is a backup system that allows the administrator to set up a single master backup server to back up multiple hosts over network to tape drives/changers or disks or optical media. Amanda uses native dump and/or GNU tar facilities and can back up a large number of workstations running multiple versions of Unix. Amanda uses Samba, Cygwin or a native Windows client to back up Microsoft Windows desktops and servers
标签： Automatic Advanced Maryland Archiver
上传时间： 2017-01-13
上传用户：xc216
专家点评: Y P7 `. @ {$ r％ pa.功能很强大，可以看出花了很多心血在算法上，非常好。算法上还有一点瑕疵，例如在删除一个员工的同时没有办法自动建立其他员工的上下级关系，必须删除全部下级员工，不是非常合理。此外，界面设计过于简单，应该加强. " W" R+ b* g$ a$ Sb.程序运用了自己的算法来提高Tree控件显示的速度和资源分配，这个非常值得肯定和鼓励。* C. c4 D0 e9 ` J$ w# U c.基本实现所有规定的功能，在所有参赛者中唯一熟 : O) l- F6 F9 f) S7 Q. l练使用面向对象设计方式开发程序的工程师，很不错！程序体现了作者非常扎实的数据结构功底，值得大家学习。工程管理也做得非常好，体现了作者在软件工程方面也有很深入的研究，该代码是很好的学习范例。 ％ G* H$ ~3 W1 ]. e! id.算法的创新是独特之处(hashtable算法建立),可见作者在数据结构方面的熟练掌握.此程序是很多专家会员学习典范.
上传时间： 2017-01-19
上传用户：奇奇奔奔
汉诺塔！！！ Simulate the movement of the Towers of Hanoi puzzle Bonus is possible for using animation eg. if n = 2 A→B A→C B→C if n = 3 A→C A→B C→B A→C B→A B→C A→C
标签： the animation Simulate movement
上传时间： 2017-02-11
上传用户：waizhang
Instead of finding the longest common subsequence, let us try to determine the length of the LCS. Then tracking back to find the LCS. Consider a1a2…am and b1b2…bn. Case 1: am=bn. The LCS must contain am, we have to find the LCS of a1a2…am-1 and b1b2…bn-1. Case 2: am≠bn. Wehave to find the LCS of a1a2…am-1 and b1b2…bn, and a1a2…am and b b b b1b2…bn-1 Let A = a1 a2 … am and B = b1 b2 … bn Let Li j denote the length of the longest i,g g common subsequence of a1 a2 … ai and b1 b2 … bj. Li,j = Li-1,j-1 + 1 if ai=bj max{ L L } a≠b i-1,j, i,j-1 if ai≠j L0,0 = L0,j = Li,0 = 0 for 1≤i≤m, 1≤j≤n.
标签： the subsequence determine Instead
上传时间： 2013-12-17
上传用户：evil
C++ XML is a book exclusively devoted to the pow er and complexities of integrating XML standards into C++. As a developer,this is a book you cannot miss. C++ XML addresses all major standards,toolkits,and types of applications dealing with XML as a format for representing and exchanging data,as well as XML behavior,from a C++ standpoint. It explains the implementation of applications and reusuable frameworks for all major XML purposes exclusively using C/C++ parsers and toolkits, such as expat,Xerces,Xalan,libxml2,and Microsoft’s MSXML.
标签： complexities exclusively integrating XML
上传时间： 2014-03-11
上传用户：zhaiyanzhong
This program demonstrates how to draw lines in a picture box using the GDI, controlling background color and line color. It also includes a simple animation using a timer.
标签： demonstrates controlling background program
上传时间： 2014-01-16
上传用户：小眼睛LSL
ITU-T G.729 Annex C+ - Reference C code for floating point implementation of G.729 at 6.4/8/11.8 kbit/s with DTX functionality (integration of Annexes B, D and E)
标签： implementation 729 Reference floating
上传时间： 2017-04-10
上传用户：cccole0605
