代码搜索：Square
找到约 8,911 项符合「Square」的源代码
代码结果 8,911
www.eeworm.com/read/300378/13916803
m program_13_17.m
%装载并显示原始图像
load belmont2;
subplot(2,2,1);
image(X);colormap(map);title('原始图像 ');axis square;
disp('压缩前图像的大小：');
whos('X')
%对图像进行7层小波分解
[c,l]=wavedec2(X,2,'bior3.7');
%提取小波分解结构中的一层的低频系数和高频系数
c
www.eeworm.com/read/235003/14089246
m examp13_17.m
%装载并显示原始图像
load belmont2;
subplot(2,2,1);
image(X);colormap(map);title('原始图像 ');axis square;
disp('压缩前图像的大小：');
whos('X')
%对图像进行7层小波分解
[c,l]=wavedec2(X,2,'bior3.7');
%提取小波分解结构中的一层的低频系数和高频系数
c
www.eeworm.com/read/455033/7378641
edp lame.edp
// file lame.edd
mesh Th=square(10,10,[20*x,2*y-1]);
fespace Vh(Th,P2);
Vh u,v,uu,vv;
real sqrt2=sqrt(2.);
macro epsilon(u1,u2) [dx(u1),dy(u2),(dy(u1)+dx(u2))/sqrt2] // EOM
// remark the $1/\sqrt2$ i
www.eeworm.com/read/455033/7378684
edp laplace3d.edp
load "msh3"
load "medit"
int nn=8;
mesh Th2=square(nn,nn);
fespace Vh2(Th2,P2);
Vh2 ux,uz,p2;
int[int] rup=[0,2], rdown=[0,1], rmid=[1,1,2,1,3,1,4,1];
real zmin=0,zmax=1;
mesh3 Th=buildlayers(Th2,nn
www.eeworm.com/read/455033/7378695
edp stokes.edp
load "msh3" load "medit"
int nn=8;
mesh Th2=square(nn,nn);
fespace Vh2(Th2,P2); Vh2 ux,uz,p2;
int[int] rup=[0,2], rdown=[0,1], rmid=[1,1,2,1,3,1,4,1];
real zmin=0,zmax=1;
mesh3 Th=buildlayers(Th2,nn
www.eeworm.com/read/455033/7378708
edp nsi3d.edp
load "msh3"
real nu=0.01,dt=0.3;
real alpha=1./dt,alpha2=sqrt(alpha);
int nn=5;
mesh Th2=square(nn,nn);
fespace Vh2(Th2,P2);
Vh2 ux,uz,p2;
int[int] rup=[0,2], rdown=[0,1], rmid=[1,1,2,1,3,1,4,1];
r
www.eeworm.com/read/455033/7379406
edp splitmesh6.edp
load "splitmesh6"
mesh Th=square(5,5);
mesh Th6=splitmesh6(Th);
plot(Th6,wait=1);
fespace Vh(Th,P1);
fespace Nh(Th,P0);
fespace Vh6(Th6,P1);
fespace Nh6(Th6,P0);
fespace RT6(Th6,RT0); // Raviart Tho
www.eeworm.com/read/333698/12664540
m kmeanlbg.m
function [x,esq,j] = kmeanlbg(d,k)
%KMEANLBG Linde-Buzo-Gray 舅绊府硫阑 捞侩茄 氦磐 剧磊拳 [X,ESQ,J]=(D,K)
%涝仿 牢磊:
% D 单捞磐 氦磐(one per row)
% K 吝缴 肮荐
%
%免仿 牢磊:
% X 免仿 凯 氦磐(K 俺狼 凯)
% ESQ 乞闭 磊铰 坷瞒(mean square
www.eeworm.com/read/494312/6382121
m project_2.m
%项目二 连续系统的频域分析
%线性系统为;H(jw)=1/(jw+1);输入信号为周期矩形波
%画双边幅度频谱
tau_T = 1/4; %占空比
n = -20:20;
t = -3:0.01:3;
A = 2;
T = 2;
f_t = A*0.5*(square(pi*t,25)+1); %占空比为25%的方波
F_n = tau_T*sinc(tau_T*n*pi
www.eeworm.com/read/487114/6523716
m polyphase.m
close all
clear all;
clc;
N=512;
M=32;
K=16;
n=1:N;
f1=600;
f2=5;
fs=2000;
t=-1:1/fs:1;
t1=0.2;
t2=0.5;
x1=sin(2*pi*f1*t);
% x2=square(2*pi*f2*t,20);
% x2=sawtooth(2*pi*f2*t,0.5);