代码搜索:数字对讲机

找到约 10,000 项符合「数字对讲机」的源代码

代码结果 10,000
www.eeworm.com/read/355750/10245294

cdf dds_vhdl.cdf

/* Quartus II Version 7.1 Build 156 04/30/2007 SJ Full Version */ JedecChain; FileRevision(JESD32A); DefaultMfr(6E); P ActionCode(Cfg) Device PartName(EP1C6Q240) Path("C:/dds数字移相信号发生器/") F
www.eeworm.com/read/354944/10311195

c main.c

/*********************************************** **** AVR SPI接口控制AD9833 *** 功能:M8 SPI 接口控制 AD9833 AD9833为DDS(Direct Digital Frequency Synthesis)直接数字频率合成器 可产生0-12.5MHz的正弦波、三
www.eeworm.com/read/161874/10358843

m kaiser1.m

%利用凯赛窗设计高通数字滤波器 clear all figure;set(gcf,'color','w'); % 设置图形界面为白色 %先确定凯赛窗的阶数 Wn=0.5; Ws=0.4*pi; % 阻带最大衰减 Wp=0.6*pi;
www.eeworm.com/read/354333/10363481

h change.h

//change.h// //数制转换函数集,将数字转换成ASCII字符串,结果保存到outbufful缓冲区 //#ifndef __CHANGE_H__ //#define __CHANGE_H__ #define UCHAR unsigned char #define UINT unsigned int #define ULONG unsigned long #define L
www.eeworm.com/read/351752/10611996

m mydpll.m

%数字锁相环,跟踪输入方波信号的频率和相位 %by fyoung samp=zeros(1,10000); %输入信号 samp=rand(1,10000); %初始为随机信号 DCO_cnt=1; %生成参考频率的计数器 DCO_Prd=100;
www.eeworm.com/read/159191/10681999

htm ex14-14.htm

数字元符号匹配演示(检测字符串中是否包含6246局的电话)
www.eeworm.com/read/421831/10695341

m test4.m

% 生成AD采样量化后的中频数字信号,纯信号,用二进制存储 %clear,clc Svnum = 1; Doppler = 2.25e+3; % Doppler = input('Please input doppler freq(KHz)'); % if(length(Doppler) ==0) Doppler =0; end; % Svnum = input('Please
www.eeworm.com/read/421831/10695442

asv test4.asv

% 生成AD采样量化后的中频数字信号,纯信号,用二进制存储 %clear,clc Svnum = 1; Doppler = 2.25e+3; % Doppler = input('Please input doppler freq(KHz)'); % if(length(Doppler) ==0) Doppler =0; end; % Svnum = input('Please
www.eeworm.com/read/350816/10708654

h change.h

//change.h// //数制转换函数集,将数字转换成ASCII字符串,结果保存到outbufful缓冲区 //#ifndef __CHANGE_H__ //#define __CHANGE_H__ #define UCHAR unsigned char #define UINT unsigned int #define ULONG unsigned long #define L
www.eeworm.com/read/276181/10758370

c re.c

#include main() { int n,s,j,k,p; int a[100];//最多允许100人 printf("请输入人数:"); scanf("%d",&n); printf("请输入数字:"); scanf("%d",&s); for(j=0;j