代码搜索：Disc

找到约 1,656 项符合「Disc」的源代码

代码结果 1,656
热门代码： main.c GPIO I2C SPI UART timer interrupt ADC PWM LED
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html toc.html

Shell &
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www.eeworm.com/read/295249/8178231

html toc.html

Rationale: D
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www.eeworm.com/read/295249/8178285

html contents.html

Rationale: T
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www.eeworm.com/read/192739/8289101

c al4_6.c

/*案例代码文件名：AL4_6.C。*/ /*功能：求一元二次方程的解。*/ #include "math.h" main() { float a,b,c,disc,x1,x2,p,q; scanf("%f,%f,%f", &a, &b, &c); /*输入一元二次方程的系数a，b，c*/ disc=b*b-4*a*c; if (fabs(disc)
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www.eeworm.com/read/192739/8289140

c al3_11.c

/*案例代码文件名：AL3_11.C。*/ /*功能：设计一个顺序结构程序，求方程的根。*/ #include "math.h" /*为使用求平方根函数sqrt()，包含math.h头文件 */ main() {float a,b,c,disc,x1,x2; printf("Input a, b, c: "); scanf("%f,%f,%f",&a,&b,&c);
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www.eeworm.com/read/174062/9610000

c ch4_17.c

/*ch4_17*/ /*求方程ax2+bx+c=0的实数根。a，b，c由键盘输入(a≠ 0且b2-4ac>0)*/ #include #include "math.h" /*包含math.h头文件,为使用求平方根函数sqrt()*/ main() { float a,b,c,disc,x1,x2; printf("Input
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www.eeworm.com/read/174062/9610005

c ch5_6.c

/*ch5_6*/ /*求一元二次方程ax2+bx+c=0的解（a≠ 0）*/ #include #include "math.h" main() { float a,b,c,disc,x1,x2,p,q; scanf("%f,%f,%f", &a, &b, &c); disc=b*b-4*a*c; if (fabs(dis
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www.eeworm.com/read/171002/9776641

txt load.txt

connect -c uja -y erase write -b 1 -f out.ihx -intel -ver write -b 2 -f protect_word.bin -binary -a FE -ver disc
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www.eeworm.com/read/415537/11064753

txt copy x box games!.txt

BURNING X-BOX & GAMECUBE GAMES USEING CDRWIN ------------------------------------------------------ 1) Insert your original in your CD-ROM. 2) Open CDRWin (or any other image extractor) to make an
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www.eeworm.com/read/266116/11239963

cpp demo_1_io_simple.cpp

//*************************************************** // 标准输入输出流: cin cout cerr clog //*************************************************** //# include //# include # in
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