虫虫首页| 资源下载| 资源专辑| 精品软件
登录| 注册

可<b>编程</b>时钟

  • 源代码用动态规划算法计算序列关系个数 用关系"<"和"="将3个数a

    源代码\用动态规划算法计算序列关系个数 用关系"<"和"="将3个数a,b,c依次序排列时,有13种不同的序列关系: a=b=c,a=b<c,a<b=v,a<b<c,a<c<b a=c<b,b<a=c,b<a<c,b<c<a,b=c<a c<a=b,c<a<b,c<b<a 若要将n个数依序列,设计一个动态规划算法,计算出有多少种不同的序列关系, 要求算法只占用O(n),只耗时O(n*n).

    标签: lt 源代码 动态规划 序列

    上传时间: 2013-12-26

    上传用户:siguazgb

  • The government of a small but important country has decided that the alphabet needs to be streamline

    The government of a small but important country has decided that the alphabet needs to be streamlined and reordered. Uppercase letters will be eliminated. They will issue a royal decree in the form of a String of B and A characters. The first character in the decree specifies whether a must come ( B )Before b in the new alphabet or ( A )After b . The second character determines the relative placement of b and c , etc. So, for example, "BAA" means that a must come Before b , b must come After c , and c must come After d . Any letters beyond these requirements are to be excluded, so if the decree specifies k comparisons then the new alphabet will contain the first k+1 lowercase letters of the current alphabet. Create a class Alphabet that contains the method choices that takes the decree as input and returns the number of possible new alphabets that conform to the decree. If more than 1,000,000,000 are possible, return -1. Definition

    标签: government streamline important alphabet

    上传时间: 2015-06-09

    上传用户:weixiao99

  • 电力系统在台稳定计算式电力系统不正常运行方式的一种计算。它的任务是已知电力系统某一正常运行状态和受到某种扰动

    电力系统在台稳定计算式电力系统不正常运行方式的一种计算。它的任务是已知电力系统某一正常运行状态和受到某种扰动,计算电力系统所有发电机能否同步运行 1运行说明: 请输入初始功率S0,形如a+bi 请输入无限大系统母线电压V0 请输入系统等值电抗矩阵B 矩阵B有以下元素组成的行矩阵 1正常运行时的系统直轴等值电抗Xd 2故障运行时的系统直轴等值电抗X d 3故障切除后的系统直轴等值电抗 请输入惯性时间常数Tj 请输入时段数N 请输入哪个时段发生故障Ni 请输入每时段间隔的时间dt

    标签: 电力系统 计算 运行

    上传时间: 2015-06-13

    上传用户:it男一枚

  • Vxworks下TCP通信的源程序

    Vxworks下TCP通信的源程序,可作为编程参考

    标签: Vxworks TCP 通信 源程序

    上传时间: 2015-06-27

    上传用户:wangzhen1990

  • 可以从计算机向WINBOND516直接下载程序的源码

    可以从计算机向WINBOND516直接下载程序的源码,调试单片机用,可不用编程哭

    标签: WINBOND 516 计算机 下载程序

    上传时间: 2015-07-19

    上传用户:zhuoying119

  • 这是一本关于VC++的书

    这是一本关于VC++的书,可供编程人员参考使用。

    标签: VC

    上传时间: 2015-08-10

    上传用户:ayfeixiao

  • 优盘读写子程序,芯片是SL811

    优盘读写子程序,芯片是SL811,单片机是80C196,不是很全,但可作为编程参考。

    标签: 811 SL 读写 程序

    上传时间: 2015-08-20

    上传用户:731140412

  • 演示matlab曲线拟和与插直的基本方法

    演示matlab曲线拟和与插直的基本方法,详细的工具箱可供编程人员使用

    标签: matlab

    上传时间: 2015-08-25

    上传用户:daguda

  • 摘要:AD9852是美国ANALOGDEVICES公司生产的新型直接数字频率合成器(DDS)

    摘要:AD9852是美国ANALOGDEVICES公司生产的新型直接数字频率合成器(DDS),具有频率转换速度快(小于lt~s)、频谱纯度高、工作温度范围宽(一25℃~+85℃)、集成度高等特点,是一种使用方便灵活、功能较强的芯片。AD9852由带有48位相位累加的数控振荡器、可墒程参考时钟倍乘器、反向正弦滤波器、计数倍乘器、两个300MHz12住数模转换器、高速模拟比较器和接口逻辑组成。可用于本振合成回路,高精度时钟发生器和FSK//3PSK调制。文中介绍了AD9852的工作原理、引脚功能以厦具体应用。

    标签: ANALOGDEVICES 9852 DDS AD

    上传时间: 2015-11-30

    上传用户:kiklkook

  • We have a group of N items (represented by integers from 1 to N), and we know that there is some tot

    We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.

    标签: represented integers group items

    上传时间: 2016-01-17

    上传用户:jeffery