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驱动<b>控制</b>系统

  • 主要用于数字仿真方面的代码

    主要用于数字仿真方面的代码,可以供做控制,系统辨识等方面的朋友参考。

    标签: 数字仿真 代码 方面

    上传时间: 2015-04-26

    上传用户:z754970244

  • 数字运算

    数字运算,判断一个数是否接近素数 A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no

    标签: 数字 运算

    上传时间: 2015-05-21

    上传用户:daguda

  • 源代码用动态规划算法计算序列关系个数 用关系"<"和"="将3个数a

    源代码\用动态规划算法计算序列关系个数 用关系"<"和"="将3个数a,b,c依次序排列时,有13种不同的序列关系: a=b=c,a=b<c,a<b=v,a<b<c,a<c<b a=c<b,b<a=c,b<a<c,b<c<a,b=c<a c<a=b,c<a<b,c<b<a 若要将n个数依序列,设计一个动态规划算法,计算出有多少种不同的序列关系, 要求算法只占用O(n),只耗时O(n*n).

    标签: lt 源代码 动态规划 序列

    上传时间: 2013-12-26

    上传用户:siguazgb

  • The government of a small but important country has decided that the alphabet needs to be streamline

    The government of a small but important country has decided that the alphabet needs to be streamlined and reordered. Uppercase letters will be eliminated. They will issue a royal decree in the form of a String of B and A characters. The first character in the decree specifies whether a must come ( B )Before b in the new alphabet or ( A )After b . The second character determines the relative placement of b and c , etc. So, for example, "BAA" means that a must come Before b , b must come After c , and c must come After d . Any letters beyond these requirements are to be excluded, so if the decree specifies k comparisons then the new alphabet will contain the first k+1 lowercase letters of the current alphabet. Create a class Alphabet that contains the method choices that takes the decree as input and returns the number of possible new alphabets that conform to the decree. If more than 1,000,000,000 are possible, return -1. Definition

    标签: government streamline important alphabet

    上传时间: 2015-06-09

    上传用户:weixiao99

  • Linux环境下编译通过

    Linux环境下编译通过,C++语言实现,命令驱动的教学管理系统,可以查看design文件夹下的FunctionalSpec.doc需求说明文档,使用文档是Usage_manual.doc。

    标签: Linux 环境 下编译

    上传时间: 2014-01-18

    上传用户:李梦晗

  • 上下文无关文法(Context-Free Grammar, CFG)是一个4元组G=(V, T, S, P)

    上下文无关文法(Context-Free Grammar, CFG)是一个4元组G=(V, T, S, P),其中,V和T是不相交的有限集,S∈V,P是一组有限的产生式规则集,形如A→α,其中A∈V,且α∈(V∪T)*。V的元素称为非终结符,T的元素称为终结符,S是一个特殊的非终结符,称为文法开始符。 设G=(V, T, S, P)是一个CFG,则G产生的语言是所有可由G产生的字符串组成的集合,即L(G)={x∈T* | Sx}。一个语言L是上下文无关语言(Context-Free Language, CFL),当且仅当存在一个CFG G,使得L=L(G)。 *⇒ 例如,设文法G:S→AB A→aA|a B→bB|b 则L(G)={a^nb^m | n,m>=1} 其中非终结符都是大写字母,开始符都是S,终结符都是小写字母。

    标签: Context-Free Grammar CFG

    上传时间: 2013-12-10

    上传用户:gaojiao1999

  • 使用硬盘制作mp3的源程序

    使用硬盘制作mp3的源程序,包含了硬盘驱动代码,文件系统,usb驱动,液晶驱动

    标签: mp3 硬盘 源程序

    上传时间: 2015-09-26

    上传用户:as275944189

  • AT89S52原理图AT89S52是一种低功耗、高性能CMOS8位微控制器

    AT89S52原理图AT89S52是一种低功耗、高性能CMOS8位微控制器,具有8K 在系统可编程 Flash 存储器。使用 Atmel 公司高密度非 易失性存储器技术制造,与工业 80C51 产品指令和引脚完全兼容。片上Flash允许程序储器在系统可编程,亦适于常规编程器。在单芯片上,拥有灵巧的 8 位 CPU 和在系统可编程Flash,使得 AT89S52为众多嵌入式控制应用系统提供高灵活、超有效的解决方案。

    标签: 89S S52 CMOS8 AT

    上传时间: 2013-12-25

    上传用户:qwe1234

  • We have a group of N items (represented by integers from 1 to N), and we know that there is some tot

    We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.

    标签: represented integers group items

    上传时间: 2016-01-17

    上传用户:jeffery

  • 利用EVC4.0编写的运行在Wince5.0上的应用程序

    利用EVC4.0编写的运行在Wince5.0上的应用程序,该应用程序使用S3C2410微控制器的IO驱动,控制IO口电平的置高或置低。

    标签: Wince EVC 4.0 5.0

    上传时间: 2014-12-06

    上传用户:klin3139