RSA算法 :首先, 找出三个数, p, q, r, 其中 p, q 是两个相异的质数, r 是与 (p-1)(q-1) 互质的数...... p, q, r 这三个数便是 person_key，接著, 找出 m, 使得 r^m == 1 mod (p-1)(q-1)..... 这个 m 一定存在, 因为 r 与 (p-1)(q-1) 互质, 用辗转相除法就可以得到了..... 再来, 计算 n = pq....... m, n 这两个数便是 public_key ，编码过程是, 若资料为 a, 将其看成是一个大整数, 假设 a < n.... 如果 a >= n 的话, 就将 a 表成 s 进位 (s
标签： person_key RSA 算法
上传时间： 2013-12-14
上传用户：zhuyibin
Matlab加扰解扰仿真系统，可以观察加解扰前后信号的时域和频域波形，有助于理解扰码的概念和解扰的过程
上传时间： 2015-04-21
上传用户：zukfu
caiyang 演示采样定理，时域采样，频谱周期延拓
上传时间： 2014-01-24
上传用户：qoovoop
数字运算，判断一个数是否接近素数 A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no
上传时间： 2015-05-21
上传用户：daguda
·Matlab加扰解扰仿真系统，可以观察加解扰前后信号的时域和频域波形，有助于理解扰码的概念和解扰的过程
上传时间： 2015-06-06
上传用户：康郎
The government of a small but important country has decided that the alphabet needs to be streamlined and reordered. Uppercase letters will be eliminated. They will issue a royal decree in the form of a String of B and A characters. The first character in the decree specifies whether a must come ( B )Before b in the new alphabet or ( A )After b . The second character determines the relative placement of b and c , etc. So, for example, "BAA" means that a must come Before b , b must come After c , and c must come After d . Any letters beyond these requirements are to be excluded, so if the decree specifies k comparisons then the new alphabet will contain the first k+1 lowercase letters of the current alphabet. Create a class Alphabet that contains the method choices that takes the decree as input and returns the number of possible new alphabets that conform to the decree. If more than 1,000,000,000 are possible, return -1. Definition
标签： government streamline important alphabet
上传时间： 2015-06-09
上传用户：weixiao99
一个酒店客房管理的数据库设计过程，包括问题域的分析和具体在Microsoft SQL sercer 2000上的实现过程
上传时间： 2014-01-22
上传用户：1966640071
主要利用Matlab工具箱实现数字图像融合：手动配准，模拟时域加权函数，Mask法图像融合。
上传时间： 2015-07-06
上传用户：sxdtlqqjl
已知单位负反馈系统被控对象的传函为: • 设计滞后-超前校正装置,使校正后的系统满足: • (1).在单位斜坡信号作用下,Kv=10s^(-1) • (2).校正后相角裕度³ 45° • (3).系统校正后剪切频率wc ³ 1.5s^(-1) • (4).时域性能指标:s％£ 30％,Tp £ 2s,Ts £ 6s
上传时间： 2014-07-27
上传用户：qlpqlq
建立了OFDM系统仿真平台，主要可以测试时域滤波信道估计方式下系统的误码率性能
上传时间： 2015-08-29
上传用户：qiao8960
