代码搜索：montecarlo
找到约 154 项符合「montecarlo」的源代码
代码结果 154
www.eeworm.com/read/382499/9024042
cuh montecarlo_kernel.cuh
/*
* Copyright 1993-2007 NVIDIA Corporation. All rights reserved.
*
* NOTICE TO USER:
*
* This source code is subject to NVIDIA ownership rights under U.S. and
* international Copyright l
www.eeworm.com/read/365441/9863216
m montecarlo_pi.m
%求pi的程序
n=input('n=?');%总次数
m=input('m=?');%步长
k=1;
j=1;
h=0;
for i=1:n
x=rand();y=rand();
rxy=x.^2+y.^2;
if rxy
www.eeworm.com/read/365441/9863218
m montecarlo_area.m
%求两曲线间的面积第一种方法
n=input('n=?');%总数
m=input('m=?');%步长
k=1;
j=1;
h=0;%求两曲线间的面积
for i=1:n
x=3*rand();y=30*rand();
f1=0.3*x.^4+0.5*x.^3-x.^2-x+2;
f2=-0.8*x.^2+0.5*x+3;
if ((y
www.eeworm.com/read/365441/9863221
m montecarlo_function.m
x=norminv(P,mu,sigma)% 正态逆累积分布函数
x=expinv(p,mu) %指数逆累积分布函数
x=weibinv(p,a,b)% 威布尔逆累积分布函数
x=logninv(p,mu,sigma)%对数正态逆累积分布函数
chi2inv(p,a,b)%卡方逆累积分布函数
x=betainv(p,a,b)%β分布逆累积分布函数
unifrnd(-1,1,3,3)%产
www.eeworm.com/read/365441/9863225
m montecarlo_multintegral.m
clear all
n=input('n=?');%计算多重积分
B=[5,5,5,5,2*pi,2*pi,2*pi,2*pi];
SNR=11.2415;
D0=sqrt(2*10^(SNR/10));
D1=0.5*D0;
D2=D0;
D3=0.5*D0;
D4=0;
a=1/(10*(pi)^5);
b=-2/5;
c=4*D1-3*D2+2*D3-
www.eeworm.com/read/436824/7762184
m lmm_montecarlo.m
clear all;
global tau;
%----------------------------- parameters
tau = 1; %accrual time
alpha=5; %start peg of swap
beta=9; %end peg of swap
dt=1; %time-step of monte carlo simulation
N=10;
www.eeworm.com/read/336465/12442042
nlogo ---montecarlo-area.nlogo
globals [mc-area
normal-area
mc-error
error-list
areas-list
mc-area-max
mean-error
mean-standard-deviation
MCS]
to setup-plots
www.eeworm.com/read/279486/4136272
m montecarlo_bic.m
function bicv = MonteCarlo_bic(trajs,Ops)
%MonteCarlo_bic Run BIC on random subsets of a large dataset.
% BICV = MonteCarlo_bic(Trajs,Ops)
%
% Scott J Gaffney 20 November 2003
% Department
www.eeworm.com/read/382499/9024015
cu montecarlo_sm10.cu
/*
* Copyright 1993-2007 NVIDIA Corporation. All rights reserved.
*
* NOTICE TO USER:
*
* This source code is subject to NVIDIA ownership rights under U.S. and
* international Copyright l