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有源<b>相控阵</b>

  • 题目:利用条件运算符的嵌套来完成此题:学习成绩>=90分的同学用A表示

    题目:利用条件运算符的嵌套来完成此题:学习成绩>=90分的同学用A表示,60-89分之间的用B表示,60分以下的用C表示。 1.程序分析:(a>b)?a:b这是条件运算符的基本例子。

    标签: gt 90 运算符 嵌套

    上传时间: 2015-01-08

    上传用户:lifangyuan12

  • Windows网络封包与截获技术的配套光盘

    Windows网络封包与截获技术的配套光盘,内有源码

    标签: Windows 网络 光盘

    上传时间: 2014-01-16

    上传用户:ikemada

  • c语言的教程

    c语言的教程,内有源码

    标签: c语言 教程

    上传时间: 2013-12-18

    上传用户:talenthn

  • DES算法BCB组件

    DES算法BCB组件,有源码,DELPHI也可以用。

    标签: DES BCB 算法

    上传时间: 2015-03-10

    上传用户:shizhanincc

  • RSA算法 :首先, 找出三个数, p, q, r, 其中 p, q 是两个相异的质数, r 是与 (p-1)(q-1) 互质的数...... p, q, r 这三个数便是 person_key

    RSA算法 :首先, 找出三个数, p, q, r, 其中 p, q 是两个相异的质数, r 是与 (p-1)(q-1) 互质的数...... p, q, r 这三个数便是 person_key,接著, 找出 m, 使得 r^m == 1 mod (p-1)(q-1)..... 这个 m 一定存在, 因为 r 与 (p-1)(q-1) 互质, 用辗转相除法就可以得到了..... 再来, 计算 n = pq....... m, n 这两个数便是 public_key ,编码过程是, 若资料为 a, 将其看成是一个大整数, 假设 a < n.... 如果 a >= n 的话, 就将 a 表成 s 进位 (s

    标签: person_key RSA 算法

    上传时间: 2013-12-14

    上传用户:zhuyibin

  • arm芯 ucos 下的开发框架

    arm芯 ucos 下的开发框架,有源码,值得参考 下载

    标签: ucos arm

    上传时间: 2015-04-08

    上传用户:R50974

  • 一个好的基于VC++的音频文件播放器

    一个好的基于VC++的音频文件播放器,有源码,大家值得一看哦

    标签: 音频文件 播放器

    上传时间: 2015-04-14

    上传用户:dbs012280

  • 一个好的基于VC++和DSound的语音播放软件

    一个好的基于VC++和DSound的语音播放软件,有源码,不可不看哦

    标签: DSound 语音 播放 软件

    上传时间: 2015-04-14

    上传用户:www240697738

  • 数字运算

    数字运算,判断一个数是否接近素数 A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no

    标签: 数字 运算

    上传时间: 2015-05-21

    上传用户:daguda

  • The government of a small but important country has decided that the alphabet needs to be streamline

    The government of a small but important country has decided that the alphabet needs to be streamlined and reordered. Uppercase letters will be eliminated. They will issue a royal decree in the form of a String of B and A characters. The first character in the decree specifies whether a must come ( B )Before b in the new alphabet or ( A )After b . The second character determines the relative placement of b and c , etc. So, for example, "BAA" means that a must come Before b , b must come After c , and c must come After d . Any letters beyond these requirements are to be excluded, so if the decree specifies k comparisons then the new alphabet will contain the first k+1 lowercase letters of the current alphabet. Create a class Alphabet that contains the method choices that takes the decree as input and returns the number of possible new alphabets that conform to the decree. If more than 1,000,000,000 are possible, return -1. Definition

    标签: government streamline important alphabet

    上传时间: 2015-06-09

    上传用户:weixiao99