📄 5.2 求对称三对角阵的全部特征值与特征向量 sstq.c
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#include "stdio.h"
#include "math.h"
int sstq(n,b,c,q,eps,l)
int n,l;
double b[],c[],q[],eps;
{
int i,j,k,m,it,u,v;
double d,f,h,g,p,r,e,s;
c[n-1]=0.0; d=0.0; f=0.0;
for (j=0; j<=n-1; j++)
{
it=0;
h=eps*(fabs(b[j])+fabs(c[j]));
if (h>d) d=h;
m=j;
while ((m<=n-1)&&(fabs(c[m])>d)) m=m+1;
if (m!=j)
{
do
{
if (it==l) printf("fail\n");
return(-1);
}
it=it+1;
g=b[j];
p=(b[j+1]-g)/(2.0*c[j]);
r=sqrt(p*p+1.0);
if(p>=0.0) b[j]=c[j]/(p+r);
else b[j]=c[j]/(p-r);
h=g-b[j];
for (i=j+1; i<=n-1; i++)
b[i]=b[i]-h;
f=f+h;
p=b[m];
e=1.0;
s=0.0;
for (i=m-1; i>=j; i--)
{
g=e*c[i]; h=e*p;
if (fabs(p)>=fabs(c[i]))
{
e=c[i]/p; r=sqrt(e*e+1.0);
c[i+1]=s*p*r; s=e/r; e=1.0/r;
}
else
{
e=p/c[i]; r=sqrt(e*e+1.0);
c[i+1]=s*c[i]*r;
s=1.0/r; e=e/r;
}
p=e*b[i]-s*g;
b[i+1]=h+s*(e*g+s*b[i]);
for (k=0; k<=n-1; k++)
{
u=k*n+i+1; v=u-1;
h=q[u]; q[u]=s*q[v]+e*h;
q[v]=e*q[v]-s*h;
}
}
c[j]=s*p; b[j]=e*p;
}while (fabs(c[j])>d);
}
b[j]=b[j]+f;
}
for (i=0; i<=n-1; i++)
{
k=i; p=b[i];
if (i+1<=n-1)
{
j=i+1;
while ((j<=n-1)&&(b[j]<=p))
{
k=j; p=b[j]; j=j+1;
}
}
if (k!=i)
{
b[k]=b[i]; b[i]=p;
for (j=0; j<=n-1; j++)
{
u=j*n+i; v=j*n+k;
p=q[u]; q[u]=q[v]; q[v]=p;
}
}
}
return(1);
}
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