代码搜索:singular

找到约 750 项符合「singular」的源代码

代码结果 750
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c singular.c

#include #include #include #include "pbc_field.h" #include "pbc_curve.h" #include "pbc_fops.h" #include "pbc_pairing.h" #include "pbc_fp.h" #include "pbc_memory.h" #includ
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cpp singular.cpp

// Copyright Daniel Wallin 2005. Use, modification and distribution is // subject to the Boost Software License, Version 1.0. (See accompanying // file LICENSE_1_0.txt or copy at http://www.boost.org/
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m matrix_singular.m

% matrix_singular.m % 求解非奇异线性方程组的解 A=[1 3 7;-1 4 4;1 10 18]; y=[6;4;15]; % 方法一:通过矩阵左除来求解线性方程组的解 x_1=A\y; % 方法二:判断A的条件数,A的秩以及增广矩阵【A y】的秩 det_A=det(A) rank_A=rank(A) rank_Ay=rank([A y]) cond_A
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h fred_singular.h

template struct Wwghts { Doub h; Int n; Q &quad; VecDoub wghts; Wwghts(Doub hh, Int nn, Q &q) : h(hh), n(nn), quad(q), wghts(n) {} VecDoub weights() { Int k; Doub fac;
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m matrix_singular.m

% matrix_singular.m % 求解非奇异线性方程组的解 A=[1 3 7;-1 4 4;1 10 18]; y=[6;4;15]; % 方法一:通过矩阵左除来求解线性方程组的解 x_1=A\y; % 方法二:判断A的条件数,A的秩以及增广矩阵【A y】的秩 det_A=det(A) rank_A=rank(A) rank_Ay=rank([A y]) cond_A
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m iteration_singular.m

%%%%%%%%%%%%%%%%%%%%%% %% Main Function function Matrix( ) fprintf(' -------------------------------------------- \n'); fid = fopen('matrix.txt', 'r'); A = fscanf(fid, '%5f', [8 8])
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h pbc_singular.h

//requires // * stdio.h // * gmp.h // * field.h #ifndef __PBC_SINGULAR_H__ #define __PBC_SINGULAR_H__ void field_init_curve_singular_with_node(field_t c, field_t field); void pairing_init_singular_wi
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h hp_singular.h

// $Id: hp_singular.h 2501 2007-11-20 02:33:29Z benkirk $ // The libMesh Finite Element Library. // Copyright (C) 2002-2007 Benjamin S. Kirk, John W. Peterson // This library is free software; yo
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c hp_singular.c

// $Id: hp_singular.C 2501 2007-11-20 02:33:29Z benkirk $ // The libMesh Finite Element Library. // Copyright (C) 2002-2007 Benjamin S. Kirk, John W. Peterson // This library is free software; yo
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m matrix_non_singular.m

% matrix_non_singular.m % 求解非奇异线性方程组的解 A=[1 2 3;4 5 6;7 8 0]; y=[366;804;351]; % 方法一:判断A的条件数,A的秩以及增广矩阵【A y】的秩 rank(A) rank([A y]) cond(A) x_1=inv(A)*y; % 方法二:通过矩阵左除来求解线性方程组的解 x_2=A\y; % 输出结