代码搜索:递归回溯
找到约 2,805 项符合「递归回溯」的源代码
代码结果 2,805
www.eeworm.com/read/363342/9958166
c 阶乘递归.c
#include
int factr(int n)
{
int result,r;
if (n==1) return 1;
result=factr(n-1)*n;
return result;
}
main()
{
int a;
a=factr(5);
printf("%d",a);
}
www.eeworm.com/read/363342/9958205
c 链表(递归).c
#include
#include
struct listNode{
int data;
struct listNode *nextPtr;
};
typedef struct listNode LISTNODE;
typedef LISTNODE * LISTNODEPTR;
LISTNODEPTR list(LISTNODEPTR , int); /
www.eeworm.com/read/363342/9958220
c 递归车厢.c
/**********递归题改为非递归题实例 车厢********/
#include
#define MAX 4
int stack[MAX],p=-1;
struct
{
int num;
int sign;
}train[MAX];
void sub()
{
int inc;
if(p==MAX-
www.eeworm.com/read/167125/9980251
c 链表(递归).c
#include
#include
struct listNode{
int data;
struct listNode *nextPtr;
};
typedef struct listNode LISTNODE;
typedef LISTNODE * LISTNODEPTR;
LISTNODEPTR list(LISTNODEPTR , int); /
www.eeworm.com/read/163189/10172083
txt 6.5递归.txt
STACK EQU 1FH
BOTTOM EQU 00H
M EQU 200
TOP DATA 3EH
N DATA 30H
NFACT EQU 31H
TST:
MOV SP,#5FH
LCALL SETNULL
MOV N,#5
LCALL FACT0
www.eeworm.com/read/424315/10464567
txt 6.5递归.txt
STACK EQU 1FH
BOTTOM EQU 00H
M EQU 200
TOP DATA 3EH
N DATA 30H
NFACT EQU 31H
TST:
MOV SP,#5FH
LCALL SETNULL
MOV N,#5
LCALL FACT0
www.eeworm.com/read/159770/10618628
c 链表(递归).c
#include
#include
struct listNode{
int data;
struct listNode *nextPtr;
};
typedef struct listNode LISTNODE;
typedef LISTNODE * LISTNODEPTR;
LISTNODEPTR list(LISTNODEPTR , int); /
www.eeworm.com/read/159770/10618641
c 递归车厢.c
/**********递归题改为非递归题实例 车厢********/
#include
#define MAX 4
int stack[MAX],p=-1;
struct
{
int num;
int sign;
}train[MAX];
void sub()
{
int inc;
if(p==MAX-
www.eeworm.com/read/159463/10647476
cpp nqueens递归.cpp
#include
#include
#include
define QUEENS 4;
//!记录解的序号的全局变量。
int iCount = 0;
//!记录皇后在各列上的放置位置的全局数组。
int Site[QUEENS];
//!递归求解的函数。
void Queen(int n
www.eeworm.com/read/276181/10758055
c 傻瓜递归.c
#include
main()
{ int m=1,n=1,s;
s=akm(m,n);
printf("%d",s);
}
akm(int m,int n)
{ if(m==0)
return n+1;
else if(m!=0&&n==0)
akm(m-1,1);
else if(m!=0&&n!=0)