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A<b>Bode</b>P

  • prolog 找路例子程序: === === === === === === Part 1-Adding connections Part 2-Simple Path example

    prolog 找路例子程序: === === === === === === Part 1-Adding connections Part 2-Simple Path example | ?- path1(a,b,P,T). will produce the response: T = 15 P = [a,b] ? Part 3 - Non-repeating path As an example, the query: ?- path2(a,h,P,T). will succeed and may produce the bindings: P = [a,depot,b,d,e,f,h] T = 155 Part 4 - Generating a path below a cost threshold As an example, the query: ?- path_below_cost(a,[a,b,c,d,e,f,g,h],RS,300). returns: RS = [a,b,depot,c,d,e,g,f,h] ? RS = [a,c,depot,b,d,e,g,f,h] ? no ==================================

    标签: Part connections example prolog

    上传时间: 2015-04-24

    上传用户:ljt101007

  • 源代码用动态规划算法计算序列关系个数 用关系"<"和"="将3个数a

    源代码\用动态规划算法计算序列关系个数 用关系"<"和"="将3个数a,b,c依次序排列时,有13种不同的序列关系: a=b=c,a=b<c,a<b=v,a<b<c,a<c<b a=c<b,b<a=c,b<a<c,b<c<a,b=c<a c<a=b,c<a<b,c<b<a 若要将n个数依序列,设计一个动态规划算法,计算出有多少种不同的序列关系, 要求算法只占用O(n),只耗时O(n*n).

    标签: lt 源代码 动态规划 序列

    上传时间: 2013-12-26

    上传用户:siguazgb

  • The government of a small but important country has decided that the alphabet needs to be streamline

    The government of a small but important country has decided that the alphabet needs to be streamlined and reordered. Uppercase letters will be eliminated. They will issue a royal decree in the form of a String of B and A characters. The first character in the decree specifies whether a must come ( B )Before b in the new alphabet or ( A )After b . The second character determines the relative placement of b and c , etc. So, for example, "BAA" means that a must come Before b , b must come After c , and c must come After d . Any letters beyond these requirements are to be excluded, so if the decree specifies k comparisons then the new alphabet will contain the first k+1 lowercase letters of the current alphabet. Create a class Alphabet that contains the method choices that takes the decree as input and returns the number of possible new alphabets that conform to the decree. If more than 1,000,000,000 are possible, return -1. Definition

    标签: government streamline important alphabet

    上传时间: 2015-06-09

    上传用户:weixiao99

  • 一:需求分析 1. 问题描述 魔王总是使用自己的一种非常精练而抽象的语言讲话,没人能听懂,但他的语言是可逐步解释成人能听懂的语言,因为他的语言是由以下两种形式的规则由人的语言逐步抽象上去的: -

    一:需求分析 1. 问题描述 魔王总是使用自己的一种非常精练而抽象的语言讲话,没人能听懂,但他的语言是可逐步解释成人能听懂的语言,因为他的语言是由以下两种形式的规则由人的语言逐步抽象上去的: ----------------------------------------------------------- (1) a---> (B1)(B2)....(Bm) (2)[(op1)(p2)...(pn)]---->[o(pn)][o(p(n-1))].....[o(p1)o] ----------------------------------------------------------- 在这两种形式中,从左到右均表示解释.试写一个魔王语言的解释系统,把 他的话解释成人能听得懂的话. 2. 基本要求: 用下述两条具体规则和上述规则形式(2)实现.设大写字母表示魔王语言的词汇 小写字母表示人的语言的词汇 希腊字母表示可以用大写字母或小写字母代换的变量.魔王语言可含人的词汇. (1) B --> tAdA (2) A --> sae 3. 测试数据: B(ehnxgz)B 解释成 tsaedsaeezegexenehetsaedsae若将小写字母与汉字建立下表所示的对应关系,则魔王说的话是:"天上一只鹅地上一只鹅鹅追鹅赶鹅下鹅蛋鹅恨鹅天上一只鹅地上一只鹅". | t | d | s | a | e | z | g | x | n | h | | 天 | 地 | 上 | 一只| 鹅 | 追 | 赶 | 下 | 蛋 | 恨 |

    标签: 语言 抽象

    上传时间: 2014-12-02

    上传用户:jkhjkh1982

  • We have a group of N items (represented by integers from 1 to N), and we know that there is some tot

    We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.

