代码搜索:实时接收
找到约 10,000 项符合「实时接收」的源代码
代码结果 10,000
www.eeworm.com/read/105531/6198034
ini test.ini
signal void ky_1()
{
SIN = 0xf0; //串口接收到数据0xf0,注意它是不需要时间的
twatch(4090); //等待4090个机器周期
SIN = 0xf1;
twatch(4090);
SIN = 0xf0;
twatch(4090);
SIN = 0xf0;
www.eeworm.com/read/420367/6288544
txt 2402test.txt
/********************************************************************************************
Sun-2402C 桌面控制钟应用程序 C
Sun
V0.1 2008-4-2
MCS-51 12MHZ C语言
LCM2402 89S52 DS18B20 DS1302 AT24C02 红外接收IC
www.eeworm.com/read/420367/6288550
pa51备份 2402test.c.pa51备份
/********************************************************************************************
Sun-2402C 桌面控制钟应用程序 C
Sun
V0.1 2008-4-2
MCS-51 12MHZ C语言
LCM2402 89S52 DS18B20 DS1302 AT24C02 红外接收IC
www.eeworm.com/read/493864/6391664
c 9-2.c
#include
#include
void main(void)
{
char xdata * XROM;
char a;
int Aa = 0xFB1C;
long Ba = 0x893B7832;
float Ca = 3.4534;
SCON = 0x50; //串口方式1,允许接收
TMOD = 0x20
www.eeworm.com/read/490882/6445078
asv main.asv
%IR-UWB MRC合并RAKE性能仿真
function
clc;
clear all;
tic;%clock
G_tx=1;%发射机仿真开关
G_channel=1;%信道仿真开关
G_rx=1;%接收机仿真开关
Pow = -30; % average transmitted power (dBm)
fc = 50e9; % sa
www.eeworm.com/read/489869/6462917
c main.c
/*Main.c*/
/*CAN发送与接收程序,波特率设置为125kbps,标准帧,ID=0x024*/
#include "global.c"
void SystemInit();
void Timer1Init();
void KickDog();
void Can_Init();
void Can_Send();
int numled0=200;
unsig
www.eeworm.com/read/484316/6585578
s spi.s
.module SPI.c
.area text(rom, con, rel)
.dbfile E:\心电监护系统\测试程序\第一阶段\无线测试\接收端\SPI.c
.dbfunc e init_spi _init_spi fV
; temp -> R16
.even
_init_spi::
.dbline -1
.dbline 23
; /**
www.eeworm.com/read/481317/6652535
prg datetostring.prg
*——“DateToString”函数
* 将日期型数据转换为字符串
* 接收日期型变量作为参数
FUNCTION DateToString(dDate)
*——默认返回空字符串
sDate = ""
*——如果参数非空而且为日期型
IF .NOT. EMPTY(dDate) .AND. VARTYPE(dDate) = "D"
*——分别获取其年、月、日字段
www.eeworm.com/read/479346/6691893
c calender.c
#include
unsigned char tmp=0;
unsigned char tmp_S;
unsigned char data_Sen[2];
main()
{
unsigned char tmpData;
SCON=0x50;//模式1-8位的UART,允许接收
PCON=PCON&0x7f;//SMOD置0,不加倍BAUD
//
www.eeworm.com/read/478517/6708858
asm 5_9.asm
;193页第五章第9题 键盘接收4位16进制数,并以二进制的形式显示出来。
codesg segment
main proc far
assume cs:codesg
start:
mov bx,0
mov ch,4
newchar:mov ah,01
int 21h
c