代码搜索:while

找到约 10,000 项符合「while」的源代码

代码结果 10,000
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lst gg.lst

C51 COMPILER V8.05a GG 10/04/2007 17:46:28 PAGE 1 C51 COMPILER V8.05a, COMPILATION OF MODULE GG OBJECT MODULE PLACED IN gg.
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c gg.c

//proteus仿真论坛:proteus.5d6d.com #include #include #include sbit DI=P2^2; // 数据\指令 选择 sbit RW=P2^1; // 读\写 选择 sbit E=P2^0; // 读\写使能 sbit CS1=P2^4; // 片选1 sbit C
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cpp cross.cpp

#include ifstream in; ofstream out; #define cin in #define cout out #include int r,c,w; #define MAXR 60 #define MAXC 60 #define MAXW 310 #define bool int #define tr
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cpp 1265 floating point presentation.cpp

#include using namespace std; int main() { int n,t,i,j,p; unsigned int e ,m[23]; float f; scanf("%d",&n); while(n--) { scanf("%f",&f); for(i=0;i
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cpp 1628 roman roulette.cpp

#include using namespace std; int cir[101]; int main() { int i,j,n,k,now,die; while( scanf("%d %d",&n ,&k)==2 && (n != 0 || k != 0)) { for(i=1;i
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cpp 1052 tian ji -- the horse racing.cpp

//贪心 #include #include using namespace std; int n,m; int t[1100],k[1100]; int main() { int i,j,i2,j2; while(scanf("%d",&n)==1 && n) { for(i=0;i
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cpp 1113 word amalgamation.cpp

/* 1113 Word Amalgamation Time Limit : 1000 ms Memory Limit : 32768 K Output Limit : 5120 K GUN C++ */ #include #include using namespace std; const int Max=101; ch
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bak 8.bak

main( ) { int a[11] , l , h , m , y , x , *p ; for ( y=1 ; y
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c 12.5 求约束条件下n维极值的复形调优法 cplx.c

#include "stdlib.h" int cplx(n,m,a,b,alpha,eps,x,xx,k,s,f) int n,m,k; void (*s)(); double a[],b[],alpha,eps,x[],xx[],(*f)(); { double rn(double *); int r,g,i,j,it,kt,jt,kk;
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c 5.2 求对称三对角阵的全部特征值与特征向量 sstq.c

#include "stdio.h" #include "math.h" int sstq(n,b,c,q,eps,l) int n,l; double b[],c[],q[],eps; { int i,j,k,m,it,u,v; double d,f,h,g,p,r,e,s; c[n-1]=0.0; d=0.0; f=0.0; for (j=0;