    标签: represented integers group items

    上传时间: 2016-01-17

    上传用户:jeffery

  • 单纯形法算法,int K,M,N,Q=100,Type,Get,Let,Et,Code[50],XB[50],IA,IAA[50],Indexg,Indexl,Indexe float Sum,A

    单纯形法算法,int K,M,N,Q=100,Type,Get,Let,Et,Code[50],XB[50],IA,IAA[50],Indexg,Indexl,Indexe float Sum,A[50][50],B[50],C[50]

    标签: 50 Indexg Indexe Indexl

    上传时间: 2013-12-22

    上传用户:顶得柱

  • The "GEE! It s Simple" package illustrates Gaussian elimination with partial pivoting, which produce

    The "GEE! It s Simple" package illustrates Gaussian elimination with partial pivoting, which produces a factorization of P*A into the product L*U where P is a permutation matrix, and L and U are lower and upper triangular, respectively. The functions in this package are accurate, but they are far slower than their MATLAB equivalents (x=A\b, [L,U,p]=lu(A), and so on). They are presented here merely to illustrate and educate. "Real" production code should use backslash and lu, not this package.

    标签: illustrates elimination Gaussian pivoting

    上传时间: 2016-11-09

    上传用户:wang5829

  • The "GEE! It s Simple" package illustrates Gaussian elimination with partial pivoting, which produce

    The "GEE! It s Simple" package illustrates Gaussian elimination with partial pivoting, which produces a factorization of P*A into the product L*U where P is a permutation matrix, and L and U are lower and upper triangular, respectively. The functions in this package are accurate, but they are far slower than their MATLAB equivalents (x=A\b, [L,U,p]=lu(A), and so on). They are presented here merely to illustrate and educate. "Real" production code should use backslash and lu, not this package.

    标签: illustrates elimination Gaussian pivoting

    上传时间: 2014-01-21

    上传用户:lxm

  • made by: kangkai data:2008.11.23 this one is used to test arm7 str71x. use a led to test

    made by: kangkai data:2008.11.23 this one is used to test arm7 str71x. use a led to test GPIO. a---------P0.0 b---------P0.1 c---------P0.2 d---------P0.3 e---------P0.4 f---------P0.5 g---------P0.6 just run it and you will see the led to show 0-9 all the time.

