代码搜索:implementing

找到约 2,669 项符合「implementing」的源代码

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www.eeworm.com/read/185622/9013171

txt rfc1936.txt

Network Working Group J. Touch Request For Comments: 1936 B. Parham Category: Informational
www.eeworm.com/read/465477/6937647

txt rfc1936.txt

Network Working Group J. Touch Request For Comments: 1936 B. Parham Category: Informational
www.eeworm.com/read/340734/12137734

txt readme.txt

Files of the sub-directory \SOURCE\MICRO\8051\TR8051 This project is a TMEX example program written in 8051 Assembly. It is a Stand-alone piece of software implementing all functions up to
www.eeworm.com/read/340734/12137749

txt readme.txt

Files of the sub-directory \SOURCE\MICRO\808x\TR808x This project is a TMEX example program written in 808x Assembly. It is a Stand-alone piece of software implementing all functions up to
www.eeworm.com/read/224165/14603269

h visimsrciface.h

//////////////////////////////////////////////////////////////////////////// // // @doc INTERNAL EXTERNAL VISIMSRCIFACE // // @module VisImSrcIFace.h | // // This file defines standard interface
www.eeworm.com/read/171081/5398637

svn-base contrib.txt.svn-base

Contributions to Agobot3: Num - Name - What 1. - Ago - Writing Agobot3 base, being the author/maintainer 2. - Fight - Hosting my testing bots 3. - killer77 - Donating money to make Agobot3 as
www.eeworm.com/read/202015/15391049

txt ver-highspeed_io_readme-v1.0.0p1.txt

Implementing High-Speed Differential I/O Capability in Stratix Devices v1.0.0 README File This readme file for the Implementing High-Speed Differential I/O Capability in Stratix Devices includes
www.eeworm.com/read/112400/15487640

txt rfc1936.txt

Network Working Group J. Touch Request For Comments: 1936 B. Parham Category: Informational
www.eeworm.com/read/106679/15628810

txt rfc1936.txt

Network Working Group J. Touch Request For Comments: 1936 B. Parham Category: Informational
www.eeworm.com/read/279052/10474233

c csetest.c

/* csetest.c - An example of implementing cse optimization */ #include void funct1(int a, int b) { int c = a * b; int d = (a * b) / 5; int e = 500 / (a * b); printf("The results