代码搜索：conditional
找到约 2,177 项符合「conditional」的源代码
代码结果 2,177
www.eeworm.com/read/101082/6249111
y awk.g.y
/* @(#)awk.g.y 4.1 ULTRIX 7/17/90 */
/*************************************************
* Modification History
*
* 11-Jan-89 Tim N
* Put in 4.3-5 fix for dumping core on syntax error.
* Put in t
www.eeworm.com/read/490316/6454432
m lab2.m
% close all
% clear all
% time=0:0.01:30;
%
% [t,y]=ODE45('lorenc',time,[5 5 5]);
%
% % figure, plot(t,y(:,1))
% % figure, plot(t,y(:,2))
% % figure, plot(t,y(:,3))
% %
% % figure, plot
www.eeworm.com/read/410432/11287362
c ifdef.c
/* ifdef.c -- uses conditional compilation */
#include
#define JUST_CHECKING
#define LIMIT 4
int main(void)
{
int i;
int total = 0;
for (i = 1; i
www.eeworm.com/read/410432/11287630
c paint.c
/* paint.c -- uses conditional operator */
#include
#define COVERAGE 200 /* square feet per paint can */
int main(void)
{
int sq_feet;
int cans;
printf("Enter numb
www.eeworm.com/read/400541/11574690
txt support.txt
supported mnemonics: (2001-03-09)
aaa
aad
aam
aas
adc
add
arpl
bsf
bsr
bswap
call
cbw
cdq
clc
cld
cli
clts
cmc
cmpsb
cmpsw
cmpsd
cpuid
cwd
cwde
daa
das
dec
div
enter
www.eeworm.com/read/343227/11962871
m hmm_psim.m
function s = hmm_psim (X, A, pi0, mu, Sigma, QUIET)
%hmm_psim Generates a random sequence of conditional HMM states.
% Use: s = hmm_psim(X,A,pi0,mu,Sigma) where s is a sequence of states
% of the HM
www.eeworm.com/read/210806/15192054
v equ_inequ.v
module equ_inequ();
reg [3:0] a, b, c, d, e, f;
initial begin
a=3; b=6; // decimal values
c = 4'b011;
d = 4'bx11;
e = 4'bx110;
f = 4'bxx10;
$display (a==b); //l
www.eeworm.com/read/162614/5522037
c 900324_02.c
// { dg-do assemble }
// g++ 1.37.1 bug 900324_02
// The following erroreous code causes g++ to segfault.
// Cfront 2.0 passes this test.
// keywords: segfault, function pointer, conditional opera
www.eeworm.com/read/162614/5528053
c struct-non-lval-2.c
/* Bug c/17855, using conditional expression for non-lvalue. */
struct foo {char x, y, z[2];};
struct foo p, q; int r;
void bar(int baz)
{
(r ? p : q).z[baz] = 1;
}