    标签: test kangkai made 2008

    上传时间: 2016-12-16

    上传用户:moerwang

  • 12345

    /****************temic*********t5557***********************************/    #include   <at892051.h>     #include   <string.h>    #include   <intrins.h>     #include   <stdio.h>     #define    uchar    unsigned char     #define    uint     unsigned int     #define    ulong    unsigned long     //STC12C2051AD的SFR定义     sfr  WDT_CONTR = 0xe1;//stc2051的看门狗??????     /**********全局常量************/    //写卡的命令     #define    write_command0       0//写密码     #define    write_command1       1//写配置字     #define    write_command2       2//密码写数据     #define    write_command3       3//唤醒     #define    write_command4       4//停止命令     #define    TRUE       1     #define    FALSE      0     #define    OK         0     #define    ERROR      255     //读卡的时间参数us     #define ts_min          250//270*11.0592/12=249//取近似的整数     #define ts_max          304//330*11.0592/12=304     #define t1_min          73//90*11.0592/12=83:-10调整     #define t1_max          156//180*11.0592/12=166     #define t2_min          184//210*11.0592/12=194     #define t2_max          267//300*11.0592/12=276     //***********不采用中断处理:采用查询的方法读卡时关所有中断****************/     sbit p_U2270B_Standby = P3^5;//p_U2270B_Standby PIN=13     sbit p_U2270B_CFE = P3^3;//p_U2270B_CFE     PIN=6     sbit p_U2270B_OutPut = P3^7;//p_U2270B_OutPut  PIN=2     sbit wtd_sck = P1^7;//SPI总线     sbit wtd_si = P1^3;    sbit wtd_so = P1^2;    sbit iic_data = P1^2;//lcd IIC     sbit iic_clk = P1^7;    sbit led_light = P1^6;//测试绿灯     sbit led_light1 = P1^5;//测试红灯     sbit led_light_ok  = P1^1;//读卡成功标志     sbit fengmingqi = P1^5;    /***********全局变量************************************/       uchar data Nkey_a[4] = {0xA0, 0xA1, 0xA2, 0xA3};//初始密码             //uchar idata card_snr[4];   //配置字     uchar data bankdata[28] = {1,2,3,4,5,6,7,1,2,3,4,5,6,7,1,2,3,4,5,6,7,1,2,3,4,5,6,7};     //存储卡上用户数据(1-7)7*4=28     uchar data cominceptbuff[6] = {1,2,3,4,5,6};//串口接收数组ram     uchar command; //第一个命令     uchar command1;//     //uint  temp;     uchar j,i;    uchar myaddr = 8;    //uchar ywqz_count,time_count;             //ywqz jishu:     uchar bdata DATA;    sbit BIT0 = DATA^0;    sbit BIT1 = DATA^1;    sbit BIT2 = DATA^2;    sbit BIT3 = DATA^3;    sbit BIT4 = DATA^4;    sbit BIT5 = DATA^5;    sbit BIT6 = DATA^6;    sbit BIT7 = DATA^7;    uchar bdata DATA1;    sbit BIT10 = DATA1^0;    sbit BIT11 = DATA1^1;    sbit BIT12 = DATA1^2;    sbit BIT13 = DATA1^3;    sbit BIT14 = DATA1^4;    sbit BIT15 = DATA1^5;    sbit BIT16 = DATA1^6;    sbit BIT17 = DATA1^7;    bit i_CurrentLevel;//i_CurrentLevel  BIT 00H(Saves current level of OutPut pin of U2270B)     bit timer1_end;    bit read_ok = 0;    //缓存定时值,因用同一个定时器     union HLint { uint W;    struct   {    uchar H;uchar L;   }   B; };//union HLint idata a     union HLint data a;    //缓存定时值,因用同一个定时器     union HLint0 { uint W;    struct {   uchar H;   uchar L; } B; };//union HLint idata a     union HLint0 data b;    /**********************函数原型*****************/    //读写操作     void f_readcard(void);//全部读出1~7 AOR唤醒     void f_writecard(uchar x);//根据命令写不同的内容和操作     void f_clearpassword(void);//清除密码     void f_changepassword(void);//修改密码     //功能子函数     void write_password(uchar data *data p);//写初始密码或数据     void write_block(uchar x,uchar data *data p);//不能用通用指针     void write_bit(bit x);//写位     /*子函数区*****************************************************/    void delay_2(uint x)    //延时,时间x*10us@12mhz,最小20us@12mhz     {    x--; x--;    while(x)    {      _nop_();      _nop_();      x--;    }    _nop_();//WDT_CONTR=0X3C;不能频繁的复位     _nop_();    }    /////////////////////////////////////////////////////////////////////     void initial(void)    {    SCON = 0x50; //串口方式1,允许接收     //SCON  =0x50;     //01010000B:10位异步收发,波特率可变,SM2=0不用接收到有效停止位才RI=1,     //REN=1允许接收     TMOD = 0x21; //定时器1 定时方式2(8位),定时器0 