5_9.asm
来自「汇编语言课后习题答案」· 汇编 代码 · 共 78 行
ASM
78 行
;193页第五章第9题 键盘接收4位16进制数,并以二进制的形式显示出来。
codesg segment
main proc far
assume cs:codesg
start:
mov bx,0
mov ch,4
newchar:mov ah,01
int 21h
cmp al,30h
jl exit
cmp al,39h
jg next1
sub al,30h
jmp next2
next1: cmp al,41h
jl exit
cmp al,46h
jg exit
sub al,30h
sub al,07h
next2: cbw
mov cl,4
shl bx,cl
add bx,ax
dec ch
jnz newchar
mov dl,0dh
mov ah,02
int 21h
mov dl,0ah
mov ah,02
int 21h
mov cx,16
loop2: shl bx,1
jc next3
mov dl,30h
mov ah,02
int 21h
jmp next4
next3: mov dl,31h
mov ah,02
int 21h
next4: loop loop2
mov dl,0dh
mov ah,02
int 21h
mov dl,0ah
mov ah,02
int 21h
jmp start
exit: mov ax,4c00h
int 21h
main endp
codesg ends
end start
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