定时方式1(16位)     TCON = 0x40; //设定时器1 允许开始计时(IT1=1)     TH1 = 0xfD;  //FB 18.432MHz 9600 波特率     TL1 = 0xfD;  //fd 11.0592 9600     IE = 0X90;     //EA=ES=1     TR1 = 1;     //启动定时器     WDT_CONTR = 0x3c;//使能看门狗     p_U2270B_Standby = 0;//单电源     PCON = 0x00;    IP = 0x10;//uart you xian XXXPS PT1 PX1 PT0 PX0     led_light1 = 1;    led_light = 0;    p_U2270B_OutPut = 1;    }    /************************************************/    void f_readcard()//读卡     {    EA = 0;//全关,防止影响跳变的定时器计时     WDT_CONTR = 0X3C;//喂狗     p_U2270B_CFE = 1;//      delay_2(232);  //>2.5ms            /*   //   aor    用唤醒功能来防碰撞   p_U2270B_CFE = 0; delay_2(18);//start gap>150us   write_bit(1);//10=操作码读0页   write_bit(0);       write_password(&bankdata[24]);//密码block7   p_U2270B_CFE =1 ;//    delay_2(516);//编程及确认时间5.6ms   */    WDT_CONTR = 0X3C;//喂狗     led_light = 0;    b.W = 0;    while(!(read_ok == 1))    {             //while(p_U2270B_OutPut);//等一个稳定的低电平?超时判断?              while(!p_U2270B_OutPut);//等待上升沿的到来同步信号检测1       TR0 = 1;      //deng xia jiang       while(p_U2270B_OutPut);//等待下降沿       TR0 = 0;   a.B.H = TH0;   a.B.L = TL0;   TH0 = TL0 = 0;   TR0 = 1;//定时器晚启动10个周期       //同步头       if((324 < a.W) && (a.W < 353)) ;//检测同步信号1                  else     {     TR0 = 0;     TH0 = TL0 = 0;     goto read_error;    }      //等待上升沿        while(!p_U2270B_OutPut);   TR0 = 0;   a.B.H = TH0;   a.B.L = TL0;   TH0 = TL0 = 0;   TR0 = 1;//b.N1<<=8;            if(a.B.L < 195);//0.5p       else     {     TR0 = 0;     TH0 = TL0 = 0;     goto read_error;    }      //读0~7块的数据       for(j = 0;j < 28;j++)      {       //uchar i;                  for(i = 0;i < 16;i++)//8个位        {        //等待下降沿的到来         while(p_U2270B_OutPut);                TR0 = 0;     a.B.H = TH0;     a.B.L = TL0;     TH0 = TL0 = 0;     TR0 = 1;              if(t2_max < a.W/*)&&(a.W < t2_max)*/)//1P          {         b.W >>= 2;//先左移再赋值          b.B.L += 0xc0;                             i++;        }        else if(t1_min < a.B.L/*)&&(a.B.L < t1_max)*/)//0.5p         {         b.W >>= 1;         b.B.L += 0x80;                           }        else      {      TR0 = 0;      TH0 = TL0 = 0;      goto read_error;     }        i++;        while(!p_U2270B_OutPut);//上升                   TR0 = 0;     a.B.H = TH0;     a.B.L = TL0;     TH0 = TL0 = 0;     TR0 = 1;                      if(t2_min < a.W/*)&&(a.W < t2_max)*/)//1P          {         b.W >>= 2;         i++;        }        else if(t1_min < a.B.L/*a.W)&&(a.B.L < t1_max)*/)//0.5P         //else if(!(a.W==0))         {         b.W >>= 1;         //temp+=0x00;          //led_light1=0;led_light=1;delay_2(40000);         }        else      {      TR0 = 0;      TH0 = TL0 = 0;      goto read_error;     }        i++;       }       //取出奇位        DATA = b.B.L;       BIT13 = BIT7;    BIT12 = BIT5;    BIT11 = BIT3;    BIT10 = BIT1;       DATA = b.B.H;       BIT17 = BIT7;    BIT16 = BIT5;    BIT15 = BIT3;    BIT14 = BIT1;       bankdata[j] = DATA1;      }              read_ok = 1;//读卡完成了     read_error:    _nop_();    }       }    /***************************************************/    void f_writecard(uchar x)//写卡     {    p_U2270B_CFE = 1;    delay_2(232);  //>2.5ms            //psw=0 standard write     if (x == write_command0)//写密码:初始化密码     {      uchar i;      uchar data *data p;      p = cominceptbuff;      p_U2270B_CFE = 0;   delay_2(31);//start gap>330us       write_bit(1);//写操作码1:10       write_bit(0);//写操作码0       write_bit(0);//写锁定位0       for(i = 0;i < 35;i++)      {       write_bit(1);//写数据位1       }      p_U2270B_CFE = 1;      led_light1 = 0;   led_light = 1;   delay_2(40000);//测试使用       //write_block(cominceptbuff[4],p);       p_U2270B_CFE = 1;      bankdata[20] = cominceptbuff[0];//密码存入       bankdata[21] = cominceptbuff[1];      bankdata[22] = cominceptbuff[2];      bankdata[23] = cominceptbuff[3];    }    else if (x == write_command1)//配置卡参数:初始化     {      uchar data *data p;      p = cominceptbuff;      write_bit(1);//写操作码1:10       write_bit(0);//写操作码0       write_bit(0);//写锁定位0               write_block(cominceptbuff[4],p);      p_U2270B_CFE=  1;    }    //psw=1  pssword mode     else if(x == write_command2)  //密码写数据    {      uchar data*data p;      p = &bankdata[24];      write_bit(1);//写操作码1:10       write_bit(0);//写操作码0       write_password(p);//发口令       write_bit(0);//写锁定位0       p = cominceptbuff;      write_block(cominceptbuff[4],p);//写数据            }    else if(x == write_command3)//aor    //唤醒 {      //cominceptbuff[1]操作码10 X xxxxxB       uchar data *data p;      p = cominceptbuff;      write_bit(1);//10       write_bit(0);             write_password(p);//密码       p_U2270B_CFE = 1;//此时数据不停的循环传出     }    else //停止操作码     {      write_bit(1);//11       write_bit(1);             p_U2270B_CFE = 1;         }    p_U2270B_CFE = 1;    delay_2(560);//5.6ms     }    /************************************/    void f_clearpassword()//清除密码     {    uchar data *data p;    uchar i,x;          p = &bankdata[24];//原密码     p_U2270B_CFE = 0; delay_2(18);//start gap>150us     //操作码10:10xxxxxxB     write_bit(1);    write_bit(0);              for(x = 0;x < 4;x++)//发原密码     {             DATA = *(p++);      for(i = 0;i < 8;i++)      {       write_bit(BIT0);       DATA >>= 1;      }    }    write_bit(0);//锁定位0:0     p = &cominceptbuff[0];    write_block(0x00,p);//写新配置参数:pwd=0             //密码无效:即清除密码     DATA = 0x00;//停止操作码00000000B     for(i = 0;i < 2;i++)    {    write_bit(BIT7);    DATA <<= 1;    }    p_U2270B_CFE = 1;       delay_2(560);//5.6ms     }    /*********************************/    void f_changepassword()//修改密码            {       uchar data *data p;    uchar i,x,addr;    addr = 0x07;//block7     p = &Nkey_a[0];//原密码     DATA = 0x80;//操作码10:10xxxxxxB     for(i = 0;i < 2;i++)    {      write_bit(BIT7);      DATA <<= 1;    }    for(x = 0;x < 4;x++)//发原密码     {             DATA = *(p++);      for(i = 0;i < 8;i++)      {       write_bit(BIT7);       DATA >>= 1;      }    }    write_bit(0);//锁定位0:0     p = &cominceptbuff[0];    write_block(0x07,p);//写新密码     p_U2270B_CFE = 1;    bankdata[24] = cominceptbuff[0];//密码存入     bankdata[25] = cominceptbuff[1];    bankdata[26] = cominceptbuff[2];    bankdata[27] = cominceptbuff[3];    DATA = 0x00;//停止操作码00000000B     for(i = 0;i < 2;i++)    {      write_bit(BIT7);      DATA <<= 1;    }    p_U2270B_CFE = 1;       delay_2(560);//5.6ms     }    /***************************子函数***********************************/    void write_bit(bit x)//写一位     {    if(x)    {      p_U2270B_CFE = 1;   delay_2(32);//448*11.0592/120=42延时448us       p_U2270B_CFE = 0;   delay_2(28);//280*11.0592/120=26写1     }    else    {      p_U2270B_CFE = 1;   delay_2(92);//192*11.0592/120=18       p_U2270B_CFE = 0;   delay_2(28);//280*11.0592/120=26写0     }    }    /*******************写一个block*******************/    void write_block(uchar addr,uchar data *data p)    {    uchar i,j;        for(i = 0;i < 4;i++)//block0数据     {             DATA = *(p++);      for(j = 0;j < 8;j++)      {       write_bit(BIT0);       DATA >>= 1;      }    }    DATA = addr <<= 5;//0地址     for(i = 0;i < 3;i++)    {      write_bit(BIT7);      DATA <<= 1;    }                   }    /*************************************************/    void write_password(uchar data *data p)    {    uchar i,j;        for(i = 0;i < 4;i++)//     {             DATA = *(p++);      for(j = 0;j < 8;j++)      {       write_bit(BIT0);       DATA >>= 1;      }    }        }   /*************************************************/   void main()    {    initial();    TI = RI = 0;    ES = 1;    EA = 1;  delay_2(28);   //f_readcard();     while(1) {   f_readcard();      //读卡   f_writecard(command1);  //写卡    f_clearpassword();   //清除密码     f_changepassword();    //修改密码 } }

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